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Ask QuestionPosted by Vinit Pandit????? 6 years, 11 months ago
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Posted by Kiran Yadav 6 years, 11 months ago
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Vinit Pandit????? 6 years, 11 months ago
. . 6 years, 11 months ago
Posted by Vinit Pandit????? 6 years, 11 months ago
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Devansh Kanthariya 6 years, 11 months ago
Posted by Anshika Pal???? 6 years, 11 months ago
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Vinit Pandit????? 6 years, 11 months ago
Posted by Riya Panwar 6 years, 11 months ago
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Anshika Pal???? 6 years, 11 months ago
Posted by Damanjeet Kaur 6 years, 4 months ago
- 1 answers
Sia ? 6 years, 4 months ago
we have to Solve the equation, {tex}\frac { 1 } { x + 4 } - \frac { 1 } { x - 7 } = \frac { 11 } { 30 } , x \neq - 4{/tex} ,{tex}7{/tex} for x.
Given equation, {tex}\frac { 1 } { x + 4 } - \frac { 1 } { x - 7 } = \frac { 11 } { 30 }{/tex}
or, {tex}\frac { x - 7 - x - 4 } { ( x + 4 ) ( x - 7 ) } = \frac { 11 } { 30 }{/tex}
or, {tex}( - 11 ) \times 30 = 11 ( x + 4 ) ( x - 7 ){/tex}
or, {tex}x ^ { 2 } - 3 x + 2 = 0{/tex}
or, {tex}x ^ { 2 } - 2 x - x + 2 = 0{/tex}
or, (x - 1)(x - 2 ) = 0
{tex}\therefore {/tex} x = 1, 2
Posted by Rajan Dewan 6 years, 11 months ago
- 3 answers
Sunidhi??? Chauhan 6 years, 11 months ago
Posted by Sahil Virk 6 years, 11 months ago
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Dipti Singh 6 years, 11 months ago
Posted by Abishay Narain 6 years, 11 months ago
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Posted by Abishay Narain 6 years, 11 months ago
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Posted by Ruval Parekh 6 years, 11 months ago
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Posted by Akash Mishra 6 years, 11 months ago
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Posted by Muskan Kumari 6 years, 11 months ago
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Posted by Avaneesh Sharma Mdjssv 6 years, 4 months ago
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Sia ? 6 years, 4 months ago
Let the ratio be x
{tex}\therefore{/tex} Radius 'r' = 5x
Height 'h' = 12x
{tex}\therefore{/tex} Slant height = {tex}\sqrt { r ^ { 2 } + h ^ { 2 } } = \sqrt { ( 5 x ) ^ { 2 } + ( 12 x ) ^ { 2 } }{/tex} =13x
Now, volume = 314 m3 [given]
{tex}\Rightarrow {/tex} {tex}\frac { 1 } { 3 } \pi r ^ { 2 } h{/tex} = 314
{tex}\Rightarrow {/tex} {tex}\frac { 1 } { 3 }{/tex} {tex}\times{/tex} 3.14 {tex}\times{/tex} 25 x2 {tex}\times{/tex} 12x = 314
{tex}\Rightarrow {/tex} x3 = {tex}\frac { 314 \times 3 } { 3.14 \times 25 \times 12 }{/tex}
{tex}\Rightarrow {/tex} x = 1
{tex}\therefore{/tex} Slant height = 13x = 13m
Radius = 5x = 5m
Posted by Sonakshi Bhandari 6 years, 11 months ago
- 4 answers
Tanya Zanzad 6 years, 11 months ago
Posted by Avaneesh Sharma Mdjssv 6 years, 11 months ago
- 1 answers
Yogita Ingle 6 years, 11 months ago
Volume of hemisphere = 2425.5 cu cm.
Volume of hemisphere = 2/3πr³
2425.5 = 2/3 × 22/7× r³
r³ = (2425.5 × 21)/44
r³ = 50935.5/44
r³ = 1157.625
r = 10.5 cm
Now,
Curved Surface Area of hemisphere = 2πr²
= 2×22/7×10.5×10.5
= 693 sq cm
CSA of hemisphere is 693 sq cm.
Posted by Nikita Sharma 6 years, 11 months ago
- 3 answers
Yogita Ingle 6 years, 11 months ago
Let AB be the wall and AC be the ladder
We have,
AC = 15 m and ∠BAC = 60°
Cos 60° = AB/AC
⇒ 1/2 = AB/15
⇒ AB = 15/2 m

. . 6 years, 11 months ago
Posted by Nikita Sharma 6 years, 11 months ago
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Anushka Jugran ? 6 years, 11 months ago
Posted by Dhananjay Pandey 6 years, 11 months ago
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Anushka Jugran ? 6 years, 11 months ago
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. . 6 years, 11 months ago
Posted by Harsh Vardhan 6 years, 11 months ago
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Posted by Riya ? 6 years, 11 months ago
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Rahul Raj 6 years, 11 months ago
Rahul Raj 6 years, 11 months ago
Usha Yadav 6 years, 11 months ago
Posted by Deepak Thakur 5 years, 8 months ago
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Yogita Ingle 6 years, 11 months ago
3 - 4 + 7 × 87 + 80
= 3 - 4 + 609 + 80
= - 1 + 609 + 80
= 608 + 80
= 688
Posted by Prince Garg 6 years, 11 months ago
- 1 answers
Mohit Singh 6 years, 11 months ago

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