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Soumya Teggi 7 years, 10 months ago

U have read score lesson
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Tanmaya Nayak 7 years, 10 months ago

1st:: find the point of intersection of lines x+2y-3=0 and 4x-y+7=0 , which is the solution of the lines. (use substitution or elimination method) 2nd:: find the slope of 5x+4y-20=0 (y=mx+c,where m is the slope or coefficient of x) 3rd:: since two lines are to be parallel, slope must be equal. 4th:: Use slope point form to get the equation[m=(y-y') /(x-x') where x'and y' are the solutions in step 1] Hope you got your answer All the best.
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Priya Kumari 7 years, 10 months ago

12
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Priya Kumari 7 years, 10 months ago

Tan15°=tan(45°-30°) then by applying the formula of tan(x-y) we get √3-1/√3+1 and cot15° will be the reciprocal of tan15° then by solving these two we will get 4
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Priya Kumari 7 years, 10 months ago

Cos square x+sin square x/cos square x

Ram Joshi 7 years, 10 months ago

(Cosx d/dx Sinx - Sinx d/dx Cosx)/Cos^2x [Cosx(Cosx) - Sinx(-Sinx)]/Cos^2x (Cos^2x + Sin^2x)/Cos^2x 1/Cos^2x
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Raman Preet Singh 7 years, 10 months ago

(x-2i)(1+i) = x+2 -i(x-2) X+2 = 0 X=-2
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4*3
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Laxmi Maheshwari 7 years, 10 months ago

12
1+3
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Vishnu Nair 7 years, 10 months ago

4

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