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Ankit Kumar 8 years, 2 months ago
chain mass intensity per unit length = 4kg/2m
ie.,I= 2kg/m
mass of chain of length hanged from table ie., 60cm = 0.6*2=1.2kg
now weight of 60 cm chain hanged from table = 9.8 * 1.2=11.76 N
now since gravitational force in both sections i.e, 140cm(on table) and 60cm(hanged from table) will be vertical in direction but we will exert force horizontally.
so we will consider only the work done to slide the table edged point of chain( the point on chain positioned at the edge from which the chain is hanged) to side it 60 cm horizontally over table so that the last end of chain also comes on the table
so we will require the force acting horizontall valued equal to the gravitational force to slide it 60cm horizontally.
so work required =11.76*0.6=7.056 Joule
Posted by Abhishek Kumar 8 years, 2 months ago
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Ankit Kumar 8 years, 2 months ago
static friction :- if a body is at rest and we apply the insufficient force to slide it so that the body keeps in rest without tending to any disturbance in its position due to a opposite force acting on it between the two contact surfaces. that opposite force is known as static friction
limiting friction:- it can be defined as the friction offered by contact surface about which body tends to move due to external increasing force. ie., it is the maximum value of static friction.
kinetic friction:; the friction exerted during the motion of the body.
Posted by Sandeep Thakur 8 years, 2 months ago
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Ankit Kumar 8 years, 2 months ago
FORCE = MASS * ACCELERATION
SO
[FORCE] = [MASS] *[ACCELERATION]
[F]= [M] * [LT-2]
[F]= [MLT-2]
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Srishti Rachna 8 years, 2 months ago
you can take a year gap after 12 for your iit preperations
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Rahul Poddar 8 years, 2 months ago
2Thank You