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Sia ? 6 years, 4 months ago
- When the direction of applied force is in the direction of displacement then work done is said to be positive. e.g. When a body falls under the action of gravity, {tex}\theta = 0 ^ { \circ }{/tex}
- When the direction of applied force is opposite to the direction of displacement then work done is said to be negative. e.g. When brakes are applied on a moving vehicle work done by a braking force is negative.
- When the direction of applied force is perpendicular to the direction of displacement then work done is zero. e.g. A coolie carrying a load on his head moves on a horizontal platform, {tex}\theta = 90 ^ { \circ }{/tex} work done is zero.
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Gaurav Seth 6 years, 4 months ago
Unification: It is a trial to correlate and unite various universal laws and basic phenomena of nature to explain an activity. For example—Maxwell unified electric, magnetic and optical phenomenon on when he explained that light is an electromagnetic wave.
Reduction: It is the effort to solve a complex problem by breaking it into simpler parts. It is considered to be heart of physics. For example temperature of a system is reduced to average kinetic.
Posted by Md Fahad 6 years, 4 months ago
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Yogita Ingle 6 years, 4 months ago
The resultant force on a body simultaneously depends upon the direction in which both the force has been acting on the body.
If they act on opposite side of the particle, then the resultant net force will counter each other, hence,
F net = 7 – 2 = 5 N
If the act on the particle on the same side, then the resultant net force will be cumulative, hence
F net = 7 + 2 = 9 N
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Sia ? 6 years, 4 months ago
For unit vector, we have
{tex}| \hat { \mathbf { i } } + m \hat { \mathbf { j } } + \hat { \mathbf { k } } | = \sqrt { 1 + m ^ { 2 } + 1 } = 1{/tex}
m2 + 2 = 1
{tex}m ^ { 2 } = - 1 \Rightarrow m = \sqrt { - 1 }{/tex}
Hence, m is imaginary number.
Posted by Ayush Vishwakarma?? 6 years, 4 months ago
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#Aditi~ Angel???? 6 years, 4 months ago
Yogita Ingle 6 years, 4 months ago
When a particle is thrown obliquely near the earth’s surface, it moves along a curved path under constant acceleration that is directed towards the center of the earth (we assume that the particle remains close to the surface of the earth). The path of such particle is called a projectile and the motion is called as projectile motion. Air resistance to the motion of the body is to be assumed absent in projectile motion.
An object that becomes airborne after it is thrown or projected is called projectile. Example, football, javelin throw, etc.
#Aditi~ Angel???? 6 years, 4 months ago
Posted by Mohan Manohar 6 years, 4 months ago
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Posted by #Aditi~ Angel???? 6 years, 4 months ago
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Ayush Vishwakarma?? 6 years, 4 months ago
Ayush Vishwakarma?? 6 years, 4 months ago
Ayush Vishwakarma?? 6 years, 4 months ago
Gaurav Seth 6 years, 4 months ago
(a)
H = u²/(2g)
H = 20²/(2×10)
H = 20 m
The ball will reach 20 m high from the point of projection.
It reaches 20 + 20.5 = 40.5m high from the ground.
(b)
t1 = 2u/g
t1 = 2×20/10
t1 = 4 seconds
If v is the velocity with which it hits the ground then,
v = √(u² + 2aS)
v = √(20² + 2×10×25)
v = 30 m/s
v = u + at
t2 = (v - u)/g
t2 = (30 - 20)/10
t2 = 1 second
Time taken for it to hit the ground = t1 + t2
= 4 + 1
= 5 seconds
Note: I took g = 10m/s².
Posted by Aarav Katoch 6 years, 4 months ago
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Unnati Pragya 6 years, 4 months ago
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