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An adiabatic process is a thermodynamic process in which the system is thermally insulated from the surroundings and the heat released or absorbed by the system is zero.
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Rf values are always less than 1. An Rf value of 1 or too close to it means that the spot and the solvent front travel close together and is therefore unreliable. This happens when the eluting solvent is too polar for the sample.
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The formula of urea is NH2CONH2
Molar mass = 60.01 g/mol
Atomic mass of N = 14 and
Number of atoms = 2
That means, 14 {tex}\times{/tex} 2= 28g/mol of urea
MW urea = 60.1
%N = 100% x 28.0 g N / 60.1 g urea = 46.66 %N
Or
%N= 28/60{tex}\times{/tex}100= 46.66 % N
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The chemical formula and molar mass of calcium chloride are respectively CaCl2 and 111 g respectively. Thus, there are 6.022{tex}\times{/tex}1023 formula units in 111g of CaCl2. So,
number of formula units of CaCl2 in 111 g of CaCl2 = 6.022 {tex}\times{/tex}1023
number of formula units of CaCl2 in 1g of CaCl2 = {tex}\frac{(6.022\times1023)}{111}{/tex}
number of formula units in 222g of CaCl2 ={tex}\frac{(6.022\times1023\times222)}{111}{/tex}
= 12.044 {tex}\times{/tex} 1023
Now, each formula unit of CaCl2 contains one Ca2+ ion and two Cl- ions. Therefore
number of Ca2+ ions in one unit of CaCl2 = 1
number of Ca2+ ions in 12.044 {tex}\times{/tex} 1023 units of CaCl2 = 1 {tex}\times{/tex} 12.044 {tex}\times{/tex} 1022 = 1.2044 {tex}\times{/tex} 1024
Similarly
number of Cl- ions in one unit of CaCl2 = 2
number of Cl- ions in 12.044 {tex}\times{/tex} 1023 units of CaCl2 = 2 {tex}\times{/tex} 12.044 {tex}\times{/tex} 1023
= 2.4088 {tex}\times{/tex} 1024
Hence, there are 1.2044 {tex}\times{/tex} 1024 Ca2+ ions and 2.4088 {tex}\times{/tex} 1024 Cl- ions in 222 g of CaCl2.
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