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Sia ? 6 years, 3 months ago
You can check syllabus in mycbseguide app of each subject in syllabus last page contains exam design which will help you.
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Sia ? 6 years, 3 months ago
cos (-1710o)
= cos (1710o) (As cos (-x) = cos x)
{tex}=\cos(1710\times{\textstyle\frac{\mathrm\pi}{180}}){/tex}
{tex}=\cos({\textstyle\frac{19\mathrm\pi}2}){/tex}
{tex}=\cos(9{\textstyle\frac12}\mathrm\pi){/tex}
{tex}=\cos(10\mathrm\pi{\textstyle\frac{\mathrm\pi}2}){/tex}
{tex}=\cos(-{\textstyle\frac{\mathrm\pi}2}){/tex}
{tex}=\cos(-{\textstyle\frac{180}2}){/tex}
= cos (-90o)
= cos 90 (As cos (-x) = cos x )
= 0
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Aditya Khurana 6 years, 3 months ago
1Thank You