CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Pythagoras was a great mathematician who modified the theirem which is given by baudhayan fro india . This theorem is also known as baudhayan Pythagoras theorem

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Rohan Gurjar 7 years, 3 months ago

Pythagoras is mathamathesion .He give theorem base square + perpendicular square= hypotenuse square

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5+-4y+8=0

Posted by Sagar Paliwal 7 years, 3 months ago

CBSE > Class 10 > Mathematics

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A girl of height 90cm is walking from a base of lamp at a speed of 1.2m/s. If the lamp is 3.6m above the ground, find the length of shadow after 4s.

Posted by Nachiket Tulankar 7 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Nachiket Tulankar 7 years, 3 months ago

From Triangles chapter.

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Vaibhav Yadav 7 years, 3 months ago

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Afifa Khan 7 years, 3 months ago

Which chapter?

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Chapter 1st of RS agraval question n. 8 solution of exercise 1A plz hurry up

Posted by Pankaj Chauhan 7 years, 3 months ago

CBSE > Class 10 > Mathematics

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What is a unique solution , coincident solution and parellel???

Posted by Radhika :) Mishra:} 7 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Adwaitha Nair 7 years, 3 months ago

Unique solution is a single solution is there for the quadratic equation and it intersects in graph . Coincident is that the graph is a line which cannot intersects and always coincides . Parallel is that the graph has two lines which is parallel to eachother

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Aditya Kumar Tiwary 7 years, 3 months ago

when we get a single solution of different variable than thisbis called as unique solution.

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Solution of 5th question of maths exercise 5.2

Posted by Shikayna Panday 7 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Pankaj Chauhan 7 years, 3 months ago

Now we find that the common difference d=13-7=6 , d=6 And first term A = 7 And , last term An = 205 By using formula we have An = a + (n -1) d = = 205 = 7 + (n -1) 6 = ( n -1 ) 6 = 205 - 7 = n - 1= 198/6 = n = 33 + 1 = 34 Ans Hence , 34 th term is 205 I hope this is the helpful for u ..........

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Sarthak Bhardwaj 7 years, 3 months ago

a=7,d=6,an=205 an=a+(n-1)×d 205=7+(n-1)×6 205=7+6n-6 205=1+6n 6n=205-1 6n=204 n=204÷6 n=34 My name is sarthak Bhardwaj

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Class 7 chapter -6 6.3 que no 2

Posted by Gurpreet Singh 7 years, 3 months ago

CBSE > Class 10 > Mathematics

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Write all the formulas of chapter 3 linear equations in two variables. Anyone please??

Posted by Radhika :) Mishra:} 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Shamsher Ali 7 years, 3 months ago

Graphical method substitution elimination method cross multiply method

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1/a+b+c = 1/a + 1/b + 1/ c

Posted by Disha Sharma 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Chanchal Dhiman 7 years, 3 months ago

1/a+b+c=1/a+1/b+1/c =>1/a+b+c -1/c=1/a+1/b =>[c-(a+b+c)] /c(a+b+c) =(b+a) /ab =>Cross multiplying (since a, b, c=0 and a+b+c=0) =>c(a+b+c) (b+a) = -ab(a+b) =>(a+b) (ca+cb+cc+ab) =0 =>(a+b) (ca+cc+cb+ab) =0 =>(a+b) (b+c) (c+a) = 0 ?

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In what form of decimals can irrational numbers be represented

Posted by Priyam Kumar 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Aachal Singh 7 years, 3 months ago

Non terminating and non repeating decimal

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Show how root 5 can be represent on number line

Posted by Anjali Raja 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

According to the Pythagoras theorem, we can conclude that {tex}{\left( {\sqrt 5 } \right)^2} = {\left( 2 \right)^2} + {\left( 1 \right)^2}{/tex} We need to draw a line segment AB of 1 unit on the number line. Then draw a straight line segment BC of 2 units. Then join the points C and A, to form a line segment BC. Then draw the arc ACD, to get the number {tex}\sqrt 5 {/tex} on the number line.

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The string of a kite is 100 m long and it makes an angle of 60degree with the horizontal.find the height of the kite assuming that there is no slack in the string

Posted by Raja Singh 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Nitin Kumar?Hr35 Vala?(Narnaul)? 7 years, 3 months ago

Draw a diagram of it By uaing cos 60 =base/hypotenuse Then put the value of cos 60. (1/2) Then 100/2 =50 So, the height is 50m

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1+2-3×4÷5

Posted by Priyansh Upadhyay 7 years, 3 months ago

CBSE > Class 10 > Mathematics

7 answers

Vibhanshu Yadav 7 years, 3 months ago

0.6

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Abhi Sodhi 7 years, 3 months ago

0.6

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Nitin Kumar?Hr35 Vala?(Narnaul)? 7 years, 3 months ago

2.4

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Tanya Gupta 7 years, 3 months ago

1Thank You

Ankit Singh 7 years, 3 months ago

3/5

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Barun Agrawal 7 years, 3 months ago

7/12

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Barun Agrawal 7 years, 3 months ago

7 12

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The nth term of an APis 3x+5 find its common difference.

Posted by Deepak Khatri 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

We are given, a_n = 3n + 5 which is nth term.
So, a₁= 3(1) + 5 = 8
and, a₂= 3(2) + 5 = 6 + 5 = 11
so common difference, d = a₂- a₁= 11 - 8 = 3

Therefore common difference is 3

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Divide 3xcube+xsquare+2x+5

Posted by Pravesh Panghal 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Mamta Bansal 5 years, 8 months ago

Answer

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Wah wah wah

Posted by Prasha Ttsvv Bbaga 7 years, 3 months ago

CBSE > Class 10 > Mathematics

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RD sharma solutions of ch 2

Posted by Palak Phogat 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Shikayna Panday 7 years, 3 months ago

All but how

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Ch8trignomatry

Posted by Gourav Chhabra 7 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Sreejith Sreejith 7 years, 3 months ago

Spelling : Trigonometry

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Gourav Chhabra 7 years, 3 months ago

Chapter -8

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How to made the table before ploting the graph in the chapter the pair of linear equations in two variables.

Posted by Sreejith Sreejith 7 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Sreejith Sreejith 7 years, 3 months ago

Plz explain the answer in brief

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Sreejith Sreejith 7 years, 3 months ago

Plz explain the answer in detailed steps

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Abhishek Varma 7 years, 3 months ago

For e.g: there is a equation 10x+y=5 Y=5-10x Substitute values for x. If x=1,y=-5 Hence form a table and plot the graph.

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Percatage of 7/8

Posted by Shaurya Singh 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Shiva Yadav Shiva Yadav 7 years, 3 months ago

87.5%

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In an AP the sum of 1st n term Sn=3n^2/2+5n/2 find 25th term

Posted by Keshav Agarwal 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

According to the question,we are given that,

{tex}S _ { n } = \frac { 3 n ^ { 2 } } { 2 } + \frac { 5 n } { 2 } = \frac { 3 n ^ { 2 } + 5 n } { 2 }{/tex}
{tex}\Rightarrow S _ { n - 1 } = \frac { 3 ( n - 1 ) ^ { 2 } + 5 ( n - 1 ) } { 2 }{/tex}

{tex}= \frac { 3 \left( n ^ { 2 } - 2 n + 1 \right) + 5 n - 5 } { 2 }{/tex}
{tex}= \frac { 3 n ^ { 2 } - 6 n + 3 + 5 n - 5 } { 2 }{/tex}
{tex}= \frac { 3 n ^ { 2 } - n - 2 } { 2 }{/tex}
Now,
n^th term = T_n=S_n-S_n-1={tex}= \frac { 3 n ^ { 2 } + 5 n } { 2 } - \frac { 3 n ^ { 2 } - n - 2 } { 2 } = \frac { 3 n ^ { 2 } + 5 n - 3 n ^ { 2 } + n + 2 } { 2 }{/tex}={tex}\frac{{6n + 2}}{2}{/tex}=3n+1
25^th term=T₂₅=3(25)+1=75+1=76.