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What quantities of two samples of superphosphate, one containing 14 and the other 22 per cent of P20 5, should be mixed to prepare 400 kg of the fertilizer containing 20 per cent of P20 5? What is the ratio of the two samples in the mixture?

Posted by Suriya Prakash 4 years, 3 months ago

CBSE > Class 11 > Chemistry

0 answers

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What did Rutherford conclude from the observations of a-ray scattering experiment?

Posted by Himanshu Rajput 4 years, 3 months ago

CBSE > Class 11 > Chemistry

2 answers

Adithya Dev A 4 years, 3 months ago

A correction, 1) most alpha rays pass straight through atom. 3) 1/12000 alpha rays. Sorry.

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Adithya Dev A 4 years, 3 months ago

1) Most of the α - rays emerged out of the gold foil with large amount of scattering indicating that most of the space inside a gold atom is empty. 2) A few α - rays suffered a small amount of deviation indicating that something which is positive in charge is situated at inside every gold atom. 3) 1 out of every 2000 rays came out of the gold foil undeviated retracing the path indicating that all positive charges present in an atom is accumulated at a very small volume inside the atom.

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The multiple 5*0.2 after rounding off will be

Posted by Monu Gothwal 4 years, 3 months ago

CBSE > Class 11 > Chemistry

1 answers

Monu Gothwal 4 years, 3 months ago

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The multiple after rounding off will be

Posted by Monu Gothwal 4 years, 3 months ago

CBSE > Class 11 > Chemistry

0 answers

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How does molarity and molality depends on temperature

Posted by Lakshay Tyagi 4 years, 3 months ago

CBSE > Class 11 > Chemistry

1 answers

Adithya Dev A 4 years, 3 months ago

When temperature increases, the molarity decreases.

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If 0.85g of NH3 is dissolved in 100ml of solution find molarity if density of solution is 1.2g/ml

Posted by Komal Bharti 4 years, 3 months ago

CBSE > Class 11 > Chemistry

1 answers

Adithya Dev A 4 years, 3 months ago

Molar mass (M2) = 14 + 3 = 17 g// Therefore, M = (W2/ M2 * V) * 1000 = (0.85/ 17 * 100) * 1000 = 0.5 mol/L//

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If mass of 1 atom is 3.32×10^-23g, then calculate the number of nucleons present in 2 atom of the element

Posted by V. Poojitha 4 years, 3 months ago

CBSE > Class 11 > Chemistry

1 answers

Lakshay Tyagi 4 years, 3 months ago

Don't know

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equivalent weight of metal is 12 . weight of its chloride is

Posted by Dhanvi Sharma 4 years, 3 months ago

CBSE > Class 11 > Chemistry

1 answers

Khushi Yadav 4 years, 2 months ago

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Calculate the energy of mole of photon of radiation where f is 5×10^14 Hz

Posted by A Sh. 4 years, 3 months ago

CBSE > Class 11 > Chemistry

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What is the order of -I effect

Posted by Shakshi Rana 4 years, 3 months ago

CBSE > Class 11 > Chemistry

1 answers

Sia ? 4 years, 3 months ago

Often in experimental studies, researchers will have participants provide responses to several different treatments. In these types of studies, order effects refer to differences in participant responses as a result of the order in which treatments are presented to them.

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Chemistry 2 part book

Posted by Simran . 4 years, 3 months ago

CBSE > Class 11 > Chemistry

1 answers

Niraj Shaw 4 years, 3 months ago

Kon sa book? ??

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One mole of any substance contains 6.022 x 1023 atoms/molecules. Number of molecules of H2S04 present in 100 mL of 0.02 M H2S04 solution is __________

Posted by Peter O'Connell 4 years, 3 months ago

CBSE > Class 11 > Chemistry

1 answers

Sia ? 4 years, 3 months ago

Moles of H₂SO₄= Molarity of H₂SO₄× Volume of solution (L)

=0.02×0.1

=2×10−3 moles

No. of H₂SO₄ molecules =2×10−3×6.022×1023=12.044×1020 molecules

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How 1amu=1.66*10^-24

Posted by Gourav Kumar 4 years, 3 months ago

CBSE > Class 11 > Chemistry

0 answers

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(-).^ / \ / \ /----------\ /--------------\ Aromatic or not

Posted by Sabari Krishna 4 years, 3 months ago

CBSE > Class 11 > Chemistry

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Why do alkali metals give blue colour when dissolved in liquid ammonia?

Posted by Eyahiya Ahmed 4 years, 3 months ago

CBSE > Class 11 > Chemistry

1 answers

Sweta Jha 4 years, 3 months ago

Because alkali metals are generally basic in nature.

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At NTP , what will be the volume of molecules of 6.022× 10*23

Posted by Anshika Kumari 4 years, 3 months ago

CBSE > Class 11 > Chemistry

5 answers

Mohak Prakash 4 years, 3 months ago

Nahin hai koi explanation ?

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Ani G 4 years, 3 months ago

First convert it into moles . In order to convert it into moles divide it by Avogadro number then you will get 1 mole. As you know that 1mol= 22.4 litres .

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Anshika Kumari 4 years, 3 months ago

Aditya Dev A I plz tell me in detail with solution

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Adithya Dev A 4 years, 3 months ago

22.4 litres = 22400 ml.

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Anshika Kumari 4 years, 3 months ago

Explain in details plz

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Chemistry mein kuch samajh nahi aa raha hai.....koi batado kaise phado is subject ko....please

Posted by Mary Stuart 4 years, 3 months ago

CBSE > Class 11 > Chemistry

5 answers

Atharva Verma 4 years, 3 months ago

Padhai karte rahein all the very best ?

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Yashika Chauhan? 4 years, 3 months ago

Ary kuch nahi bas ap chapter ko 2ya 3times pdlo only and only ncert then make a mind mape and paste it on your study table then may you understand the chemisrty Hope you like this ?

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Vanshika Sharma 4 years, 3 months ago

Arey kuch nhi hai bas aap ch ko 2, 3 times padho or fir ek youtube channel hai physicswallah bo chemistry ke ch bhi padhata hai to aap vaha se padh lo??

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Khushi Tiwari 4 years, 3 months ago

Don't worry "Mary Stuart " meri bhi problem aisi hi thi par ye isiliye hota h kyuki hamare basics clear nhi hote isiliye iss may month mai sabse pehle apne basics clear karo

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Shweta Palwe 4 years, 3 months ago

Lunch meat Karen Sarah kar

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Calculate normality of 500 ml h2so4 solution prepared by dissolving 49 g h2so4

Posted by Rajveer Kaur 4 years, 3 months ago

CBSE > Class 11 > Chemistry

4 answers

Roopam Almadi 4 years, 3 months ago

N = M * n-factor 1M * 49 So N = 49// * represents ✖ multiply

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Roopam Almadi 4 years, 3 months ago

Normality = M * n-factor =

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Adithya Dev A 4 years, 3 months ago

Normality = mass of solute (in gms) / volume of solution (in litres) = 49/0.5 = 490/5 = 98//

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Abhay Karki 4 years, 3 months ago

Gk knockdown juddhaporadhider sidebar supply try IV on PC ty ty ty ty ty ty ty ty ty ty ty

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Find the molar mass of manganese IV oxide

Posted by Suman Jakhar 4 years, 3 months ago

CBSE > Class 11 > Chemistry

2 answers

Anshika Kumari 4 years, 3 months ago

The molar mass of manganese oxide is 36.9368g mol

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Mary Stuart 4 years, 3 months ago

86.9368g/mol

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in addition to carbon monoxide and carbon dioxide in the third compound of carbon and oxygen called carbon suboxide if a 2.500 gram sample of carbon suboxide contains 1.32 gram of carbon and 1.18 gram of oxygen show that the law of multiple proportions is followed

Posted by Khushi Gehlot 4 years, 3 months ago

CBSE > Class 11 > Chemistry

1 answers

Sia ? 4 years, 3 months ago

In addition to carbon monoxide (CO) and carbon dioxide (CO₂) , there is a third compound of carbon called carbon suboxide. If a 2.5g sample of carbon sub-oxide contains 1.32g of C and 1.18g of O, using the law of multiple proportions, a possible formula of carbon suboxide can be deduced.

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a) 1.75 g copper gives 2.19 g copper oxide. b) 1.135 g copper gives 1.430 g copper oxide. Show that these data confirm the law of definite proportion.

Posted by Varnika Verma 4 years, 3 months ago

CBSE > Class 11 > Chemistry

2 answers

Roopam Almadi 4 years, 3 months ago

Value instead of vaue

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Roopam Almadi 4 years, 3 months ago

It's an easy question Don't be panic First take(a) part then, 2.19 - 1.44 = weight of O2 Then take the ratio of copper to oxygen, the ratio comes out to be 3.9 : 1 Then take (b) part 1.430 - 1.135 = weight of O2 Then take the ratio of copper to oxygen, the ratio comes out to be 3.9 : 1 In this way this data illustrate law of definate proportion Don't take approx bcz it is not allowed Take the exact vaue

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What is particle nature of electromagnetic readiation

Posted by Lakshay Malik 4 years, 3 months ago

CBSE > Class 11 > Chemistry

1 answers

Daksh Gamer 4 years, 3 months ago

Particle Nature-->when radiation interacts with matter

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Given density of water in 1 g/ml, find in kg/m^3

Posted by Suman Jakhar 4 years, 3 months ago

CBSE > Class 11 > Chemistry

2 answers

Adithya Dev A 4 years, 3 months ago

To convert g/ml to kg/m^3, we need to multiply the value with 1000. Therefore, density of water (in kg/m^3) is 1000 kg/m^3.

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Vinit Kumar 4 years, 3 months ago

1000

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Calculate the amount of water produced by the combustion of 25 g of methane

Posted by Kromyx Official 4 years, 3 months ago

CBSE > Class 11 > Chemistry

2 answers

Harshit Gautam 4 years, 3 months ago

You can solve it through mass mass relation

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Harshit Gautam 4 years, 3 months ago

Final answer is 28.125gm

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A sample of NaNO3 weighing 0.38 is placed in a 250ml volumetric flask .The flask is then filled with water to the mark on the neck. What is the molarity of the solution??

Posted by Kumari Shalini 4 years, 3 months ago

CBSE > Class 11 > Chemistry

1 answers

Ramesh S 4 years, 3 months ago

Solution : Mass of dissolved = 0.38 g
Molecular mass of
Moles of dissolved
Volume of solution =250 mL
Molarity
=0.018 M

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Convert 24 days into seconds

Posted by Suman Jakhar 4 years, 3 months ago

CBSE > Class 11 > Chemistry

4 answers

Suhani Kumari 4 years, 3 months ago

2073600 sec

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Vedant Rai 4 years, 3 months ago

2073600

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Poonam Mittewad 4 years, 3 months ago

2073600 sec.

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Poonam Mittewad 4 years, 3 months ago

2073600

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Explain difference in precision and accuracy.

Posted by Suman Jakhar 4 years, 3 months ago

CBSE > Class 11 > Chemistry

1 answers

Adithya Dev A 4 years, 3 months ago

Accuracy indicates how near the measurements obtained experimentally are to the true value. Whereas precision indicates how near two measurements, whether theoretically or experimentally obtained, are to each other.

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give the difference in the origin of cathode and anode rays

Posted by Daksh Pandey 4 years, 3 months ago

CBSE > Class 11 > Chemistry

1 answers

Sia ? 4 years, 3 months ago

Cathode rays originate from the cathode whereas anode rays are not produced from the anode. They are produced from the gaseous atoms by knock out of the electrons by high speed cathode rays.

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What is the molarity of Co2

Posted by Nitin Gurjar 4 years, 4 months ago

CBSE > Class 11 > Chemistry

1 answers

Rajinder Saharan 4 years, 4 months ago

12 grams of carbon dioxide (molecular weight = 48) dissolved in 200 ml of water. The molarity would be (12/48) x (1000/200) which would become (0.25) x (5) = 1.25 molar.

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3×10ki power 8 /5×10ki power 9 How to solve this eqn..... My answer is wrong Please tell me

Posted by Nisha Gurjar 4 years, 4 months ago

CBSE > Class 11 > Chemistry