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  • 3 answers

Yashraj Solanki 8 years, 3 months ago

Good idea I buy SL Arrora

Abhishek Singh 8 years, 3 months ago

Pradeep's only

Himanshi Vk 8 years, 3 months ago

I prefer SL ARORA for best results in 11th and 12th also because it covers the whole syllabus and alots of questions it has with NCERT solutions, exampler solution and many types of other questions.
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Jyoti Suntha 8 years, 2 months ago

Explain

Diljit Singh 8 years, 3 months ago

Inertia of motion
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Ankit Kumar 8 years, 3 months ago

Weight of body can be zero but mass can never be zero
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Sia ? 4 years, 6 months ago

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Utkarsh Kaletha 8 years, 3 months ago

Gaand
Abo
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Chirag Bhardwaj 8 years, 3 months ago

V = pt.t/f

Rahul Poddar 8 years, 3 months ago

V=root (p.t/m) where p is power and v is velocity t is time
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Vijay Arora 8 years, 3 months ago

v=ds/dt vdt=ds (u+at) dt=ds. ...... (using first eq. of motion) udt+atdt=ds √udt+√atdt=√ds. (√ means integration) u√dt+a√tdt=√ds ut+at square/2=s ut+1/2at square=s Hence, s=ut +1/2at square
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Vijay Arora 8 years, 3 months ago

It is the collision in which Kinetic energy and Momentum both remain conserved
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Dhirendra Maurya 8 years, 3 months ago

We can calculate angle by divided dot product by its magnitud
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Arav Singh 8 years, 3 months ago

Shape of the body
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David Singh 8 years, 3 months ago

As per the defination of work:-

dW = Fdx

{tex}\int {/tex}dW ={tex}\int {/tex}Fdx

W=m{tex}\int {/tex}{tex}\frac{dv}{dt}{/tex} *dx          (as F=ma and  a=dv/dt)

W=m{tex}\int {/tex}v dv              (as dx/dt=v)

W=m({tex}\left.\frac{v^2}{2}\right|_u^v{/tex})

W= {tex}\frac{mv^2}{2} - \frac{mu^2}{2}{/tex}

W=KE{tex}f{/tex} - KE{tex}i{/tex}

W={tex}\Delta {/tex}KE

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Rohit Pal 8 years, 3 months ago

(2) Second equation of motion: s = ut + 1/2 at^2 sol. Let the distance travelled by the body be “s”. We know that Distance = Average velocity X Time Also, Average velocity = (u+v)/2 .: Distance (t) = (u+v)/2 X t …….eq.(1) Again we know that: v = u + at substituting this value of “v” in eq.(2), we get s = (u+u+at)/2 x t =>s = (2u+at)/2 X t =>s = (2ut+at^2)/2 =>s = 2ut/2 + at^2/2 or s = ut +1/2 at^2 This is the 2nd equation of motion.

Shariq Ahmad 8 years, 3 months ago

Its not a=ut Its s=ut+½at²
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Himanshu Gwala 8 years, 3 months ago

The acceleration of the car is greater when the brake pedal is pushed hard, because the car comes suddenly in rest i.e the rate of change of velocity of car is large in this case

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