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Gaurav Seth 6 years, 4 months ago
Given:
Solution:
In the series combination, the resistance are added.
Here, the error is added because is in addition.
In parallel combination, the reciprocal of the resistances are added.
After we differentiate the parallel combination formula we get,
We need to keep the error on one side and bring the rest on another side.
On rounding, we get,
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Gaurav Seth 6 years, 4 months ago
Total time duration in consideration : 2 min 40 secs = 160 secs
No of complete rounds in this time = 160/40 = 4 rounds
Therefore he will be exactly at the point where he started. Hence his displacement will be 0, although he will cover a distance of 4 (2πR)
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Sia ? 6 years, 4 months ago
{tex}\begin{array} { l } { F _ { \mathrm { f-static } } \leq \mu _ { s } N } \\ { F _ { \mathrm { f-kinetic } } = \mu _ { k } N } \end{array}{/tex}
Notice that both of these friction formulas ONLY depend on the coefficient of friction and the normal force. It does not depend the area of contact, it doesn't depend on the sliding speed.
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