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Ask QuestionPosted by सत्य सनातन? 4 years, 9 months ago
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Posted by Ansh Raghav 4 years, 9 months ago
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Posted by First Name 4 years, 9 months ago
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Śěřãj The Cute? 4 years, 9 months ago
Posted by Punam Ingale ?? 4 years, 9 months ago
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Gaurav Seth 4 years, 9 months ago
For mechanical equilibrium of a rigid body, two conditions need to be satisfied:
1. Translational equilibrium: The net external force or the vector sum of all the external forces acting on the body must be zero.i.e
2.Rotational equilibrium :The net external torque or the vector sum of all the torques acting on the body is zero.
i.e
Posted by Mugunthan Mugunthan 4 years, 9 months ago
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Abirami Kamalbabu 4 years, 9 months ago
Raunak Chauhan 4 years, 9 months ago
Sruti Mohanty 4 years, 9 months ago
Gaurav Seth 4 years, 9 months ago
Black body radiation: Black body is defined as perfect emitter and absorber of light.
For example, whenever we heat an Iron ball like objects, on heating they become first Red, then Orange, then Yellow and at very high temperature they become White.
According to the electromagnetic theory, the energy is emitted or absorbed continuously. So, the radiations emitted may vary in intensity, but should have same colour. The change in color shows, that wavelength also changes .This indicates non continuous flow of energy. So, it couldn’t be explained by electromagnetic theory. This phenomenon shows, that if we keep on heating the light that it emits. It will show changes in wavelength. That means the wavelength keeps on decreasing but after White there is no further change.
Posted by First Name 4 years, 5 months ago
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Apurva Jindal 4 years, 9 months ago
First Name 4 years, 9 months ago
First Name 4 years, 9 months ago
Posted by Aadya Singh 4 years, 9 months ago
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Posted by Ashutosh Gautam 4 years, 9 months ago
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Yogita Ingle 4 years, 9 months ago
In a chemical reaction chemical equilibrium is defined as the state at which there is no further change in concentration of reactants and products.
For example,
At equilibrium the rate of forward reaction is equal to the rate of backward reaction. Equilibrium mixture: The mixture of reactants and products in the equilibrium state is called an equilibrium mixtures.
Based on the extent to which the reactions proceed to reach the state of equilibrium, these may be classified in three groups:
(i) The reactions which proceed almost to completion and the concentrations of the reactants left are negligible.
(ii) The reactions in which most of the reactants remains unchanged, i.e. only small amounts of products are formed.
(iii) The reactions in which the concentrations of both the reactants and products are comparable when the system is in equilibrium.
Posted by Royal Thakur ? 4 years, 9 months ago
- 3 answers
Gaurav Seth 4 years, 9 months ago
Projectile Motion
When any object is thrown from horizontal at an angle θ except 90°, then the path followed by it is called trajectory, the object is called projectile and its motion is called projectile motion.
If any object is thrown with velocity u, making an angle θ, from horizontal, then
- Horizontal component of initial velocity = u cos θ.
- Vertical component of initial velocity = u sin θ.
- Horizontal component of velocity (u cos θ) remains same during the whole journey as no acceleration is acting horizontally.
- Vertical component of velocity (u sin θ) decreases gradually and becomes zero at highest point of the path.
- At highest point, the velocity of the body is u cos θ in horizontal direction and the angle between the velocity and acceleration is 90°.
Important Points & Formulae of Projectile Motion
- At highest point, the linear momentum is mu cos θ and the kinetic energy is (1/2)m(u cos θ)2.
- The horizontal displacement of the projectile after t seconds
x = (u cos θ)t - The vertical displacement of the projectile after t seconds
y = (u sin θ) t — (1/2)gt2 - Equation of the path of projectile
- The path of a projectile is parabolic.
- Kinetic energy at lowest point = (1/2) mu2
- Linear momentum at lowest point = mu
- Acceleration of projectile is constant throughout the motion and it acts vertically downwards being equal to g.
- Angular momentum of projectile = mu cos θ x h, where h denotes the height.
- In case of angular projection, the angle between velocity and acceleration varies from 0° < θ < 180°.
- The maximum height occurs when the projectile covers a horizontal distance equal to half of the horizontal range, i.e., R/2.
- When the maximum range of projectile is R, then its maximum height is R/4.
Posted by Utkarsh Mishra 4 years, 9 months ago
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Posted by Sanjana Purohit 4 years, 9 months ago
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Posted by Jaspreet Sidhu 4 years, 9 months ago
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Posted by Parth Suthar 4 years, 9 months ago
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Gaurav Seth 4 years, 9 months ago
a ns w e r
Energy is involved in a chemical change because of formation and breakdown of bonds. In exothermic reactions energy is released and in endothermic reactions energy is taken in.
Posted by Parth Suthar 4 years, 9 months ago
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Gaurav Seth 4 years, 9 months ago
Weak Nuclear Force: This force appears only in certain nuclear processes such as the β-decay of a nucleus. In β-decay, the nucleus emits an electron and an uncharged particle called neutrino.This particle was first predicted by Wolfgang Pauli in 1931.
Posted by Chundawat 4001 Singh 4 years, 9 months ago
- 3 answers
Yogita Ingle 4 years, 9 months ago
Density = Mass/Volume = 5.74/1.2 = 4.783 g/cm3
Here least significant figure is 2,
so density = 4.8 g/cm3
Posted by Aadya Singh 4 years, 9 months ago
- 5 answers
Gagandeep Kaur 4 years, 9 months ago
Posted by Divya Pareya 4 years, 9 months ago
- 2 answers
First Name 4 years, 9 months ago
Y = Young's modulus of wires
R1= r
R2=2r
As equal elomgation is produced,
∆l = elongation
F = YA∆l/l
f = YA'∆l/l
F/f = A/A'
F/f = $$\pi$$r²/$$\pi$$r² ×4
F:f = 4 : 1
Posted by Divya Pareya 4 years, 9 months ago
- 1 answers
Yogita Ingle 4 years, 9 months ago
it is based on Young's modulus concepts .
we know, Young's modulus = stress/strain
stress = F/A , strain = ∆L/L
so, Young's modulus, Y = FL/A∆L
so, F = YA∆L/L
hence, it is clear that tension in rope is directly proportional to area of cross section of rope.
area of cross section of rope , A = πd²/4
so,
we can write ,
so,
hence, maximum tension that may be given to a similar role of diameter 2cm is 2000N
Posted by Shiv Thakur 4 years, 9 months ago
- 2 answers
Gaurav Seth 4 years, 9 months ago
(4)
not accelerating .
Reason:
Forces that are equal in size but opposite in direction are called balanced forces. Balanced forces do not cause a change in motion. When balanced forces act on an object at rest, the object will not move. If you push against a wall, the wall pushes back with an equal but opposite force
Posted by Clera Noronha 4 years, 9 months ago
- 2 answers
Abirami Kamalbabu 4 years, 9 months ago
Yogita Ingle 4 years, 9 months ago
Acceleration of a body moving with a uniform velocity = 0
because acceleration = change in velocity/time
change in velocity= 0
SO, acceleration = 0
Posted by Nisha Gothi 4 years, 9 months ago
- 4 answers
Gaurav Seth 4 years, 9 months ago
Earth attracts all things towards it through an unseen force of attraction. This force of attraction is called as gravitation or gravitational pull. You must have noticed that every time you throw an object upwards, it reaches a certain height and then falls down on the earth's surface
Posted by Kajal Nazirkar 4 years, 9 months ago
- 1 answers
Gaurav Seth 4 years, 9 months ago
Using S = ut + (1/2)at²
S = 500 m
u = 0 Start from rest
a = ?
t = 30 sec
=> 500 = 0 + (1/2)a(30)²
=> a = 1000/900
=> a = 10/9 m/s²
V = u + at
=> V = 0 + (10/9) * 30
=> V = 100/3 m/s
velocity of the aeroplane at the take off = 100/3 m/s
Posted by Kajal Nazirkar 4 years, 9 months ago
- 1 answers
Yogita Ingle 4 years, 9 months ago
We know that, distance = speed×time
So, d = 50×40 = 2000m
d = 2×3.14×r (circumference of the circle)
=> 2000=2×3.14×r
On calculating, r = 318.47 m
In this case, required acceleration will be centripetal acceleration.
So, a = (v×v)/r
a = (50×50)/318.47
a = 7.85m/s^2
Posted by ?Ritesh Gupta? 4 years, 9 months ago
- 2 answers
Yogita Ingle 4 years, 9 months ago
When a particle is thrown obliquely near the earth’s surface, it moves along a curved path under constant acceleration that is directed towards the center of the earth (we assume that the particle remains close to the surface of the earth). The path of such a particle is called a projectile and the motion is called projectile motion. Air resistance to the motion of the body is to be assumed absent in projectile motion.
In a Projectile Motion, there are two simultaneous independent rectilinear motions:
- Along the x-axis: uniform velocity, responsible for the horizontal (forward) motion of the particle.
- Along y-axis: uniform acceleration, responsible for the vertical (downwards) motion of the particle.
Nazaf Parveen 4 years, 9 months ago
Posted by Zagwar Insan 4 years, 9 months ago
- 2 answers
Gaurav Seth 4 years, 9 months ago
The expression for rigid body’s “rotational kinetic energy” is
SOLUTION:
A body undergoing a rotational dynamics with angular velocity ω will also poses a translational motion. Let the velocity for translation motion be ‘’v’’.
We know for translational motion the energy poses by body is kinetic and given as
Also we know that for a body obeying rotation
v=rω
Substituting in translation
Also there is a relation for moment of inertia i.e
Substituting we get,
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Raunak Chauhan 4 years, 9 months ago
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