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Ask QuestionPosted by Deepak Bishnoi 6 years, 3 months ago
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Posted by T T 6 years, 3 months ago
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Sia ? 6 years, 3 months ago
Dimensional Analysis is a very basic aspect of measurement and has many applications in real life physics. We use dimensional analysis for three prominent reasons, they are: Consistency of a dimensional equation.
Tannu Sharma 6 years, 3 months ago
Pintu Kumar Yadav 6 years, 3 months ago
Yogita Ingle 6 years, 3 months ago
Dimensional Analysis is a very basic aspect of measurement and has many applications in real life physics. We use dimensional analysis for three prominent reasons, they are:
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Consistency of a dimensional equation
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Derive relation between physical quantities in physical phenomena
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To change units from one system to another
Posted by Arshad Ansari 6 years, 3 months ago
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Purvi Diwakar 6 years, 3 months ago
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Harender Singh 6 years, 3 months ago
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Tripti Rawat 6 years, 3 months ago
We define one newton as that force which when acting on a mass of 1 kg produces in it an acceleration of {tex}1m/s^2{/tex} in its own direction.
{tex}1 N=1 kgm/s^2{/tex}
Ram Singh 6 years, 3 months ago
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Yogita Ingle 6 years, 3 months ago
One Newton is 1 kilogram meter per second square. It is the SI unit of force. It is the force needed to accelerate a mass of 1 kilogram by 1 m/s2 in the direction of the applied force.
Posted by Alok Singh 6 years, 3 months ago
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Sia ? 6 years, 3 months ago
<i>Newton's three laws of motion</i> may be stated as follows:
- Every object in a state of uniform motion will remain in that state of motion unless an external force acts on it.
- Force equals mass times acceleration [ f (t) = m a (t) ].
- For every action there is an equal and opposite reaction.
Ram Singh 6 years, 3 months ago
Posted by Purnima Sarkar 6 years, 3 months ago
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Posted by Whatsapp Status 6 years, 3 months ago
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Posted by Naina Singh 6 years, 3 months ago
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Sia ? 6 years, 3 months ago
Let the vectors are A and B.
Given, |A| = 4 units, |B| = 4 units and {tex}\theta{/tex}= 60°
The magnitude of resultant of difference of A and B from parallelogram law of vector addition for vectors A and (-B) is given by,
{tex}R = | \mathbf { R } | = \sqrt { A ^ { 2 } + B ^ { 2 } - 2 A B \cos \theta }{/tex}
{tex}= \sqrt { 4 ^ { 2 } + 4 ^ { 2 } - 2 \times 4 \times 4 \cos 60 ^ { \circ } }{/tex}
R = 4 units
Posted by Krishna Kumar 6 years, 3 months ago
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Mayank Sharma 6 years, 3 months ago
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Posted by Kulwinder Singh 6 years, 3 months ago
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Yogita Ingle 6 years, 3 months ago
- Scalar Quantities: The physical quantities which are specified with the magnitude or size alone are scalar quantities. For example, length, speed, work, mass, density, etc.
- Vector Quantities: Vector quantities refer to the physical quantities characterized by the presence of both magnitude as well as direction. For example, displacement, force, torque, momentum, acceleration, velocity, etc.
Robinpreet Kaur 6 years, 3 months ago
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Shubhanjali Singh Gaur 6 years, 3 months ago
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Posted by Nadiya Shaikh 6 years, 3 months ago
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Sia ? 6 years, 3 months ago
We know
- {tex}a = \frac { d v } { d t }{/tex}
a dt = dv
Integrating
{tex}\int\limits_0^tadt =\int\limits_u^v dv{/tex}
at = v - u
v = u+at - We know
{tex}a = \frac { d v } { d t }{/tex}
Multiply and Divide by dx
{tex}a = \frac { d v } { d t } \times \frac { d x } { d x }{/tex}
{tex}a = \frac { d v } { d x } \times v{/tex}
{tex}adx = vdv{/tex} {tex}\left( \because \frac { d x } { d t } = v \right){/tex} - Integrating within the limits
{tex}a \int \limits _{0}^{s}dx= \int \limits _{u}^{v}vdv{/tex}
{tex}as = \frac { \upsilon ^ { 2 } } { 2 } - \frac { \nu ^ { 2 } } { 2 }{/tex}
{tex}a s = \frac { \upsilon ^ { 2 } - \nu ^ { 2 } } { 2 }{/tex}
{tex}\upsilon ^ { 2 } - \nu ^ { 2 } = 2 a s{/tex}
Posted by Johnish Shaji 6 years, 3 months ago
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Sia ? 6 years, 3 months ago
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Aysha Razi 6 years, 3 months ago
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