CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

As AD = AF (tangents to the circle) similarly BD=BE AND CE=CF so let AD be x Then BD become 12-x and BE also become 12-x Then AF also becomes x and CF become 10-x and CE also 10-x Now, we will add 12-x+10-x and x = 22 So, AD =22 BE = 10 CF = 12

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What is the formula for mode

Posted by Kriti Verma 3 years, 6 months ago

CBSE > Class 10 > Mathematics

3 answers

Shally Deol 3 years, 6 months ago

Mode = l+(f1-f0/2f1- f0- f2)×h

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Satyajit Panda 3 years, 6 months ago

Most repeating number

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Kriti Verma 3 years, 6 months ago

Mode = l + (f1 - f0 / 2f1 - f0 - f2) ×h

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Middle term splitting of 9t²-6t+1

Posted by Anjali Bhartiya 3 years, 6 months ago

CBSE > Class 10 > Mathematics

5 answers

Tripti Garg 3 years, 6 months ago

3t-1 ,3t-1

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Riya Gandhi 3 years, 6 months ago

9t²-3t-3t+1 3t(3t-1)-1(3t-1) (3t-1) (3t-1)

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Aashin In 3 years, 6 months ago

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Vamsi Koyya 3 years, 6 months ago

T = -1/3,1/3

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Ananya Jha 3 years, 6 months ago

9t²-3t-3t+1

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AP 20,17,14,11 .....35th term

Posted by Shruti Singh 3 years, 6 months ago

CBSE > Class 10 > Mathematics

2 answers

Anushka Sinha 3 years, 6 months ago

a=20,d=17-20=-3,n=35 an=a+(n-1)×d a35=20+(35-1)×(-3) a35=20+34×(-3) a35=20-102 a35=-82 Hence 35th term is -82

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Riya Sinha 3 years, 6 months ago

a = 20, d = -3 •°• a35 = 20 +34 × (-3) = 20 -102 = -82

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Karan has 180 blue marbles and 150 red marbles. He wants to pack them into packets containing equal number of marbles of the same colour. What is the maximum number of marbles that each packet can hold?

Posted by Bhanwara Ram 3 years, 6 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If x-6 is a factor of x3+ax2+bx -b and a-b=7, find the value of a and b

Posted by Navyaa Sharmaa 3 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Priyanshi Tyagi 3 years, 6 months ago

x-6=0 x=6 Put x=6 in given equation x3+ax2 +bx-b=0 (6)3+a(6)2 +b(6)-b=0 18+12a+6b-b=0 6(3+2a+b-b)=0 3+2a+b-b=0------(1) a-b=7 (given) a=b+7-----(2) Put eq 2 in eq 1 3+2(b+7)+b-b=0 3+2b+14+b-b=0 17+2b=0 b=-17/2 Put value of b in eq 2 a-b=7 a-(-17/2)=7 a+17/2=7 a=7-17/2 a=14-17/2 a=-3/2

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For some integers m every even integers is of th form

Posted by Shubham Aggarwal 3 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Daksh Sharma 3 years, 6 months ago

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The sum of 5th and 9th terms of an A.P is 30 . If it's 25th terms is three times it's 8th terms find the A.P

Posted by Komal Kumari 3 years, 6 months ago

CBSE > Class 10 > Mathematics

2 answers

Piyush Mishra 3 years, 6 months ago

AP is 3,5,7,9....

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Riya Mahadik 3 years, 6 months ago

After solving we get : a=3 , d = 2. Therefore, AP is : 3,5,7,9.....

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A set of numbers consists of six 5's,seven 7's, eleven 9's, fourteen 12's,four 13's two 14's.Find the mode of this set of numbers.

Posted by Pawandeep Kaur 3 years, 6 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

'Sum of first n positive integers :- Sn = n(n+1)/2 ' Will it come in term 2 exam

Posted by Riya Sinha 3 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sahijdeep Kaur 3 years, 6 months ago

Yess it will

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6212 divide by 3

Posted by Kartikey Sharma 3 years, 6 months ago

CBSE > Class 10 > Mathematics

4 answers

Riya Gandhi 3 years, 6 months ago

2070.66667

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Neeharika Garg 3 years, 6 months ago

2070.666.....

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Vamsi Koyya 3 years, 6 months ago

207.6 bar

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Gurkirat Singh 3 years, 6 months ago

18636

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the sum of the 3rd and the 7th term of an A.P.is 6 and their product is 8 find the sum of first 16 term

Posted by Samiksha Choudhary 3 years, 6 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Solve: 2ax+2by=a+b 3x+4y=4

Posted by Shweta Halbarge 3 years, 6 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

What is the ratio of 4

Posted by Yash Dhomne 3 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Piyush Mishra 3 years, 6 months ago

1:3

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Two circles of different radii have three common tangents . Prove that the distance between their centres is equal to the sum of their radii

Posted by Rohit Chavan 3 years, 6 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Show that (a-b)², (a²+b²) , (a+b)² are in AP

Posted by Bhagya Sri 3 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Swati Suman 3 years, 6 months ago

For being in AP common difference of successive terms of an AP be equal (a^2+b^2)-(a-b)^2=(a+b)^2-(a^2+b^2) LHS = (a^2+b^2)-(a-b)^2 = a^2+b^2-a^2-b^2+2ab =2ab RHS = (a+b)^2-(a^2+b^2) =a^2+b^2+2ab-a^2-b^2 =2ab Therefore, LHS=RHS Hence, the common difference among successive terms is equal . So, the given terms are in AP.

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x-1/x+2+x+1/x-2=4x Solve for x

Posted by Poorvansh Dashore 3 years, 6 months ago

CBSE > Class 10 > Mathematics