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Ashok Kandpal 3 years ago

1 and 2
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Mannu Dahiya 3 years ago

a/4=0 (x axis) =>a=4(0)=>a=0 a-2b=+b(y axis) =>0-2b=b=>-2b=b=>-2b-b=0=>-3b=0=>b=0/-3=>0 Write answer= (0,0)
a=0,b=-3
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12,18,24....96 an=96 a=12 d=6 Let's solving an= a+(n-1)d 96=12+(n-1)6 84=6n-6 90/6=n 15=n

Kunal Tanu 3 years ago

12,18,24......96 a=12 d=6 an=96 96=12+(n-1)6 96-12=6n-6 84+6=6n 90/6=n 15=n

Kunal Tanu 3 years ago

15
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Mannu Dahiya 3 years ago

All numbers in the A and B are different i.e, A={0,1,2,3,4,5}, B={6,7,8,9,10,11}
A intersection B ={ }

Chavi Nijhawan 3 years ago

All numbers in A and B are different
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Intercept form of x = -3/2 Intercept form of y= -3/5
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Saloni Devi 3 years ago

Answer???????

Isha Balhara 3 years ago

Answer
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Here,first term =3 and last term=999. It is an ap-3,9,15,21......... Common difference =6 999=3+(n-1)6 996/6=n-1 166+1=n n=167 Now sum of terms is given by- Snth=n/2(2a+(n-1)d) 167/2(2×3+166×6) 167/2(1002) =83667 L.H.S=R.H.S Hence proved

Sarika Parjapat 3 years ago

?ᴅᴏɴᴛ ᴋɴᴏᴡ
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1/sinA+cosA/sinA=11/2 1+cosA/sinA=11/2 From this we get 1+cosA=11 sinA=2 CosA=10 sinA=2 TanA=2/10=1/5
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It is (1/2)x^-1/2

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