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Find the circumference of a circle whose area is 301.84 cm2

Posted by Omprakash Nayak 7 years, 1 month ago

1 answers

Hiru ? 7 years, 1 month ago

π(r)^2= 301.84...(given)...........put value of π and try to solve it, you will get r=9.8cm.......than using circumference= 2πr, u will get the final ans as 61.6cm

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Cos=0.6,show that (5sin-3tan)=0

Posted by Ashish Shukla 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Affu 😊 7 years, 1 month ago

Given- cos=0.6 Show that (5sin-3tan)=0 Now, 5sin-3[sin/cos]=0 (becoz =sin/cos) [5sin-3sin/cos] =0 Put the value of cos [5sin-3sin/0.6] =0 3sin-3sin __________ =0 0.6 =0/0.6 0=0 Lhs=rhs

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The angle of elevationof an aeroplane from a point on ground is 45degree .after a flight of 15 second the elevation changes to 30 degree .if the aeroplane is flying at a height of 3000 metres ,find the speed of the aeroplane .

Posted by Ujjawal Singh Rajput 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Hiru ? 7 years, 1 month ago

Using tan45 nd tan30 u can find the distance travelled by plane in 15s........in 15s it travelled 2190m so in 1s it will travell 2190/15=146m..........thus speed of aeroplane is 146m/s

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Two circle touches externally.The sum of their of their areas is 13πcm^ and the distance between their circles is 14cm.Determine thr radii of the circles.

Posted by Arjit Gupta 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Aditi Gupta 7 years, 1 month ago

7cm

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Trigono6Trigonometry

Posted by Geetha S Rashmi 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

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How many students who study in coaching?️

Posted by Rohit Sahani 7 years, 1 month ago

CBSE > Class 10 > Mathematics

4 answers

Rohit Sahani 7 years, 1 month ago

Sahi bole bhaii 1000%

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Rohit Sahani 7 years, 1 month ago

What 30 gupta

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Raunak _ Pandey ?? 7 years, 1 month ago

Coaching is a waste of time !!

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Aditi Gupta 7 years, 1 month ago

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what is eculid's devision lemma?

Posted by Uzzwal Upadhyay 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Raj Aryan 7 years, 1 month ago

The proven statement use to prove another statement is called Euclid's division lemma....

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Ashish Roy 7 years, 1 month ago

Hahaha

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(a^2+b^2)=

Posted by Apurva Singh 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Suraj Kumar Singh 7 years, 1 month ago

(a+b)^2-2ab

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what is graphical representation of the linear equation y-15=0

Posted by Sangeeta Patil 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Hfcjhj Gggh 7 years, 1 month ago

It will be a straight line parallel to x axis at a distant of 15 unit(positive) from origin.

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Hiru ? 7 years, 1 month ago

y = 15.....x variable is not present in equation

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If cos =tan

Posted by Jai Gupta 5 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Rohit Sahani 7 years, 1 month ago

So what ?????

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If secA +tanA=p ,then find the value of cosecA.(4 marks)

Posted by Sakshi Mishra 5 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

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Find the remainder when p (x)=2x2-x-6 is divided by (x-2)

Posted by Mohammed Mahshook 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Hiru ? 7 years, 1 month ago

p(x) is not clear to understand

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Factorise: m(m-1)-n(n-1).

Posted by Mohammed Mahshook 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Anjali Singh 7 years, 1 month ago

m(m-1) - n(n-1) m²-m-n²+n (m+n)(m-n)-m+n

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the equation x squared minus b x + 1 equal to zero does not possess real roots then which one of the following is correct options 1:B is greater than minus 2 2 and b is less than 2 2;2 second option B is greater then 2

Posted by Vishal Thakur 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Hiru ? 7 years, 1 month ago

If the equation has no real roots then the value of discriminent would be negative.....so "b" could not be positive.....thus option B(b>2) should not be correct.......may first option be correct

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Shivam Tomar 7 years, 1 month ago

Vishal thakur... U have not included capital B in the equation..... Can u write it again in better understanding way

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Oswaal book in maths . Introduction to trigonometry and trigonometric identities in that TOPIC -1 :Short answer types questions-|| ; Question 11 is not understand .pls help me.

Posted by Loyola Seba 7 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Divyansh Kumar 7 years, 1 month ago

We don't have the book. We can't even buy it specially for answering 1 question.

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Shivam Tomar 7 years, 1 month ago

Send question

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Harsh Virk 7 years, 1 month ago

What is the question

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t11-t18=2:3,find S5:S10

Posted by Aysha Nimra 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Shivam Tomar 7 years, 1 month ago

t11-t18 ...? Or t11:t8 ....check the questiin pls

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2 cubesof volume 64 cm3 are joined to end. find the surface area of the resulting cuboid

Posted by Utkarsh Srivastava 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Vaikash K. G 7 years, 1 month ago

Volume=64cmcube a3=64cm3 a=4cm L=4+4=8 B=4 H=4 TSA=2(lb+bh+hl) 2(8x4+4x4+4x8) 2(32+16+32) 2(80) 160 cm3

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If a=whole square root 15+4 square root 14 and b = whole square root 15- 4 square root, then find the value of a cube + b cube.

Posted by Dhananjay Pandey 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Shivam Tomar 7 years, 1 month ago

Pls write question again.....

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A metallic sphere of radius 4.2 cm is melted and recast into the shape of a cylinder of radius 6 cm. Find the height of the cylinder.

Posted by Joel Jolly 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Shivam Tomar 7 years, 1 month ago

In the 2nd line i have cancel pi from both side .....actually there is no spacing option in this app for next line so.. Dont confuse...... I have cancel pi in second line and then next remain equ.... I have written in this line... Difference it ok

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Shivam Tomar 7 years, 1 month ago

Take the vol of sphere= vol of cylinder 4/3 pi (r)³ = pi (r)²h 4/3 (r)³ = r² h Put Lhs r = 4.2 cm and rhs r = 6 cm Then you will find able to find h? And after putting r value..... h will remain and you will get ans 343/125 = 2.74cm

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Find the nature roots of quadratic equation

Posted by Sakshi Sharma 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Shivam Tomar 7 years, 1 month ago

D=b²-4ac .........D stand for discriminant # D>0 .....the two roots will be different and real # D= 0..... The two roots will be same # D< 0...... The two roots will be imaginary or say complex.... This is not in your syallbus. You will read this in 11 class

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Raghav Aggarwal 7 years, 1 month ago

b²-4ac

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Is there any news about board time table?

Posted by Disha Rathore 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

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Divid 243 in three part if one part is half of first par one third of second part one fourth of third part

Posted by Rajesh Sinha 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

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How to rationalise the cuberoot

Posted by Rahul Pandey 7 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Jaya Maji 7 years, 1 month ago

Then do n

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Sahitha?? Sharma 7 years, 1 month ago

7÷√3 =7÷√3×√3÷√3=7√3÷3

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Ananya P 7 years, 1 month ago

Easy

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The tangent at a point C of a circle and a diameter AB when extended intersect at P. if angle PCA =110 find angle CBA

Posted by Anchal Varshney 7 years, 1 month ago

CBSE > Class 10 > Mathematics

5 answers

Gurjar Naam ही भत्हैरा ??? 7 years, 1 month ago

Firstly angle PCA=90 because tangent make 90 degree angle where it touch the circle So angle CBA =45

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Nishant Mahipal 7 years, 1 month ago

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Satendra Singh Thakur 7 years, 1 month ago

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Anand Raj 7 years, 1 month ago

Sorry its 70

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Anand Raj 7 years, 1 month ago

170

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Solve the equation for x: x+2/x-2-(1-x)/x=17/x

Posted by Trusha Prajapati 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Annu Boora 7 years, 1 month ago

3 and 6

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In AP, if s6+s7=167 And s10 =235 then find the AP ,where sn denote the sum of its first n term

Posted by Kiran Yadav 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

S_n = {tex}\frac{n}{2}{/tex}[2a+(n-1)d]

Now, S₅+S₇=167
{tex}\Rightarrow{/tex} {tex}\frac{5}{2}{/tex}[2a+4d]+{tex}\frac{7}{2}{/tex}[2a+6d]=167
{tex}\Rightarrow{/tex} {tex}\frac{{5 \times 2}}{2}{/tex}[a+2d]+|{tex}\frac{{7 \times 2}}{2}{/tex}[a+3d]=167
{tex}\Rightarrow{/tex} 5a+10d+7a+21d=167
{tex}\Rightarrow{/tex} 12a+31d=167...(i)
Also, S₁₀=235
{tex}\Rightarrow{/tex} {tex}\frac{{10}}{2}{/tex}[2a+9d]=235
{tex}\Rightarrow{/tex} 5[2a+9d]=235
{tex}\Rightarrow{/tex} 10a+45d=235
{tex}\Rightarrow{/tex} 2a+9d=47...(ii)
Multiplying equation (ii) by 6, we get
12a+54d=282...(iii)
subtracting (i) from (iii), we get
23d = 115
{tex}\Rightarrow{/tex} d = 5
{tex}\Rightarrow{/tex} 2a+9(5)=47
{tex}\Rightarrow{/tex} 2a = 2
{tex}\Rightarrow{/tex} a = 1
First term = a = 1
Second term = a+d=1+5=6
Third term = a+2d=1+2(5)=11
Thus, the Ap is 1,6,11,...

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Find the value of P such that the quadratic equation (p-12)x²-2(p-12)x+2=0 has equal root

Posted by Trusha Prajapati 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Amitesh Vaishnav 7 years, 1 month ago

Since the equation has equal roots Therefore D=0 b^2-4ac=0 [2(p-12)]^2 -4*(p-12)(2)=0 4(p-12){(p-12)-2}=0 (p-12)(p-14)=0 p=12 or p=14

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1/(x-1)(x-2)+1/(x-2)(x-3)=2/3 X is not equal to 2&3

Posted by Kiran Yadav 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

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Given a= 7, a13= 35, find d and S13

Posted by Ritika Lahiri 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Ansh Verma 7 years, 1 month ago

we know a=7 so a(n)=a+(n-1)d a13=a+(13-1)d putting values 35=7+(13-1)d 35=7+12d So d=28\12 d=7\3 S13=13\2(a+l) =13\2(7+35) =13\2(42) =273 ans

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Sparsh Anand 7 years, 1 month ago

Hello mate!! a= 7 a13= 35 We know that, an= a+(n-1)d a13= 7+(13-1)d 35=7+12d 35-7= 12d 28= 12d Therefore, d= 28/12 d= 7/3 Sn= n/2(2a+(n-1)d) s13= 13/2(2X 7+(13-1)7/3 =13/2(14+12X7/3) = 13/2(14+28) = 13/2X 42 = 13X 21 = 273

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If aalpha and beeta are the zeros of the quadratic polynomial f(x)=x(x)+x-2, find the value of 1/aalpha-1/beeta

Posted by Jitendra Bhosale 7 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Tanishka Gautam 7 years, 1 month ago

If aalpha and beeta are zeroes.... Find the values of: (aalpha+beeta=-b/a). And. (aalpha×beeta= c/a) Then, 1/aaplha -1/beeta ka Lcm karo. Phir jo values jo aapne upper nikali hai use us me daal do

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Tarun Chauhan 7 years, 1 month ago

Bhdhdjdfb

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Akash Kumar 7 years, 1 month ago

I dont know

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