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Law of mass action also forms the basis which states that the rate of a chemical reaction is directly proportional to the product of the concentrations of the reactants raised to their respective stoichiometric coefficients. Therefore, given the reaction –
aA(g) + bB(g) ⇔ cC(g) + dD(g)
By using the law of mass action here,
- The forward reaction rate would be k+ [A]a[B]b
- The backward reaction rate would be k– [C]c[D]d
where, [A], [B], [C] and [D] being the active masses and k+ and k− are rate constants of forward and backward reactions, also the a, b, c, d are the stoichiometric coefficients related to A, B, C and D respectively. However, at the equilibrium – the forward and the backward rates are equal, stating –
Rate of forward reaction = Rate of backward reaction

or, 
or, 
where, 
Kc is the equilibrium constant expressed in terms of the molar concentrations. The equation Kc = [ C ]c·[ D ]d / [ A ]a·[ B ]b
or, Kc = Kf / Kb is the Law of Chemical Equilibrium. The equilibrium constant is therefore related to the standard Gibbs free energy change for the reaction which is stated by the equation –
§Gº= -RT ln Keq
where T states the temperature, R is the universal gas constant and Keq is the equilibrium constant.

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Ankit Singh 6 years, 11 months ago
1Thank You