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    • Posted by Shiva Yadav 7 years, 10 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
    ANSWER
    Cos

    • Posted by Noorjaha Khatun 7 years, 10 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Ayaan Firoz 7 years, 10 months ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Chandrashekhar Wankhede 7 years, 10 months ago

    Any point on Parabola will have co-ordinates (at2, 2at) read as (a t square, 2 a t) . where t is unique for a point on parabola. It is given that all three vertices of equilateral triangle are lying on parabola y2= 4ax. One of point is O(0,0). Other two points will be at t = t1 --> P(at12, 2at1) , at t = t2 --> Q(at22, 2at2). As all three points are vertices of equilateral triangle then OP = OQ. Solving by distance formula, we will get t12= t22 ( read as t1 square = t2 square) , which mean t1= t2, t1= -t2 or -t1= t2. t1 can't be equal to t2 otherwise triangle can't be formed. It means t1 = - t2 , or - t1= t2 , it mean Y co-ordinates(2at) of other two points will have same magnitude but opposite signs. It means that axis of parabola bisects the side of equilateral triangle opposite to vertex (0,0). Also Distance PQ will be length of side of equilateral triangle.

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    • Posted by Ajeet Pal Singh Grewal 7 years, 10 months ago

    CBSE > Class 11 > Mathematics
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    • Posted by Vikas Sharma 7 years, 10 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Neeraj Singh Thainua 7 years, 10 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Tanish Chauhan 7 years, 10 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Bhuvan Rao 7 years, 10 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Anjani Ray 7 years, 10 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Rishabh Dixit 7 years, 10 months ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Chandrashekhar Wankhede 7 years, 10 months ago

    Pl clear " vowels are consonents" ..Retype correct question..

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    • Posted by Kailash Pradhan 7 years, 10 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Ansh Saronja 7 years, 10 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Brij Kishore 7 years, 10 months ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Yashu Tyagi 7 years, 10 months ago

    4x=2×2x let 2x=∆ now, cos2∆=1-2sin"∆ put value of ∆=2x cos4x =1-2(sin 2x)". sin2x =2sinxcosx cos4x =1-2(2sinxcosx)" cos4x =1-2(4sin"xcos"x) cos4x =1-8sin"xcos"x

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    • Posted by Ananya Mishra 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 2 answers

    Chandrashekhar Wankhede 7 years, 10 months ago

    Normal form of Line 3x-4y=-4 is , x cos k + y Sin k = p, where p is length of perpendicular from origin to that line and k is angle made by that perpendicular with positive x-axis. As both forms represents same line, Alternately we can consider them as two different coinciding lines. Hence we can write 3/(cos k) = -4/(sin k) = -4/p From this equation we can determine cos k and sin k and then value of p by using identity sqr(Sin k) + sqr(cos k)= 1. You can also determine tan k. As per my calculation tan k = -4/3 therefore angle k = tan inverse (-4/3) , angle k will be greater than 90 degree as tan k is negative. Also p = 4/5.. We can directly substitute cos k and sin k values in normal form x cos k + y Sin k = p, without knowing actual value of k.

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    Chandrashekhar Wankhede 7 years, 10 months ago

    x cos $ + y sin $ = p is normal form of same line 3x - 4y = - 4 , where p is perpendicular distance of line from origin and $ is angle made by that perpendicular with positive X axis. As both equation represents same line we can consider them as two different lines which are "coinciding" . Hence we can write (3/ cos $)=(-4/sin $)=(-4/p) , from these ratios we can find cos $, sin $ and hence tan $ and angle $. p can also determined using identity sqr(sin $) + sqr(cos $) = 1. After knowing value of p and $ , we can substitute in normal form equation..

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    • Posted by Ankita Karn 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Aakash Kumar 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 4 answers

    Rishabh Dixit 7 years, 10 months ago

    1

    0Thank You

    Ashutosh Kumar Jha 7 years, 11 months ago

    1

    2Thank You

    Murli Pandey 7 years, 11 months ago

    1 since it's value is formed by division of sin45 and cos45 which is 1/2*2=1

    1Thank You

    Ankita Karn 7 years, 11 months ago

    1

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    • Posted by Supreet Jain 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Chirag Bhardwaj 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Arsalan Mehboob 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Shivam Kumar 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Chirag Bhardwaj 7 years, 11 months ago

    In mathematical operations.

    3Thank You

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    • Posted by Utkarsh Singh 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Janvi Tyagi 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Saif S 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 2 answers

    Chirag Bhardwaj 7 years, 11 months ago

    Min 6 , max 9.

    1Thank You

    Janvi Tyagi 7 years, 11 months ago

    9

    1Thank You

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    • Posted by Arpit Parakh 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Lavanya Singh 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Mayank Pathak 7 years, 11 months ago

    Dy/dx=x×d(sinx)/dx+sinxd(x)/dx = Xcosx+sinx..... Because d(sinx)/dx=cosx anddx/dx=1

    2Thank You

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    • Posted by Shilpi Nil 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Shilpi Nil 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Rajnish Kumar 7 years, 11 months ago

    Is the ans 1. ???

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    • Posted by Rahul Joshi 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Gaurav Sharma 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 0 answers
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    • Posted by Sanjana Nunna 7 years, 11 months ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Anjali Jaiswal 7 years, 10 months ago

    Lim sin^2x+h-sin^2x upon h htending to0 Lim. Sin2x+h.sinh upon h. (sin^2A-sin htending to 0. =sin2x

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