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  • 1 answers

Ankit Class 2 years, 1 month ago

tanA = y/x , from here get value of sinA and cosA and put in first eq
  • 1 answers

Ankit Class 2 years, 1 month ago

a^5 +b^5 +5a^4b +5ab^4 +10a^3b^2 +10a^2b^3.
  • 2 answers

Shailja Singh 2 years, 1 month ago

Question no. 7 exercise 12.2 mein nahi hai there have only 5 question

Srushti Diddi 2 years, 1 month ago

Chapter 8 exiercise 8.4 solution
  • 1 answers

Vivek Prajapati 2 years, 1 month ago

Question likho
  • 2 answers

Kinjal Singh 2 years, 1 month ago

The prime factors of 149 are 1 and 149 because 149 is a prime number

Reena Salvi 2 years, 1 month ago

1 and 149 itself
  • 4 answers

Divyansh Jain 2 years, 1 month ago

Question is incomplete

Lite Likam Tamin 2 years, 1 month ago

No you're wrong 2tan = 2 cotton 😑🙄

Ruchika Kumari 2 years, 1 month ago

Hi

Uchiha Pranik 2 years, 1 month ago

Tan=sin
  • 3 answers

Moni Pal 2 years, 1 month ago

Sin 0 =0

Saurav Kumar 2 years, 1 month ago

P/h

Ruchika Kumari 2 years, 1 month ago

Hiii
  • 5 answers

Vivek Prajapati 2 years, 1 month ago

sin/1-cos am I right or not

Divyansh Jain 2 years, 1 month ago

cosec A + cot A

Reena Salvi 2 years, 1 month ago

Cosec A = 2

Abhay Agrahari 2 years, 1 month ago

1

Ruchika Kumari 2 years, 1 month ago

Hiiuuuuiiiii
  • 2 answers

Lite Likam Tamin 2 years, 1 month ago

4 and 5 😂

Ruchika Kumari 2 years, 1 month ago

Hiii
  • 1 answers

Lite Likam Tamin 2 years, 1 month ago

1353 is the smallest number that make 543291 a perfect square
  • 3 answers

Reena Salvi 2 years, 1 month ago

x= -9 and y= 3

Iniyavan Saravanan 2 years, 1 month ago

Y=-3 or Y=9

Iniyavan Saravanan 2 years, 1 month ago

X=-3 or x=9
  • 3 answers

Ankit Class 2 years, 1 month ago

4A= 16 then A= 4 °

Ankit Class 2 years, 1 month ago

Cos(74-A)=cos (58+3A)

Ankit Class 2 years, 1 month ago

Cos ( 90-16-A) = cos (58 +3A)
  • 1 answers

Omya Aryan 2 years, 1 month ago

8 is a rational number.
¾
  • 2 answers

Kinjal Singh 2 years, 1 month ago

3/4=0.75

Kavya Pawar 2 years, 1 month ago

0.75
  • 5 answers

Siddharth Singh 2 years, 1 month ago

(a-b)²

Jasleen Kaur 2 years, 1 month ago

(a-b) 2

Tanishka Gupta 2 years, 1 month ago

(a-b)^2

Rohan Kumar 2 years, 1 month ago

a-b

Rohan Kumar 2 years, 1 month ago

(a+b)² formula
  • 2 answers

Nilesh Mahankuda 2 years, 1 month ago

Go through Google

Rohan Kumar 2 years, 1 month ago

Nothing
  • 5 answers

Nilesh Mahankuda 2 years, 1 month ago

37

Siddharth Singh 2 years, 1 month ago

37

Rohan Kumar 2 years, 1 month ago

37

Nikin Jart 2 years, 1 month ago

37 my

Krishna Bhatt 2 years, 1 month ago

37
  • 3 answers

Aryan Verma 2 years, 1 month ago

I wish me help you (m1x2+m2x1/m1+m2, m1y2+m2y1/m1+m2)

Deepa Goswami 2 years, 1 month ago

hello 🤗 kaise ho

Kirtimaan Kumar 2 years, 1 month ago

Coordinates of point P are {(mx' +nx)/2 , (my' +ny) /2} Where point p between 2 points A and B with coordinates (x, y) and (x',y') respectively and 'm' and 'n' are the ratio between them. Example-AP:BP = m:n A•————•——•B P Hope this helps🙌
  • 5 answers

Chinki 🦋👈🏻 2 years, 1 month ago

16 is correct answer....

Vansh Singh 2 years, 1 month ago

16

Khushi Kushwaha 2 years, 1 month ago

-10is the answer according to your question

Prajwal K 2 years, 1 month ago

Wrong bro

Shivam Kumar 2 years, 1 month ago

5is the right answer
  • 3 answers

Divyansh Jain 2 years, 1 month ago

3

Student Student 2 years, 1 month ago

No solution because lines are parallel A1/A2=B1/B2≠C1/C2

Student Student 2 years, 1 month ago

No solution
  • 0 answers
  • 1 answers

Kajal Verma 2 years, 1 month ago

It's not the part of the ap
  • 3 answers

Harman Sandhu 2 years, 1 month ago

√5 is an irrational number

Rohit Yadav 2 years, 1 month ago

Let us assume that contrary that √5 is rational number √5=a by b √5b=a square the both sides 5bsquare= asquare ASquare is divided by 5

Saksham Singh 2 years, 1 month ago

I think it should be irrational instead of rational
  • 1 answers

Abhishek Yadav Yt 2 years, 1 month ago

Discriminant, D=4(ac+bd) 2 −4(a 2 +b 2 )(c 2 +d 2 ) D=4[(ac+bd) 2 −(a 2 +b 2 )(c 2 +d 2 )] D=4[a 2 c 2 +b 2 d 2 +2acbd−a 2 c 2 −a 2 d 2 −b 2 c 2 −b 2 d 2 ] D=4[2acbd−a 2 d 2 −b 2 c 2 ] D=−4[a 2 d 2 +b 2 c 2 −2adbc] D=−4(ad−bc) 2 We have, ad  =bc Therefore, ad−bc  =0 (ad−bc) 2 >0 −4(ad−bc) 2 <0 D<0 Hence, the given equation has no real roots.

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