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  • 1 answers

Manoj Kanchani 5 years, 9 months ago

Very very very bheri bheri easy...... U can try it by yourself if u kno basics of this chapter.... I can help u but 2maro is my physics paper and typing nos. Solution is time consuming..... U should try it again nd i hope u can solve it..... I know u have it in u...
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Hemant Tiwari 6 years, 10 months ago

Use cosine = 1-sin^2Φ
3t
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  • 1 answers

Hemant Tiwari 6 years, 10 months ago

We can get this by 10+5=15
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Mr. Ajey ? 6 years, 10 months ago

Limit ka ha ky..
  • 1 answers

Manoj Kanchani 6 years, 10 months ago

Very easy
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Vaibhav Goel 6 years, 10 months ago

No
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Sia ? 4 years, 7 months ago

This solution is known as the general solution. Thus, a solution generalize by means of periodicity is known as the general solution. Note-general soluton is not restricted to only 0 to 2π. The solutions of a trigonometric equation for which 0 <=x < 2pi are called principal solutions.

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Mr. Ajey ? 6 years, 10 months ago

Where are the sample papers ???
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Krittika Kar 5 years, 9 months ago

For n=1 1(1+1)(1+2)(1+3)=1(2)(3)(4)=24 For P(1) it is true. Let us assumes that it is true for n=k Now, P(k)=k(k+1)(k+2)(k+3)=24x (k+1)(k+2)(k+3)=24x/k.....(1) Now for P(k+1)=(k+1)(k+2)(k+3)(k+4) =24[x(k+4)/k] Therefore, it is true for n=k+1 Thus by PMI, it is true for all n belongs to N
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Čůťê Ğīřł ? ? 5 years, 9 months ago

Sin15° = Sin ( 45 - 30 ) {{Now ... we know that , Sin ( A + B ) = SinA Cos B + Cos A sin B }} Thus , Sin 15° = Sin45 Cos 30 + Sin30 Cos 45 => after putting values we will get :: root3+ 1 / 2 root 2
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Čůťê Ğīřł ? ? 6 years, 10 months ago

In these type of questions , firstly multiply and divide the term by 2 and then use:: 2 SinA SinB = Cos(A +B ) - Cos ( A-B ) type identities . And then took common terms outside and then again use above identities ... you will get your answer . Its quit tough to solve the whole question over there. thus, I have told you the procedure .. I hope it will help you ...?
Jai ho dada prashuram ji ki ....
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Shreya Dixit 6 years, 10 months ago

3x -5
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Yash Aggarwal 6 years, 10 months ago

tan4x=2 tan 2x/1-tan^2 2x Now at both again put identity of 2x u will get the answer
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Hemant Tiwari 6 years, 10 months ago

Solve it bro

Abhinav Agarwal 6 years, 10 months ago

{e^(√x+h)-e^h}/h e^√x{e^h-1}/h e^√x
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Abhinav Agarwal 6 years, 10 months ago

0+cosx/(1-sinx)^2
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Dolly ?️ 6 years, 10 months ago

Pie-theta
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Dolly ?️ 6 years, 10 months ago

Lim x-0 sinx(cosx-1)/cosx.X^3 Lim x-0 (sinx) /x. (cosx-1)/x^2 Lim x-0 (cosx-1)(cosx+1)/(cosx+1)x^2 Lim x-0 - sin^2x/(cosx+1).x^2 Lim x-0 - 1/(cosx+1) = - 1/2
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Chetna ? 6 years, 10 months ago

I think u are asking about weightage?

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