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tan3x

Posted by Harsh Vardhan 7 years, 4 months ago

CBSE > Class 11 > Mathematics

2 answers

Rishab Kapoor 7 years, 4 months ago

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Nancy Rajput 7 years, 4 months ago

3 tanx-tan^3x/1-3tan^2x

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(1+cosπ/8)(1+cos3π/8)(1+cos5π/8)(1+cos7π/8)

Posted by Rishi Yadav 7 years, 4 months ago

CBSE > Class 11 > Mathematics

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Sin11AsinA+sin7ASin3A÷cos11AsinA+cos7Asin3A=tan8A

Posted by Vipul Bisht 7 years, 4 months ago

CBSE > Class 11 > Mathematics

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Prove that:1+sin2θ+cos2θ/1+sin2θ-cosθ=cotθ

Posted by Deepak Maurya 7 years, 4 months ago

CBSE > Class 11 > Mathematics

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cos20°cos40°cos60°cos80°=1/16. Prove.

Posted by Rishika Gupta 7 years, 4 months ago

CBSE > Class 11 > Mathematics

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ANSWER

If pth and qth terms of a GP are a and b respectively,find the nth term.

Posted by Abhinav Srivastav 7 years, 4 months ago

CBSE > Class 11 > Mathematics

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In class 11 half or full syallabus comes in final exam

Posted by Raunak Jha 7 years, 4 months ago

CBSE > Class 11 > Mathematics

2 answers

Christin Mathew 7 years, 4 months ago

Full syllabus

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Sujatha Vijay 7 years, 4 months ago

Full obviously

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Find value of cos 5°+ cos 10°+ cos 15°+ cos 20°+.......+ cos 180°

Posted by Shravani Py 7 years, 4 months ago

CBSE > Class 11 > Mathematics

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Why the value of iota 0 is 1?

Posted by Sushant Pratap 7 years, 4 months ago

CBSE > Class 11 > Mathematics

1 answers

Sujatha Vijay 7 years, 4 months ago

Because i^2=-1, so i= + or - 1 when u take square root and not zero

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F(x)=log 1-x/1+x. Prove that f(a)+f(b)=f[a-b /1+ab]

Posted by Aadarsh Kurmi 7 years, 4 months ago

CBSE > Class 11 > Mathematics

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We know that sum of interior angle of a triangle is 180 show that th

Posted by Sona Kumari 7 years, 4 months ago

CBSE > Class 11 > Mathematics

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Guys who want to talk to.me ?

Posted by Mickey Mickey 5 years, 8 months ago

CBSE > Class 11 > Mathematics

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Chapter 5 of Element of Mathematics ka Solution Kaha mela ga

Posted by Rajinder Kumar 7 years, 4 months ago

CBSE > Class 11 > Mathematics

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1/3.6+1/6.9+1/9.12+..+1/3n(3n+3)=n/9(n+1)

Posted by Jay Thacker 7 years, 4 months ago

CBSE > Class 11 > Mathematics

1 answers

Suman Sharma 7 years, 4 months ago

Step 1 put (n=1) L.H.S. 1/3.6=1/18 R.H.S. n/9(n+1)=1/9(1+1) =1/9.2 =1/18 Step 2 Let it be true for (n=k) 1/3.6+1/6.9+1/9.12+...+1/3k(3k+3)=k/9(k+1) Step 3 Put (n=k+1) 1/3.6+1/6.9+1/9.12+...+1/3(k+1)(3(k+1)+3)=k+1/9(k+1+1) =1/3.6+1/6.9+1/9.12+...+1/3k(3k+3)+1/(3k+3)(3k+6)=k+1/3(3k+6) L.H.S. =k/3(3k+3)+1/(3k+3)(3k+6) =1/3k+3(k/3+1/3k+6) =1/3k+3(3k^2+6k+3/3(3k+6)) =1/3k+3((k+1)(3k+3)/3(3k+6)) =1(k+1/3(3k+6)) =k+1/3(3k+6)=R.H.S.

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Let S be a set of give different positive integers, the if which is n. It is impossible to construct a quadrilateral with non-zero area, whose side lengths are all distinct elements of S. The smallest value of n is?

Posted by Nithilasaravanavel Scientist 7 years, 4 months ago

CBSE > Class 11 > Mathematics