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  • 3 answers

Aditi _Chouhan_ 7 years ago

The answer is 14

Yakshi ? 7 years, 1 month ago

Answer : 14

Yakshi ? 7 years, 1 month ago

Arithematic mean =( a + b )/2that means as u have two no.s 9 and 19. Let them as a and b and put them in formula.......u will get the answer
  • 3 answers

Yakshi ? 7 years, 1 month ago

From which chapter this question is????

Yakshi ? 7 years, 1 month ago

Mahendra plz tell me the reason.....i don't get the answer

Mahendra D 7 years, 1 month ago

(2,3,5)
  • 1 answers

Harsh Mishra 7 years, 1 month ago

The differentiation of sec {tan root( x )} is ? as given: Answer, y'=sec(tan(x))tan(tan(x))(sec2(x)) Solution : If, y=sec(f(x)) then using chain rule, y'=sec(f(x))tan(f(x))f'(x) In same way, y'=sec(tan(x))tan(tan(x))(tan(x)) ' y' =sec(tan(x))tan(tan(x))(sec2(x))
  • 3 answers
R D Sharma is best book for maths

Ayushi Ayushi 7 years, 1 month ago

For your knowledge - The rule is named after the 17th-century French mathematician Guillaume de l'Hôpital. Although the contribution of the rule is often attributed to L'Hôpital, the theorem was first introduced to L'Hôpital in 1694 by the Swiss mathematician Johann Bernoulli.

Ayushi Ayushi 7 years, 1 month ago

In mathematics, and more specifically in calculus, L'Hôpital's rule or L'Hospital's rule (French: [lopital]) uses derivatives to help evaluate limits involving indeterminate forms. Application (or repeated application) of the rule often converts an indeterminate form to an expression that can be evaluated by substitution, allowing easier evaluation of the limit.
  • 1 answers

Helly Patel 7 years, 1 month ago

Here, tanA =a/a+1. And. TanB = 1/2a+1 A = tan–¹(a/a+1) B = tan –¹(1/2a+1) A+B = tan–¹(a/a+1) + tan–¹ (1/2a+1) = tan–¹[(a/a+1) + (1/2a+1) / 1 - (a/a+1)(1/2a+1)] = tan–¹(2a²+2a+1/2a²+2a+1) = tan –¹(1) = tan–¹[tan(π/4)] =π/4
  • 3 answers
1+cotAcotB/cotA-cotB

Harsh Mishra 7 years, 1 month ago

The formula for Cot A - Cot B is ?. [-2 Sin A+B/2 • Sin A-B/2] , where dot implies to multiplication between them.???

Hrittick Ram 7 years, 1 month ago

{Sin(B-A)/SinASinB}
  • 4 answers

Ram Kushwah 7 years, 1 month ago

cot A-cotB

=cosA/sinA  - cos B/sinB

=(sinBcosA-cosBsinA) /sinAsinB

=sin(B-A) / sinA sinB

Yash Sharma 7 years, 1 month ago

Sin(B-A)/SinASinB

Peter Parker 7 years, 1 month ago

-2sina+b/2*sina-b/2

Mohit Kumar 7 years, 1 month ago

sorru sorry its not cos its (cotA-cotB)
  • 1 answers

Mohit Kumar 7 years, 1 month ago

-2sin x is correct answer
  • 1 answers

Ram Kushwah 7 years, 1 month ago

d2= ((a+b)-(a-b))2 +((a-b)-(a+b))2

=(a+b-a+b)2 + (a-b-a-b)2

=4b2 + 4a2

so d= ((4(a2+b2))1/2

=2 root(a2+b2)

 

  • 2 answers

Nitin Shukla 7 years, 1 month ago

Well i needed the procedure but i did it by my own thanks

Mohit Kumar 7 years, 1 month ago

e^x
  • 1 answers

Ankit Singh 7 years, 1 month ago

In calculus, Rolle's theorem or Rolle's lemma essentially states that any real-valued differentiable function that attains equal values at two distinct points must have at least one stationary point somewhere between them—that is, a point where the first derivative is zero.
  • 0 answers
  • 1 answers

Sivan Karthick 7 years, 1 month ago

Y-y=m(X-x) (slope point form) x/a+y/b=1where a &b are intercept on x and yaxis
  • 2 answers

Priya Dharshini ☺☺ 7 years, 1 month ago

1-cos^2x

Mayank Tiwari 7 years, 1 month ago

1-Cosxsquare
  • 1 answers

Harsh Mishra 7 years, 1 month ago

Slope =5-0/4-0=5/4. . Therefore, Equation=Y-5=5/4*(X-3) 5X-4Y=0.
  • 3 answers

Pragati Gola 7 years, 1 month ago

f (x+h)=lim h->0 tan (x+h)-tanx /h ; lim h->0 sin (x+h-x)/cos (x+h)cosx .h ; lim h->0 sin h/h cos (x+h)cosx ; lim h->0 1/cos (x+h)cosx ; Putting h=0 1/cos (x+0)cosx ; 1/cosx.cosx ; 1/cosx^2 ; Secx^2

Nancy Rajput 7 years, 1 month ago

its sec^2 x

Akash Kumar 7 years, 1 month ago

Answer
  • 1 answers

Nikhil Phogat 7 years, 1 month ago

Break down cos in half angle
  • 1 answers

Ayushi Ayushi 7 years, 1 month ago

In calculus, Rolle's theorem or Rolle's lemma essentially states that any real-valued differentiable function that attains equal values at two distinct points must have at least one stationary point somewhere between them—that is, a point where the first derivative (the slope of the tangent line to the graph of the function) is zero.
  • 6 answers

Priya Dharshini ☺☺ 7 years, 1 month ago

?? yakshiii

Ankit Singh 7 years, 1 month ago

???yakshi

Yakshi ? 7 years, 1 month ago

???

Aditi Mittal 7 years, 1 month ago

Yakshi what! U said???

Yakshi ? 7 years, 1 month ago

With eyes.....or u can also watch it with nose or ears.....

Priya Dharshini ☺☺ 7 years, 1 month ago

U can watch videos to understand that or ask ur teacher. It quite tough to explain by texting.and u will not understand that also
  • 4 answers

Ankit Singh 7 years, 1 month ago

That's right

Muskan ???? 7 years, 1 month ago

Please don't post this rubbish thing....post only Question and try to help other by solving their problem

Ankit Singh 7 years, 1 month ago

Gm

Tanya??? Jaiswal 7 years, 1 month ago

G.m
  • 4 answers

Ankit Singh 7 years, 1 month ago

1

Muskan ???? 7 years, 1 month ago

Tan 45°=1

Saood Khan 7 years, 1 month ago

1

Harsh Mishra 7 years, 1 month ago

Tan 45 degree = Tan ㅠ/4 = 1
  • 1 answers

Ram Fagoria 7 years, 1 month ago

1002001
  • 0 answers
  • 3 answers

Aditi Mittal 7 years, 1 month ago

(X-h)whole square + (Y-k) whole square =rsquare

Christin Mathew 7 years, 1 month ago

(x-h)2+(y-k)2=r2

Akash Kumar 5 years, 9 months ago

Answer

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