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Keshav Bindal 7 years, 4 months ago
As we all know,
tan70°=tan(20+50)°
tan70°=(tan20°+tan50°)/1-tan20°tan50°
tan70°-tan20°tan50°tan70°=tan20°+tan50°
Also
tan70°tan20°=tan70°cot70°=1
Hence
tan70°-tan50°=tan20°+tan50°
So tan70°=tan20°+2tan50°
Posted by Esha Rani 7 years, 4 months ago
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Keshav Bindal 7 years, 4 months ago
L.H.S.
sec4θ - sec2θ
= sec2 θ [ sec2 θ - 1 ] { taking sec2 θ as common }
= sec2θ . tan2θ
R.H.S.
tan4θ +tan2θ
=tan2θ [ tan2θ + 1 ]
= tan2θ . sec2θ
=> L.H.S. = R.H.S.
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