CBSE > Class 11 > Physics | CBSE Board | Homework Help

X0 -x= area of trapezium =1/2 sum of parallel sides× perpendicular distance between them =1/2(OA+BD)×OD =1/2(v+u)×t =1/2(u+at+u)×t =1/2(u^2+1/2at^2) S=1/2(u^2+1/2at^2)

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Posted by Avinash Kumar 7 years, 2 months ago

CBSE > Class 11 > Physics

2 answers

∂Αяѕнαиαα ყα∂Αѵ ??? 7 years, 2 months ago

v for velocity in physics

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Ayushi Prasad 7 years, 2 months ago

???

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Rain men basic concept

Posted by Shubham Kumar 7 years, 2 months ago

CBSE > Class 11 > Physics

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The resultant of two forces 3p and 2p is R. If the first force is doubled, then the resultant is doubled. Find the angle betweeen the two forces

Posted by Vandana Baunthiyal 7 years, 2 months ago

CBSE > Class 11 > Physics

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What is need for banking of road

Posted by Sonu Sonu 7 years, 2 months ago

CBSE > Class 11 > Physics

1 answers

Rahul Sharma 7 years, 2 months ago

To provide safe turn and to ensure there is no skidding while a whicle takes a turn.

Banking of road provides an extra centripetal force that ensures a safe turn even at higher speed.

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Newtons second law

Posted by Chandra Aditya 7 years, 2 months ago

CBSE > Class 11 > Physics

3 answers

Mohit Kumar 7 years, 2 months ago

Force is directly proposnal to rate of change of momentum

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Gaurav Singh 7 years, 2 months ago

F=ma as force applied by a net force will directly proportional toAcceleration provided to that body and motion of that body.

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Prashant Kumar 7 years, 2 months ago

The rate of change of momentum is directly proportional to the force applied and in the direction force act

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The displacement (in meter) of a particle moving along x-axis is given by x=18t +t² Calculate : (i)the instantaneous velocity at t=4sec (ii)instantaneos acceleration (iii)isplacement after 5sec

Posted by Banty Shah 7 years, 2 months ago

CBSE > Class 11 > Physics

1 answers

Pratikshit Shubham 7 years, 2 months ago

(i)v (4s)= 20m/s (ii)a=2m/s^2 (iii)x (5m)= 115m

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The motion of a particle of mass m is described by y=ut+1/2t

Posted by Jaskaran Jassi 7 years, 2 months ago

CBSE > Class 11 > Physics

0 answers

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What are concurrent forces

Posted by Ritik Prajapat 7 years, 2 months ago

CBSE > Class 11 > Physics

3 answers

Ritik Prajapat 7 years, 2 months ago

Thax both of u

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Akshay Pathak 7 years, 2 months ago

The forces which act at a same point is known concurrent forces

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Yogita Ingle 7 years, 2 months ago

If two or more forces act on a point, i.e. line of action through one common point, they are called concurrent forces. Concurrent means meeting at a point.
If all the forces are passing through a single point then those forces are called as concurrent forces.

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All Derivation of projectile motion?simple,time of flight,max height,horizontal range. And tell which can be come in exam

Posted by Deeksha Gupta 7 years, 2 months ago

CBSE > Class 11 > Physics

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Two balls are thrown simultaneously .A vertically upwards with a speed of 20 m/s from ground and ,B vertically downwards from a height of 40 m with the same speed and along the same line At what point do the two balls collide above the ground

Posted by Abhishek Semwal 7 years, 2 months ago

CBSE > Class 11 > Physics

1 answers

Sheeja Menon 7 years, 2 months ago

1st case Vertically upwards Speed =20m/s Time=t Here acceleration is = -g Let us take the distance as 'x' m We know that s=ut + 1/2 at² By substituting the values, x=20×t+ 1/2× -g × t².............1 2nd case Vertically downwards Speed= 20m/s Time= t Acceleration = +g Distance =40-x From s=ut +1/2at² , 40-x=20×t +1/2gt².............2 Adding 1and 2 we get, 40=40t t=40/40=1 Substituting t=1 in equation 1 X=20+1/2×-9.8×1² =20-4.9 =15.1 m

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Can position time graph have negetive slope?

Posted by Tripti Bajpai 7 years, 2 months ago

CBSE > Class 11 > Physics

4 answers

Anshul Jaat 7 years, 2 months ago

Yes position time graph can be negative when there is negative velocity and for negative graph it is not imp. to go below the x axis

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Sarthak Sharma 7 years, 2 months ago

No it cant

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Nancy Rajput 7 years, 2 months ago

negativw

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Nancy Rajput 7 years, 2 months ago

in free fall its negativw

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What is banking of road proper detention

Posted by Yash Kumar 7 years, 2 months ago

CBSE > Class 11 > Physics

1 answers

Varun Chhokra 7 years, 2 months ago

The banking of road is just to tell us the maximum friction we should attain so that we should not slip. mv^2/r<=mgsin0 condition for no slip

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If t=ax²+b.Prove that a is directly proportional to -v³

Posted by Mohit Sharma 7 years, 2 months ago

CBSE > Class 11 > Physics

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Hlo friends... Physics mai Chapters:- 1, 2, 3, 4, 5 and 6 kitne-kitne marks k aayenge....

Posted by Mr. Thakur 7 years, 2 months ago

CBSE > Class 11 > Physics

0 answers

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Differentiate between banking of roads and bending of a cyclist

Posted by Aayushi Agrawal 7 years, 2 months ago

CBSE > Class 11 > Physics

1 answers

Aman Kumar 7 years, 2 months ago

I think it's one difference is that :- In case of banking of road, the road inclined at some angle... But in case of bending of cyclist, the cyclist bend at some angle...... If I m wrong then correct me surely

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A boy walked 10m turned to his left and walked 6m then turned to his right and walked 4m .find the displacement covered by the boy

Posted by Tejaswini Sridharan 7 years, 2 months ago

CBSE > Class 11 > Physics

0 answers

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What is business software

Posted by Hemant Joshi 7 years, 2 months ago

CBSE > Class 11 > Physics

1 answers

Kaira Choudhary 7 years, 2 months ago

Hlo friends

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Define least çount and least count error

Posted by Anjali Chouhan 7 years, 2 months ago

CBSE > Class 11 > Physics

1 answers

∂Αяѕнαиαα ყα∂Αѵ ??? 7 years, 2 months ago

least count is the smallest value of the physical quantity which can be measured accurately by the instrument...... least count error can be defined as the error associated with the resolution of the instrument.

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Derivation of kinetic energy

Posted by Adarsh Pathak 7 years, 2 months ago

CBSE > Class 11 > Physics