Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Śěřãj The Cute? 4 years, 10 months ago
- 5 answers
Posted by Sreenidhil Kp 4 years, 10 months ago
- 1 answers
Swastik . P 4 years, 10 months ago
Posted by ?Ritesh Gupta? 4 years, 10 months ago
- 1 answers
Posted by Garima Sharma 4 years, 10 months ago
- 1 answers
First Name 4 years, 10 months ago
Posted by Madhur Kumar 4 years, 10 months ago
- 2 answers
Posted by D Nathyadav 4 years, 10 months ago
- 4 answers
Posted by Rohit Rai 4 years, 10 months ago
- 2 answers
Posted by Muhammed Muhasin 4 years, 10 months ago
- 4 answers
Dεερακ Ȿιηɠꜧ 4 years, 10 months ago
Gaurav Seth 4 years, 10 months ago
A natural number is a number that occurs commonly and obviously in nature. As such, it is a whole, non-negative number. The set of natural numbers, denoted N, can be defined in either of two ways:
N = {0, 1, 2, 3, ...}
N = (1, 2, 3, 4, ...}
Posted by Subrat Kumar Majhi 4 years, 10 months ago
- 2 answers
Posted by Prabal Verma 4 years, 10 months ago
- 3 answers
Abirami Kamalbabu 4 years, 10 months ago
Posted by Smiley __ 4 years, 10 months ago
- 2 answers
Rajneesh Singh 4 years, 10 months ago
Posted by Vaishali ..... 4 years, 10 months ago
- 2 answers
Posted by Archana ..... 4 years, 10 months ago
- 1 answers
Posted by Sugumari S 4 years, 10 months ago
- 4 answers
Raunak Chauhan 4 years, 10 months ago
Posted by Divya Sree V 4 years, 10 months ago
- 4 answers
Posted by Aryan Singh 4 years, 10 months ago
- 2 answers
Tec Om 4 years, 10 months ago
Posted by Hitesh Jindal 4 years, 10 months ago
- 1 answers
Gaurav Seth 4 years, 10 months ago
Find the critical points, here they are 1 and 3.
solve for x<1,
-(x-1)-(-(x-3))≥0
-x+1+x-3≥0
-2≥0 (not possible)
Thus, x should be greater than 1
For 1 ≤ x ≤ 3
(x-1)-(-(x-3))≥0
2x-4≥0
x≥2
So one solution set is 2≤x≤3
For x>3
(x-1)-(x-3)≥0
2≥0
Therefore from above two results,
x≥2
Posted by Jasleen Kaur 4 years, 10 months ago
- 2 answers
Raunak Chauhan 4 years, 10 months ago
Gaurav Seth 4 years, 10 months ago
Answer:
Sum = 5 + 55 + 555 + …. n terms.
= 5/9 [9 + 99 + 999 + …. n terms]
= 5/9 [(10 – 1) + (100 – 1) + (1000 – 1) + … n terms]
= 5/9 [10 + 100 + 1000 ….. – (1 + 1 + … 1)]
= 5/9 [10(10n – 1)/(10 – 1) + (1 + 1 + … n times)]
= 50/81(10n – 1) – 5n/9
Posted by Mansi Pareek 4 years, 10 months ago
- 4 answers
Posted by Prabh Prabh 4 years, 10 months ago
- 1 answers
Sruti Mohanty 4 years, 10 months ago
Posted by Swaradhya E.Enandan Verma 4 years, 10 months ago
- 1 answers
Posted by Himanshu Sharma 4 years, 10 months ago
- 1 answers
Anmol Agarwal 4 years, 10 months ago
Posted by Harshita Bansal❤️ 4 years, 10 months ago
- 1 answers
Deepanshu Tyagi 4 years, 10 months ago
Posted by Sadique Ansari 4 years, 6 months ago
- 1 answers
Sia ? 4 years, 6 months ago
Posted by .... .... 4 years, 10 months ago
- 1 answers
Nisha Kashyap 4 years, 10 months ago
Posted by सत्य सनातन? 4 years, 10 months ago
- 3 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Abirami Kamalbabu 4 years, 10 months ago
3Thank You