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Yogita Ingle 7 years, 1 month ago

A good spring will be that in which a large restoring force is developed on being deformed. This in turn depends on the elasticity of the material of the spring. Since Young’s modulus for steel is more than that of copper, therefore the springs made of steel and not of copper.

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Avantika Tayal 7 years, 1 month ago

W=mg in the centre g is 0 so,W=m×0=0
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Gaurav Seth 7 years, 1 month ago

For a satellite orbiting the earth, the necessary centripetal force is applied by gravitational pull.

That is, 



  

Retarding torque is applied by the air friction. Hence, there is a decrease in the angular momentum. Therefore, the speed increases.

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Himani Pandey 7 years, 1 month ago

Mine is tomorrow....only few hours are left?

Garhwalli???? Nona 7 years, 1 month ago

Mine is on 12 march

Priya Dharshini ? 7 years, 1 month ago

Mine is on 21st

Ashish Sharma 7 years, 1 month ago

my exam on 22 feb
  • 1 answers

Pragati Gola 7 years, 1 month ago

Doppler effect ,projectile, refrigerator,heat engine
  • 1 answers

Yogita Ingle 7 years, 1 month ago

  • Doppler Effect is the phenomenon of motion-related frequency change.
  • Consider if a truck is coming from very far off location as it approaches near our house, the sound increases and when it passes our house the sound will be maximum. And when it goes away from our house sound decreases.
  • This effect is known as Doppler Effect.
  • A person who is observing is known as Observer and object from where the sound wave is getting generated it is known as Source.
  • When the observer and source come nearer to each other as a result waves get compressed. Therefore wavelength decreases and frequency increases.
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Î$Hîkâ Gûptâ???? 7 years, 1 month ago

kriti sharma from which stream you are maths or bio

Kriti Sharma 7 years, 1 month ago

0degree
-40
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Kriti Sharma 7 years, 1 month ago

Dued it is the best way of giving marks by teachers .you need to write the question stepwise step what follows after what ok even if you forget the last step you will be awarded marks of all the steps you did .it increases the possiblitiy of getting good marks .
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Sanidhya Jadaun? 7 years, 1 month ago

Tomorrow is my last exam................computer science.....???

Kriti Sharma 7 years, 1 month ago

I know bahut time lagta hai yaar i am greatly thankfull to you.

Kriti Sharma 7 years, 1 month ago

Thanks sanidhya so much. What is your next exam now

Sanidhya Jadaun? 7 years, 1 month ago

4)Describe Carnot's reversible heat engine and obtain an expression for its efficiency............5) state and prove bournolli's theorem and mentio its application .............6) if the earth stops rotating about it's axis ,what will be the effect on the value of g? will this effect be same at all places?...........

Sanidhya Jadaun? 7 years, 1 month ago

Hey Kriti these are some theoretical questions and numericals which came in my exam............1) the velocity of an aeroplane is doubled (i) what will happen to the momentum? Will the momentum remain conserved?(ii)what will happen to the kinetic energy?will the energy remain conserved?................2) Establish the displacement equation of a plane progressive wave...............3) Two sprongs of force constant k1 and k2 are joined ene to end and suspended from a support.A body of mass m is attached to the lower end .Find out the period of oscillation of the body......................... yaar bahut der lagti he type karne main isliye or nhi daal paunga questions wi isse bhi bade he .......hope this may help u.............?
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Rishav Sharma 7 years, 1 month ago

In the collisin read tge diff bw elastic inelastic collison
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Pragati Gola 7 years, 1 month ago

The workdone by force is equal to change in its kinetic energy. w=1/2mv^2-1/2mu^2
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Sanidhya Jadaun? 7 years, 1 month ago

Just note down the important formulaes of derivations which will remind u the whole concept and revise the notes as much as possible.........????

Priya Dharshini ? 7 years, 1 month ago

I am preparing 97 derivation,solved and unsolved question of ncert, few worksheets from my school.

Gaurav Pradhan 5 years, 11 months ago

I m making summary and formula sheets and solving most of the ncert exercise questions.
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Paridhi Tiwari 7 years, 1 month ago

Ooh i think my answer is incorrect ??

Paridhi Tiwari 7 years, 1 month ago

A projectile body which falls under gravity can be consider as projectile
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Paridhi Tiwari 7 years, 1 month ago

This theorem states that for a stream line flow of an ideal liquid, the total energy ( the sum of press. energy, P.E and K.E) per unit mass remains constant at every cross - section through out the liquid flow.
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Paridhi Tiwari 7 years, 1 month ago

The velocity with which the liquid flows out from a narrow hole , is equal to that which a freely falling body would acquire in the falling through a vertical distance equal to the depth of orifice below the free surface of liquid
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Rajdeep Tripathi 7 years, 1 month ago

Koi mahan vyakti lag rhe ho ap

Bharat Madan 7 years, 1 month ago

Branch of science which deals with study of flow of heat

Nikita Kumar 5 years, 11 months ago

Pahle thermodynamic ka spelling sikh lo Then ask
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Sanidhya Jadaun? 7 years, 1 month ago

Let us consider two different regions in the above diagram. Let us name the first region as BC and the second region as DE. Now consider the fluid was previously present in between B and D. However, this fluid will move in a minute (infinitesimal) interval of time (∆t). If the speed of fluid at point B is v1 and at point D is v2. Therefore, if the fluid initially at B moves to C then the distance is v1∆t. However, v1∆t is very small and we can consider it constant across the cross-section in the region BC. Similarly, during the same interval of time ∆t the fluid which was previously present in the point D is now at E. Thus, the distance covered is v2∆t. Pressures, P1 and P2, will act in the two regions, A1 and A2, thereby binding the two parts. The entire diagram will look something like the figure given below. Bernoulli's equation Finding the Work Done First, we will calculate the work done (W1) on the fluid in the region BC. Work done is W1 = P1A1 (v1∆t) = P1∆V Moreover, if we consider the equation of continuity, the same volume of fluid will pass through BC and DE. Therefore, work done by the fluid on the right-hand side of the pipe or DE region is W2 = P2A2 (v2∆t) = P2∆V Thus, we can consider the work done on the fluid as – P2∆V. Therefore, the total work done on the fluid is W1 – W2 = (P1 − P2) ∆V The total work done helps to convert the gravitational potential energy and kinetic energy of the fluid. Now, consider the fluid density as ρ and the mass passing through the pipe as ∆m in the ∆t interval of time. Hence, ∆m = ρA1 v1∆t = ρ∆V Change in Gravitational Potential and Kinetic EnergyNow, we have to calculate the change in gravitational potential energy ∆U.Bernoulli's equation.Similarly, the change in ∆K or kinetic energy can be written asBernoulli's equation.Calculation of Bernoulli’s EquationApplying work-energy theorem in the volume of the fluid andDividing each term by ∆V andRearranging the equation will yieldBernoulli's equation.The above equation is the Bernoulli’s equation. However, the 1 and 2 of both the sides of the equation denotes two different points along the pipe. Thus, the general equation can be written asBernoulli's equation.Thus, we can state that Bernoulli’s equation state that the Pressure (P), potential energy (ρgh) per unit volume and the kinetic energy (ρv2/2) per unit volume will remain constant.
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