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Ask QuestionPosted by Bhargav Navin 3 years, 4 months ago
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Bhargav Navin 3 years, 4 months ago
Bhargav Navin 3 years, 4 months ago
Posted by Ujala Pandey 3 years, 4 months ago
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Mamta ... 3 years, 4 months ago
Sia ? 3 years, 4 months ago
Posted by Kommu Sandhya 3 years, 4 months ago
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Sia ? 3 years, 4 months ago
sin (-1485°)
= - sin (1485)
(sin (-x) = -sin x)
= - sin (4.360°+45°)
= - sin (45°)
{sin (2nπ+a) = sin a}
= -12√12
Posted by Harini Kamali 3 years, 4 months ago
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Posted by Parmar Nayan 3 years, 4 months ago
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Sia ? 3 years, 4 months ago
the velocity time relation of an electron starting from rest is given by v=kt, where k=2m/s-2.
Posted by Jiya Joshal 3 years, 4 months ago
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Sia ? 3 years, 4 months ago
Adithya Dev A 3 years, 4 months ago
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Adithya Dev A 3 years, 4 months ago
Adithya Dev A 3 years, 4 months ago
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Adithya Dev A 3 years, 4 months ago
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Posted by Soniya Rana 3 years, 5 months ago
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Posted by Lucky Lucky 3 years, 5 months ago
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Posted by Prerna Sahu 3 years, 5 months ago
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Posted by Praduman Kumar Pandey 3 years, 5 months ago
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Preeti Dabral 3 years, 5 months ago
Limitations of dimensionless analysis:
- This method does not tell us how to determine the proportionality constant value.
- The method cannot be considered to derive composite relations. Examples s = ut + 1/2 at2 and 2as = v2 – u2.
-
A formula containing trigonometric function, exponential function, and logarithmic function can not derive from it.
- The method cannot be used to derive the relationship between more than three quantities.
Posted by Sushil Shukla 3 years, 5 months ago
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Preeti Dabral 3 years, 5 months ago
The dimensional formula of Work is given by,
M1 L-2 T-2
Where,
- M = Mass
- L = Length
- T = Time
Work (W) = Force × Displacement . . . . . (1)
Since, Force = Mass × acceleration = M × [L T-2]
∴ The dimensional formula of Force = M1 L1 T-2 . . . . (2)
On substituting equation (2) in equation (1) we get,
Work = Force × Displacement
Or, W = [M1 L1 T-2] × [M0 L1 T0] = [M1 L2 T-2].
Therefore, work is dimensionally represented as [M1 L2 T-2].
The dimensional formula of force is given by,
M1 L1 T-2
Where,
- M = Mass
- L = Length
- T = Time
Force = Mass × Acceleration . . . . (1)
Since, acceleration = velocity × [time]–1 = [LT-1] × [T]-1
Therefore, the dimensional formula of acceleration = [LT-2] . . . . (2)
On substituting equation (2) in equation (1) we get,
Force = m × a
Or, F = [M] × [L1 T-2] = M1 L1 T-2.
Therefore, Force is dimensionally represented as M1 L1 T-2.
Posted by Deepak Karthikeyan 3 years, 5 months ago
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Posted by Manisha Nayak 3 years, 5 months ago
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Posted by Gurjot Kaur 3 years, 5 months ago
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Preeti Dabral 3 years, 5 months ago
We know that, 1 minute = 60 seconds
60 minutes (1 hour) = 60 × 60 = 3600 seconds
24 hours (1 day) = 3600 × 24 = 86400 seconds
365 days (1 Year) = 86400 × 365 = 31536000seconds
{tex}31536000 = 31536 \times {10^3} = \frac{{31536}}{{10000}} \times {10^3} \times {10^4} = 3.1536 \times {10^{3 + 4}} = 3.1536 \times {10^7}{/tex}seconds.
Posted by Chellamuthu Muthusamy 3 years, 5 months ago
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Sia ? 3 years, 5 months ago
à” is a preposition of location (with feminine article “la”: at home: à la maison), of possession (in the west of the country (Paul’s dog : le chien à paul (standard French : le chien de Paul)), has some other usages as well related to the prepposition “de”, and sounds exactly like the standard french “a” (the accent on “à” somehow transcripts (in writing only, the spelling is the very same) an archaic expression of an extended locative case) and like “a” in “patagonia” for exemple.
“au” has the same use, but will be used with masculine non-personnal names (as the contraction of “a+le”, ex : I’m going to the woods : Je vais au bois (singular) ; aux bois (plural) ; possessive (western French) : the priest’s car : la voiture au prêtre) but will sound like the french “o” in “poteau”, and the english “o” in “obliterate”.
Adithya Dev A 3 years, 5 months ago
Posted by Kirtika Kaushik 3 years, 5 months ago
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Heer Sanghvi 3 years, 5 months ago
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Preeti Dabral 3 years, 4 months ago
Just suppose both Policeman and thief are running in the same direction.
Given :-
Acceleration of Thief = 1 m/s²
Velocity of Police = 20 m/s
Using the first equation of motion :-
v = u + at
20 = 1 × t
t = 20 s
Note :-
1. The velocity of Policeman must be more than that of thief otherwise the thief will never be caught.
2. When both will have equal velocity then also thief can never be caught.
3. Relative Velocity of theif w.r.t police will be lesser than that of relative velocity of police w.r.t thief.
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