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Preeti Dabral 1 year, 8 months ago
Solution is given below:
{tex}\begin{aligned} & n(A \cup B)=n(A)+n(B)-n(A \cap B) \\ & n(B)=42-20+4=26 \\ & n(A-B)=n(A)-n(A \cap B)=20-4=16 \\ & n(B-A)=n(B)-n(A \cap B)=26-4=22 \end{aligned}{/tex}
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Preeti Dabral 1 year, 8 months ago
We are given that, p = 4 and ω = 150
Now, {tex}\cos 15^{\circ}=\frac{\sqrt{3}+1}{2 \sqrt{2}}{/tex}
and {tex}\sin 15^{\circ}=\frac{\sqrt{3}-1}{2 \sqrt{2}}{/tex}
The equation of the line is x cos ω + y sin ω = p
{tex}x \cos 15^{\circ}+y \sin 15^{\circ}{/tex}
or {tex}\frac{\sqrt{3}+1}{2 \sqrt{2}} x+\frac{\sqrt{3}-1}{2 \sqrt{2}} y=4{/tex}
or {tex}(\sqrt{3}+1) x+(\sqrt{3}-1) y=8 \sqrt{2}{/tex}
This is the required equation.
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Aamir Gour 1 year, 8 months ago
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Pashupati Yadav 1 year, 6 months ago
0Thank You