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  • 2 answers

Mahak Yadav 3 years, 4 months ago

CosQ =QR/PQ CosQ=4/5 Let QR=4k and PQ=5k By Pythagoras theorem PQ square= PR square +QR square (5k) square = PR square+ 4k square 9k square=PR square 3k = PR TanQ = PR/QR TanQ= 3k /4k TanQ = 3/4

👌Aditya 👌 👌Kumar👌 3 years, 4 months ago

CosQ = b/h = 4/5 TanQ = p/b = 3/4
  • 1 answers

Mahak Yadav 3 years, 4 months ago

2/k=3/9 Cross multiplication 18 = 3k k=18/3 k=9
  • 2 answers

Mahak Yadav 3 years, 4 months ago

1/165

Latha .M. 3 years, 4 months ago

1/60
  • 3 answers

Raj Patel 3 years, 4 months ago

2 4 6 8 10 12 14 16 18 20

Satyam Sinha 3 years, 4 months ago

The numbers which are divisible by 2.

Khushi 1 3 years, 4 months ago

2
  • 3 answers

Mahak Yadav 3 years, 4 months ago

x=35/2×3 x= 35/6 x= 5.833

Satyam Sinha 3 years, 4 months ago

x=35/3×2

Vivek Vivek 3 years, 4 months ago

x= 5.8333......
  • 4 answers

Satyam Sinha 3 years, 4 months ago

Rs aggarwal

Vaibhav Yadav 3 years, 4 months ago

Rd

.. .. 3 years, 4 months ago

Rs Or Rd

Vivek Vivek 3 years, 4 months ago

NCERT
  • 1 answers

Misbah Ur Rehman 3 years, 4 months ago

x=-1& y=3
  • 0 answers
  • 0 answers
  • 1 answers

Piyansh Gedam 3 years, 4 months ago

4+9x²-2y+12
  • 1 answers

Account Deleted 3 years, 4 months ago

Give answer fast
  • 0 answers
  • 0 answers
  • 0 answers
  • 1 answers

Vivek Vivek 3 years, 4 months ago

P/B
  • 0 answers
  • 1 answers

Anamika Bajpai 3 years, 4 months ago

Answer plz
  • 1 answers

Satyam Sinha 3 years, 4 months ago

Let √2 be a rational no. Then it can be written in the form of p/q,where p and q having a common factor other than 1 ,q is not = 0. A/Q
  • 4 answers

Khushi Sharma 2 years, 11 months ago

Pls can anybody tell me difference between asexual and sexual reproduction?

Vivek Vivek 3 years, 4 months ago

x= 9 and y= 5

Piyush ❤️ 3 years, 4 months ago

But kasa solve krka send kru

Khushi Sharma 2 years, 11 months ago

Pls anybody answer🙏
  • 1 answers

Himanshu Chauhan 3 years, 4 months ago

Given √3 + √5 To prove: √3 + √5 is an irrational number. Let us assume that√3 + √5 is a rational number. So it can be written in the form a/b √3 + √5 = a/b Here a and b are coprime numbers and b ≠ 0 Solving √3 + √5 = a/b On squaring both sides we get, (√3 + √5)² = (a/b)² √3² + √5² + 2(√5)(√3) = a²/b² 3 + 5 + 2√15 = a²/b² 8 + 2√15 = a²/b² 2√15 = a²/b² – 8 √15 = (a²- 8b²)/2b a, b are integers then (a²-8b²)/2b is a rational number. Then √15 is also a rational number. But this contradicts the fact that √15 is an irrational number. Our assumption is incorrect √3 + √5 is an irrational number. Hence, proved.
  • 1 answers

Rose Preet 3 years, 4 months ago

3x²+5x+2 3x²+3x+2x+2 3x(x+1) +2(x+1) (X+1)(3x+2) X+1is equal to 0 Then x is equal to -1 Here we can say that alpha is equal to -1 Similarly, If we take 3x +2 Beta is equal to x is eqal to -2/3 1/alpha+ 1/beta 1/-1 +1/-2/3 Is eqal to -5/3

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