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Find the point in xy-plane which is equidistant from the three points (2,0,3),(0,3,2) and (0,0,1).

Posted by Suman Sharma 5 years, 8 months ago

CBSE > Class 11 > Mathematics

4 answers

Suman Sharma 5 years, 8 months ago

Mera y ka answer wrong aa rha h

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Suman Sharma 5 years, 8 months ago

Book me answer h (3,2,0)

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Suman Sharma 5 years, 8 months ago

Wrong answer

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Yogita Ingle 5 years, 8 months ago

Since x-coordinate of every point in yz-plane is zero. Let P (0, y, z) be a point on the yz-plane such that PA = PB = PC.
Now PA = PB
(0 – 2)² + (y – 0)² + (z – 3⁾² = (0 – 0)² + (y – 3)² + (z – 2)²

i.e. z – 3y = 0

and PB = PC

⇒ y² + 9 – 6y + z² + 4 – 4z = y² + z² + 1 – 2z ,

i.e. 3y + z = 6 Simplifying the two equating, we get y = 1, z = 3
Here, the coordinate of the point P are (0, 1, 3).

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Find the locus of point P which moves in such a way that 2PA=3PB, where A(-2,1,3) and B(3,-1,2) are the given points.

Posted by Suman Sharma 5 years, 8 months ago

CBSE > Class 11 > Mathematics

2 answers

Suman Sharma 5 years, 8 months ago

Ye +1 ka question h

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Yogita Ingle 5 years, 8 months ago

let the point p be (h, k)
Now 2PA,=3PB
PA=√[h^2+k^2]
pb=√[h-4]^2+[k+3]^2
given 2PA=3PB
SQ. both sides
4PAsq. =9PBsq
4(h^2+k^2)=9[(h-4)^2+(k+3)^2]

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A(5,4,6), B(1,-1,3) and C(4,3,2) are the three vertices of a triangle. The internal bisector of angle BAC meets BC in D.FindAD.

Posted by Suman Sharma 5 years, 8 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

The mid -point of the sides of a triangle are (1,5,-1) ,(0,4,-2) and (2,3,4). Find its vertices.

Posted by Suman Sharma 5 years, 8 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

The x co- ordinates of a point is 9 . Find its other co- ordinates if this point lies on the line joining the points (7,2,1) and (10,5,7).

Posted by Suman Sharma 5 years, 8 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

Differentiate under root X

Posted by Amita Verma 5 years, 8 months ago

CBSE > Class 11 > Mathematics

1 answers

Shreya _S❤ 5 years, 8 months ago

1/2√x

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Value of sin 90

Posted by Shivani Kushwaha 5 years, 8 months ago

CBSE > Class 11 > Mathematics

3 answers

Suman Sharma 5 years, 8 months ago

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Mimansa Gupta 5 years, 8 months ago

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Shreya S❤ シュレヤ愛ハーシット 5 years, 8 months ago

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Is mathematics is too hard in class 11

Posted by Life Kumar 5 years, 8 months ago

CBSE > Class 11 > Mathematics

5 answers

Suman Sharma 5 years, 8 months ago

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Ajay Sharma 5 years, 8 months ago

Not so hard

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Divyanshu Pal 5 years, 8 months ago

Is depend upon yout hard work

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Aditya Chauhan 5 years, 8 months ago

No !

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Life Kumar 5 years, 8 months ago

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Class 11 mai hindi bhi h agar h to vo parai bhi jaigi

Posted by Har Har Mahadev 🙏 5 years, 9 months ago

CBSE > Class 11 > Mathematics

2 answers

Suman Sharma 5 years, 8 months ago

Hmm mera bhi same

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? Royal Thakur ? 5 years, 9 months ago

Hmm....hindi aur i.t me se choose krna hai

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Find the sum of integers from 1to2001

Posted by Khushboo Gupta 5 years, 9 months ago

CBSE > Class 11 > Mathematics

4 answers

Drake Verma 5 years, 8 months ago

Or u can use the second formula for calculating sum which is- Sn=n/2[a+l] So,from above u can see yogita has already finded the value of n which is 1001 and here u have l=2001 so, Sn=1001/2[1+2001] =1001*1001 =1002001. #Ans

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Mimansa Gupta 5 years, 8 months ago

2003001

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Sanjay Kumar 5 years, 8 months ago

In this question AP has been formed, which is 1,2,3,4,5,.....,2001, in which a = 1, d = a2-a1 = 2-1 = 1, l = 2001, n = 2001 S2001 = n/2(a+l) =2001/2(1+2001) =2003001, Answer Hence, the sum of integers from 1 to 2001 is 2003001.

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Yogita Ingle 5 years, 9 months ago

The odd integers from 1 to 2001 are 1, 3, 5, …1999, 2001.
This sequence forms an A.P.
Here, first term, a = 1
Common difference, d = 2
Here,<nobr>
a+(n−1)d=2001
=>1+(n−1)(2)=2001
=>2n−2=2000
=>n=1001
S_n= n2[2a+(n−1)d]
∴S_n= 10012[2×1+(1001−1)×2]
= 10012 [2+1000 × 2]
=10012×2002
=1001×1001
=1002001</nobr>
Thus, the sum of odd numbers from 1 to 2001 is 1002001.

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Can i have a video of sets which explains me full chapter in a manner

Posted by Ditin Agrawal 5 years, 9 months ago

CBSE > Class 11 > Mathematics

2 answers

? Royal Thakur ? 5 years, 9 months ago

YouTube pe available hai...

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Αα∂Уα Ѕιиgн ? 5 years, 9 months ago

Search on YouTube....

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If z=x+iy is any complex number then /z/=4, represent a

Posted by Pramod Prajapati 5 years, 9 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

Find the sum of n terms of sereis 5+11+19....

Posted by Sheyon Thomas 5 years, 9 months ago

CBSE > Class 11 > Mathematics

2 answers

Ankit ?? Kumar 5 years, 9 months ago

Go to google

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Mr. Badmash 5 years, 9 months ago

Brainly.in What is your question? Secondary School Math 6 points Find the sum to n terms of series: 5+11+19+29+41.............It is G.P of 11th Std not A.P. Ask for details Follow Report by Rajendrapatel25 27.10.2018 Answers preetam98 preetam98 Ambitious N(n+1)(2n+1/3+1)-1 n(n+1)(2n+4)/6-1 3.6 30 votes THANKS 35 Comments (1) Report Thank you so much Log in to add a comment pr264428 Ambitious Answer: \frac{n(n+1)(2n+4)}{6}-1 Step-by-step explanation: In the given series, We have the series, 5 + 11 + 19 + 29 + 41 + ................. So, We can simply write it as, 5 + 11 + 19 + 29 + 41 + ................. = (2² + 1) + (3² + 2) + (4² + 3) + (5² + 4) + ............ On rearranging, we get, = (2² + 3² + 4² + 5² +.......) + (1 + 2 + 3 + ........) Now, we know that sum of squares of first 'n' terms is given by, Sum=\frac{n(n+1)(2n+1)}{6} So, We can write the first part as, 2^{2} + 3^{2} + 4^{2} + 5^{2} +.......=\frac{n(n+1)(2n+1)}{6}-1 also, Sum of the second half is given by, Sum=\frac{n}{2}(2a+(n-1)d)\\Sum=\frac{n}{2}(2+(n-1))=\frac{n}{2}(n+1) Therefore, the total sum of the 'n' terms is given by, Sum=(\frac{n(n+1)(2n+1)}{6}-1)+\frac{n}{2}(n+1)\\Sum=\frac{n}{2}(n+1)\left[\frac{2n+1}{3}+1\right]-1\\Sum=\frac{n(n+1)(2n+4)}{6}-1 Therefore, the sum of the the terms is given by, Sum=\frac{n(n+1)(2n+4)}{6}-1\\

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Iim ( X^2-24X-16/X^2-2X-12) X-0

Posted by Arjun Singh 5 years, 9 months ago

CBSE > Class 11 > Mathematics

1 answers

Manisha Tiwari 5 years, 9 months ago

Here limit is x tends to 0 so put x=0 here and you will get the answer as 4/3

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1/9 part of right angle

Posted by Ujjwal Taliyan 5 years, 9 months ago

CBSE > Class 11 > Mathematics

1 answers

Manisha Tiwari 5 years, 9 months ago

First convert 90 degree to radian and divide it by 9 so answer will be like (90*(180/π))/9=1800/π

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15.1 question no 11 and12

Posted by Abdul Majid 5 years, 9 months ago

CBSE > Class 11 > Mathematics

0 answers

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1+1+1+1+23

Posted by Sarika Sejkar 5 years, 9 months ago

CBSE > Class 11 > Mathematics

3 answers

Sajid Raza 5 years, 9 months ago

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Aditya Chauhan 5 years, 9 months ago

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Divyanshi??? Singh 5 years, 9 months ago

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2×2+2

Posted by Sarika Sejkar 5 years, 9 months ago

CBSE > Class 11 > Mathematics

3 answers

Sajid Raza 5 years, 9 months ago

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Aditya Chauhan 5 years, 9 months ago

6 Applying BoDmas

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Divyanshi??? Singh 5 years, 9 months ago

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I have pcmb , eng and physical education ......as my subjects. Im a biology student so i want to know that if i fail in maths will i pass class 12 as i have opted for physical education?

Posted by Riku Borah 5 years, 9 months ago

CBSE > Class 11 > Mathematics

1 answers

Satyajit Patra 5 years, 9 months ago

Without PE also you will pass

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What is domain and codomain in set?

Posted by Partha Pratim Halder 5 years, 9 months ago

CBSE > Class 11 > Mathematics

0 answers

ANSWER

Insert 6 numbers between 3 and 24 such that the resulting sequence is an A.P

Posted by Kunjilakshmi Balakrishnan 5 years, 9 months ago

CBSE > Class 11 > Mathematics

3 answers

Drake Verma 5 years, 8 months ago

U can start by Letting 6 no. Be A1,A2,A3,A4,A5,A6 between 3&24. So here,a=3 , b=24, n=8 So,l=an 24=3+(8-1)d D=3 A1=a+d=3+3=6. A2=a+2d=3+2*3=9 Similar A3,A4,A5 and A6 will be 12,15,18 and 21. So, resulting series will be 3,6,9,12,15,18 and 21. #ANS

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Rudra Parashar 5 years, 9 months ago

Sorry....you would take n=8 ( including 3 and 24)

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Rudra Parashar 5 years, 9 months ago

You are given a=3 An=24 N=6 Use an = a+(n-1)d Find d and put the no. Accordingly

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Sinx -sinx divided by x cube

Posted by Science Students 5 years, 9 months ago

CBSE > Class 11 > Mathematics

1 answers

Raghvendra Shukla 5 years, 9 months ago

What..?

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If a wheel make 120 revolution in one second through how many radians does it turn in one second

Posted by Dhruvh Sharma 5 years, 9 months ago

CBSE > Class 11 > Mathematics

1 answers

Science Students 5 years, 9 months ago

No.of revolution in one minute:360 So in one second:360/60=6 In one revolution wheel turns:2 pie radian In 6 complete revolution it turns:6*2pie....=12pie

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In how many ways can the letter of the word " MATHEMATICS" be arranged 1. word start with H and C 2.There are always 4 letter between H and C

Posted by Kuldeep Kumar 5 years, 9 months ago

CBSE > Class 11 > Mathematics