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  • 0 answers
  • 1 answers

Muskan Sharma 3 years, 6 months ago

No real roots will be there as D<0 which means b²-4ac < 0, so D will be in negative.
  • 1 answers

Khushi Jakhwal 3 years, 6 months ago

Are?
  • 1 answers

Jashan Gill 3 years, 6 months ago

Yes
  • 0 answers
  • 0 answers
  • 5 answers

Mishra Queen 3 years, 6 months ago

3

Jasneet Smagh 3 years, 6 months ago

3

Kashish Sharma 3 years, 6 months ago

3

Somil Jain 3 years, 6 months ago

3

Mohamed Mahroos 3 years, 6 months ago

3
  • 3 answers

Affin J 3 years, 6 months ago

P =12 or 14

Affin J 3 years, 6 months ago

P = 12 or 10

Pratiyansh Saini 3 years, 6 months ago

6
  • 2 answers

Mohamed Mahroos 3 years, 6 months ago

By writing in note

Jashan Gill 3 years, 6 months ago

First clear and read the formula
  • 1 answers

Narayan Patel 3 years, 6 months ago

Quadratic equation
  • 1 answers

Singh Chatwal 3 years, 6 months ago

So?
  • 2 answers

Kalpana Singh 3 years, 6 months ago

ax²+bx+c=0

Megha Soni 3 years, 6 months ago

Ax square +bx+c=0
  • 0 answers
  • 1 answers
Volume of cuboid = 982 # # cm3 Volume of cube 23 = cm3 Let number of recast cubes be n. Volume of n cubes =Volume of cuboid n23 = 982 # # n ### 222 = 982 # # n 222 982 18 # # = = # # Hence, number of cubes recast is 18.
  • 2 answers

Rahul Pathak Gshhaha 3 years, 5 months ago

Ok

Komal Preet 3 years, 6 months ago

Thank u same to you .But also please concentrate on studies
  • 2 answers

Badal Chandravanshi 3 years, 5 months ago

Hi

Badal Chandravanshi 3 years, 5 months ago

Hii
  • 1 answers

Kumkum D 3 years, 6 months ago

Let the distance on angle of depression 45° be x And from 60° be y Then the distance travelled by the ship during the time of observations would be x-y Now, cot45°=x/150 1=x/150 x=150m And cot60°=y/150 1/√3=y/150 150/√3=y 50√3=y. {by rationalisation} So, x-y=150-50√3 =50(3-√3) m
  • 1 answers

Taish Ba 3 years, 6 months ago

BC =15√3

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