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With increase in size extent of overlapping decreases.... Due to decreases extent of overlapping, the species become more electron deficient. More Electron deficient species gain electron easily and so the order is:-) BBr3>BCl3>BF3

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At what temp., density of water is maximum and why

Posted by Rajat Solanki 7 years, 1 month ago

CBSE > Class 11 > Chemistry

4 answers

Rushali Ganesh Hiwarale 7 years, 1 month ago

The initial temp we give is Used to break the Hydrogen bonding in Ice and hence at 4 Degree all the hydrogen bonds have broken so water has max density at 4 degree after that density decreases

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Priya Dharshini ? 7 years, 1 month ago

When the ice melts to liquid water, the structure collapses and the density of the liquid increases. At temperatures well above freezing, the molecules move faster and get further apart. The density decreases as temperature increases. ... Thus, the density of water is a maximum at 4 °C......

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Rajat Solanki 7 years, 1 month ago

And reason ?

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Rushali Ganesh Hiwarale 7 years, 1 month ago

4 degree Celsius

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List two factors which effect ionisation energy

Posted by Muskan Sekho 7 years, 1 month ago

CBSE > Class 11 > Chemistry

1 answers

Harshdeep Kaur 7 years, 1 month ago

Ionization energy depend on.... Size- As the size increases I.E. decreases Nuclear charge--As nuclear charge increases I.E. increases

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CO2 is a gas but SiO2 is solid at room temperature. Why?

Posted by Muskan Sekho 7 years, 1 month ago

CBSE > Class 11 > Chemistry

1 answers

Aashir Arham ⚽?⚽ 7 years, 1 month ago

Co2 consits of induvidual molecule with one central carbon atom double bounded to 2 oxygen. Co2 is gas but SiO2 is in giant molecular stucture but Co2 is simple molecular structure.

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Write functional group of monocarboxlic acids

Posted by Muskan Sekho 7 years, 1 month ago

CBSE > Class 11 > Chemistry

1 answers

Talib Gazi 7 years, 1 month ago

CooH

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Write the IUPAC name and symbol of the element with atomic number 149?

Posted by Sanat Sahu 7 years, 1 month ago

CBSE > Class 11 > Chemistry

3 answers

Kriti Sharma 7 years, 1 month ago

Sanat this question came in my exam

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Akhil Sharma 7 years, 1 month ago

Its iupac name will be unquadennium

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Sanidhya Jadaun? 7 years, 1 month ago

Unquadennium ....symbol = Uqe

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Easy Chapter Of chemistry

Posted by Aviral Saxena 7 years, 1 month ago

CBSE > Class 11 > Chemistry

5 answers

Rushali Ganesh Hiwarale 7 years, 1 month ago

Organic chemistry and p Block plus Equilibrium kar lo Pass Toh ho hi gaonge

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Aviral Saxena 7 years, 1 month ago

How I Score passing marks

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Aviral Saxena 7 years, 1 month ago

But 1 day M ye sab Kyse finish kro

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Priya Dharshini ? 7 years, 1 month ago

Environmental chemistry,redox reactions,hydrogen,s block

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Muskan Khan 7 years, 1 month ago

Ch-1, redox, ch-3

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One mole of oxygen gas at STP is equal to

Posted by Mayank Kheriya 7 years, 1 month ago

CBSE > Class 11 > Chemistry

0 answers

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State the anomalous properties of first member of group 1 and group 2

Posted by Tushar Sisodia 7 years, 1 month ago

CBSE > Class 11 > Chemistry

1 answers

Avantika Tayal 7 years, 1 month ago

Li is hard,form covalent bond,it cannot hold large sized CO32- atoms and hence li2co3 is unstable to heat,lino3 decomposes to form oxides and no2 but other members form nitrides.Be does not react directly because of deposition of a protective oxide film over its surface so it is first converted into powderes form ,amphoteric in nature,it reacts with halogens in the form of beo.

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Calculate the wavelength and frequency of limiting line of lyman series

Posted by Vivek Kumar 7 years, 1 month ago

CBSE > Class 11 > Chemistry

1 answers

Gaurav Seth 7 years, 1 month ago

As said by Namrata, the limiting wavelength in the Lyman series can be calculated by using the Rydberg formula. The Rydberg formula is given as

For the Lyman series, n₁ = 1 and n₂ = 2,3....

The above formula can be further simplified as

1 / λ = (R_H/ hc) [(1/ n₁²) - (1/ n₂²)]

Therefore for the limiting wavelength, n₂ will be ∞, so ( 1 / n₂) will be zero. The Rydberg Formula will now be

1 / λ = (R_H/ hc) [(1/ n₁²)]

Now R_H has the value of 2.18X10^–18 J, h that is Planck's constant has the value of 6.63 X 10^-34 Js, c that is the speed of light has the value 3 X 10⁸ ms^-1 and n₁has the value 1. Substituting these values in the above relation and solving for λ, we get

λ = 9.12 X 10^-8 m.

So the limiting wavelength will be 9.12 X 10^-8 m.

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Calculate ph of mixture of 0.1M acitic acid and 0.1M Na acetate k=10^5

Posted by Yashita Alawat 7 years, 1 month ago

CBSE > Class 11 > Chemistry