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Ask QuestionPosted by Pooja Singh 4 years, 10 months ago
- 1 answers
Yogita Ingle 4 years, 10 months ago
In an hour or 60 minutes, the large hand performs a complete circle of 360 degree.
Therefore, in a time span of 20 minutes or One third of one Hour, you will get 120 degree or
To find the count of centimeters it is required to move the hand, we first frame the formula i.e. to find the length of the “arc” formed by circular movement of the hand
Therefore, the extremity moves 88 cm in twenty minutes.
Posted by Jagpal Singh 4 years, 10 months ago
- 1 answers
Posted by Amit Kumar 4 years, 10 months ago
- 2 answers
Gaurav Seth 4 years, 10 months ago
Let ‘a’ be the first term and ’r’(≠) be the common ratio of the given G.P.The general teams of G.P. If Sn denotes the sum of ‘n’ terms, then,
Sn = a((1 - rn)/(1 - r)) r ≠ 1
This can also written as
Sn = a((rn - 1)/(r - 1))
Note: (1) Sn = a + ar + ar2 +….. +arn-1
(2) If r = 1, then Sn = a + a + a +……………+a – na
(3) If r = 1, then formulas for Sn fail
(4) If r < 1, then use Sn = a((1 - rn)/(1 - r))
(5) If r > 1, use Sn = a((rn - 1)/(r - 1))
(6) Sum of an infinite G.P.,a + ar + ar2 + ..... is a/(1 - r), - 1 r < 1
(7) If a, b, c are in G.P.then ‘b’ is the G.M. (geometric mean) between a and c, then b2 = ac ⇒ b = √ac
(8) If A and G are A.M. and G.M. of two given distinct positive real numbers, then relation between A and G is A > G.
Posted by Śěřãj The Cute? 4 years, 10 months ago
- 4 answers
?Ritesh Gupta? 4 years, 10 months ago
Posted by Śěřãj The Cute? 4 years, 6 months ago
- 1 answers
Sia ? 4 years, 6 months ago
Posted by Śěřãj The Cute? 4 years, 10 months ago
- 2 answers
Yogita Ingle 4 years, 10 months ago
The Fibonacci sequence, also known as Fibonacci numbers, is defined as the sequence of numbers in which each number in the sequence is equal to the sum of two numbers before it. The Fibonacci Sequence is given as:
Fibonacci Sequence = 0, 1, 1, 2, 3, 5, 8, 13, 21, ….
Here, the third term “1” is obtained by adding first and second term. (i.e., 0+1 = 1)
Similarly,
“2” is obtained by adding the second and third term (1+1 = 2)
“3” is obtained by adding the third and fourth term (1+2) and so on.
For example, the next term after 21 can be found by adding 13 and 21. Therefore, the next term in the sequence is 34.
Posted by Dεερακ Ȿιηɠꜧ 4 years, 10 months ago
- 3 answers
Posted by Dεερακ Ȿιηɠꜧ 4 years, 10 months ago
- 2 answers
Posted by Veena B M 4 years, 10 months ago
- 0 answers
Posted by Noanchi Rangsa 4 years, 10 months ago
- 2 answers
Posted by Varun Verma 4 years, 10 months ago
- 3 answers
Posted by Ambady Legend 4 years, 10 months ago
- 1 answers
Yogita Ingle 4 years, 10 months ago
It is given that:
n(X)=17,n(Y)=23,n(X∪Y)=38
n(X∩Y)=?
Using the formula
n(X∪Y)=n(X)+n(Y)−n(X∩Y)
∴38=17+23−n(X∩Y)
⇒n(X∩Y)=40−38=2
∴n(X∩Y)=2
Posted by Dεερακ Ȿιηɠꜧ 4 years, 11 months ago
- 2 answers
Nishant Kumar 4 years, 10 months ago
Posted by R. Prasad 4 years, 11 months ago
- 1 answers
Posted by Mahalakshmi Bujji?? 4 years, 11 months ago
- 0 answers
Posted by Sagarika Loka 4 years, 11 months ago
- 1 answers
Posted by Mahalakshmi Bujji?? 4 years, 11 months ago
- 2 answers
Nishtha Kalra 4 years, 11 months ago
Gaurav Seth 4 years, 11 months ago
(1.1)^(10000) = (1 + 0.1)^(10000)
use formula,
(x + y)^n = nC0.x^n + nC1.x^(n-1)y + nC2.x^(n-2)y^2 + ........+nCn.y^n
(1 + 0.1)^(10000) = 10000C0.(1)^(10000) + 10000C1.(1)^9999(0.1) + ....... other terms
= 1 × 1 + 10000 × 0.1 + ......... other terms .
= (1 + 1000 + .......other terms ) > 1000
hence, (1.1)^(10000) > 1000
Posted by Abhinav S S 4 years, 11 months ago
- 1 answers
Gaurav Seth 4 years, 11 months ago
As, it is given that k th term of the A.P. is 5k + 1.
therefore,
ak = a + (k – 1)d
⇒ a + (k – 1)d = 5k + 1
⇒ a + kd – d = 5k + 1
now, on comparing the coefficient of k, we get,
d = 5
and
a – d = 1
⇒ a – 5 = 1
⇒ a = 6
Posted by Siddharth .(.$Id) 4 years, 11 months ago
- 3 answers
Yogita Ingle 4 years, 11 months ago
We know that graph of general equation of first degree in two variables, Ax + By + C = 0, where A, B and C are real constants such that A and B are not zero simultaneously is a straight line.
Thus General Equation of Straight line is Ax + By + C = 0, where A, B and C are real constants such that A and B are not zero simultaneously.
Posted by Siddharth .(.$Id) 4 years, 11 months ago
- 2 answers
Yuvraj Singh 4 years, 11 months ago
Yogita Ingle 4 years, 11 months ago
The graph of the linear equation y = mx + c is a line with m as slope, m and c as y-intercept. This form of the linear equation is called slope-intercept form. The values of m and c are real numbers.
The slope, m, represents the steepness of a line. The slope of the line is also termed as gradient, sometimes. The y-intercept, b, of a line, represents the y-coordinate of the point where the graph of the line intersects the y-axis.
Posted by Osm Gamers 4 years, 11 months ago
- 1 answers
Gaurav Seth 4 years, 11 months ago
The question is not clear
Assuming the question to be: Express the given complex number in the form a + ib: (1 – i)4
A n s w e r
complex number in the form a + ib:
Posted by Osm Gamers 4 years, 11 months ago
- 2 answers
Dεερακ Ȿιηɠꜧ 4 years, 11 months ago
0=0 → LHS= RHS ,, , . hence proved
Posted by Vansh Thakur 4 years, 11 months ago
- 1 answers
Magan Garval 4 years, 10 months ago
Posted by Ranger King 4 years, 11 months ago
- 1 answers
Ranger King 4 years, 11 months ago
Posted by Dhruv Sharma 4 years, 11 months ago
- 2 answers
Ranger King 4 years, 11 months ago
Yogita Ingle 4 years, 11 months ago
The three numbers in GP are 4 , 8 , 16.
- Let the three numbers in GP be a/r , a , ar.
- Now the product of three numbers is given as 512.
a/r × a × ar = 512
a³ = 512
a = 8
- Now sum of the three numbers is given as 28.
a/r + a + ar = 28
8/r + 8 + 8r = 28
8 + 8r² = 20r
8r² - 20r + 8 =0
8r² - 16r - 4r + 8 =0
8r(r-2) - 4(r-2) = 0
(r-2)(8r-4) = 0
- Therefore, r = 2 or r=1/2
- Now , the three numbers are 4,8,16.
Posted by Akhil Baluni 4 years, 11 months ago
- 3 answers
Abirami Kamalbabu 4 years, 11 months ago
Ranger King 4 years, 11 months ago
Posted by Doli Kansal 4 years, 11 months ago
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Ranger King 4 years, 11 months ago
Posted by Sri Watsa Cbse Board Exam 4 years, 11 months ago
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