CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

The positive integers which are multiple of 8 are:
8,16,24,................up to 15 terms
It forms an arithmetic series.
Now first term a = 8, common difference d = 8, number of terms n = 15
Now sum of first 15 terms of AP = (n/2) × {2a + (n-1) × d}
= (15/2)× {2× 8 + (15-1)× 8}
= (15/2)× (16 + 14× 8)
= (15/2) × (16 + 112)
= (15 × 128)/2
= 15 × 64 (when 64 and 2 is divided by 2) = 960
So sum of first 15 terms which are multiple of 8 = 960

1Thank You

Honey ??? 6 years, 10 months ago

960

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ANSWER

A right circular cone is divided into three parts by trisecting its height by two planes drawn parallel to the base.Show that the volume of the three portions starting from top are in the ratio 1:7:19.

Posted by Loguss Sancheti 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Divit Advik 6 years, 10 months ago

I will send you in your email.if you can provide

1Thank You

Ram Kushwah 6 years, 10 months ago

Sir where is the figure please paste figure too.

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Divit Advik 6 years, 10 months ago

The height of a Cone, 3h is trisected by2 planes // to the base of the cone at equal distances. So, the cone is divided into a smaller cone & 2 frustums of the cone. The height of each piece is ‘h’ unit Since, right triangle ABG ~ tri ACF ~ tri ADE ( by AAA similarity criterion. So corresponding sides are to be proportional. So, AB/AC = h/2h = 1/2 = BG/CF = r/2r AB/AD = h/3h = 1/3 = BG/ DE = r/ 3r Now, we find the volume of each piece.. a smaller cone & 2 frustums Volume of Cone ABG = 1/3 pi r² h ………….(1) Volume of middle frustum = 1/3 pi ( r² + 4r² + 2r² ) h = 1/3 pi 7r² h ……………….…….(2) Volume of next frustum = 1/3 pi ( 4r² + 9r² + 6r²) h = 1/3 pi 19r² h …………………….(3) Now, by finding the ratio of (1),(2)&(3) we get, (1/3pi r² h) : (1/3 pi 7r² h) : (1/3 pi 19r² h) = 1:7:19

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Prove that (a+b)2

Posted by Naman Pandey 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Divit Advik 6 years, 10 months ago

(a+b)² = a²+2ab+b² (a+b)(a+b) = a²+2ab+b² a(a+b)+b(a+b) = a²+2ab+b² a²+ab+ab+b² = a²+2ab+b² a²+2ab+b² = a²+2ab+b²

0Thank You

Lol No 6 years, 10 months ago

Question incomplete h

2Thank You

ANSWER

Pythagoras theoram proof

Posted by Uday Kiran 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Sumit Gupta 6 years, 10 months ago

AC* = AB* + BA* THAT'S PROOF

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Rakesh Rajput 6 years, 10 months ago

See from ncert book unit 6 theorm 6.9

2Thank You

Priyanshi Mishra 6 years, 10 months ago

See from ncert

6Thank You

ANSWER

Find the quadratic equation,if x=root5+root5+root 5......infinity and x is natural number

Posted by Sarika Manger 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Shri Charan Dental Clinic 6 years, 10 months ago

leave first root 5 then take all other root 5 as xthen write x=root 5 +x . Then if yousquare this equatio you can get the answer

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ANSWER

TanA÷1-cotA+cotA÷1-tanA=1 +secA×cosecA

Posted by Vedansh Kumar 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

We have,
{tex}\mathrm { LHS } = \frac { \tan A } { 1 - \cot A } + \frac { \cot A } { 1 - \tan A }{/tex}
{tex}\Rightarrow \quad \mathrm { LHS } = \frac { \tan A } { 1 - \frac { 1 } { \tan A } } + \frac { \frac { 1 } { \tan A } } { 1 - \tan A }{/tex}
{tex}\Rightarrow \quad \text { LHS } = \frac { \tan A } { \frac { \tan A -1 } { \tan A } } + \frac { 1 } { \tan A ( 1 - \tan A ) }{/tex}
{tex}\Rightarrow \quad \mathrm { LHS } = \frac { \tan ^ { 2 } A } { \tan A - 1 } + \frac { 1 } { \tan A ( 1 - \tan A ) }{/tex}
{tex}\Rightarrow \quad \text { LHS } = \frac { \tan ^ { 2 } A } { \tan A - 1 } - \frac { 1 } { \tan A ( \tan A - 1 ) }{/tex}
{tex}\Rightarrow \quad \mathrm { LHS } = \frac { \tan ^ { 3 } A - 1 } { \tan A ( \tan A - 1 ) }{/tex} [Taking LCM]
{tex}\Rightarrow \quad \mathrm { LHS } = \frac { ( \tan A - 1 ) \left( \tan ^ { 2 } A + \tan A + 1 \right) } { \tan A ( \tan A - 1 ) }{/tex} [{tex}\because{/tex} a³ - b³ = ( a - b )(a² + ab + b²)]
{tex}\Rightarrow \quad \mathrm { LHS } = \frac { \tan ^ { 2 } A + \tan A + 1 } { \tan A }{/tex}
{tex}\Rightarrow \quad \mathrm { LHS } = \frac { \tan ^ { 2 } A } { \tan A } + \frac { \tan A } { \tan A } + \frac { 1 } { \tan A }{/tex}
{tex}\Rightarrow{/tex} LHS = tanA + 1 + cotA [ since (1/tanA) =cotA ].
= (1 + tanA + cotA)
{tex}\therefore \quad \frac { \tan A } { 1 - \cot A } + \frac { \cot A } { 1 - \tan A }{/tex} = 1 + tanA + cotA ...........(1)

Now, 1 + tanA + cotA
= 1 + {tex}\frac { \sin A } { \cos A } + \frac { \cos A } { \sin A }{/tex}
= 1 + {tex}\frac { \sin ^ { 2 } A + \cos ^ { 2 } A } { \sin A \cos A }{/tex} = 1 + {tex}\frac { 1 } { \sin A \cos A }{/tex} [{tex}\because{/tex}Sin²A + Cos² A = 1 ]
= 1 + cosecAsecA
So, 1 + tanA + cotA = 1+ cosecAsecA.......(2)

From (1) and (2), we obtain
{tex}\frac { \tan A } { 1 - \cot A } + \frac { \cot A } { 1 - \tan A }{/tex} = 1 + tanA + cotA = 1 + cosecAsecA

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ANSWER

If three numbers are in Ap.And the sum of their squares is 260.Find the numbers.

Posted by Anjali Shukla 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Shashank Mishra 6 years, 10 months ago

Tera question Sahi hai6

3Thank You

ANSWER

Aap math ko sirf unke hi liye ku bnatey ho kya hum hindi medium waley kuch ni h jo aap math ko hindi m nhi solve karte

Posted by Aakansha Shirivastav 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Ayush Tomar 6 years, 10 months ago

??math ko Hindi me bhi solve kar dege par hamare phone me hindi me alphabet nahi ate

1Thank You

ANSWER

Ex13.2 quesn6

Posted by Robin Bhagat 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Shivam Tripathi 6 years, 10 months ago

Volume of CYL + volume of cyl ,,,,,,,,,,,πR^2h + πr^2h ,,,,,,,, 3.14×12×12×220 + 3.14×8×8×60 ===== 99475.2 + 12057.6 =====111532.8 ,,,,,,,,,,, 111532.8×8 ====892262.4 cm^3 ,,,,,,,,892.2624 km ^3 ??

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ANSWER

Ex13.26

Posted by Robin Bhagat 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Ex 13.26

Posted by Robin Bhagat 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

The 8th term of ap is 35 and 102th term of ap is 317 find ap

Posted by Misthi Rajput 6 years, 10 months ago

CBSE > Class 10 > Mathematics

4 answers

Rakshitha Raju? 6 years, 10 months ago

That is a+7d=35

0Thank You

Rakshitha Raju? 6 years, 10 months ago

Ya Ya... Sry I have done mistakes

0Thank You

Rahul Raj?? 6 years, 10 months ago

A+7d=35+a+101d=317 solve this

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Rakshitha Raju? 6 years, 10 months ago

a+9d=35 a+101d=317 Solve it n u wl find the value of a and d

1Thank You

ANSWER

solve rhis question☺4+2

Posted by Anjali Kumari 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

@ Aashu 6 years, 10 months ago

6.......???????

2Thank You

Amisha Sharma ? 6 years, 10 months ago

Of course 6

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ANSWER

What is the HCF of prime number and composite number

Posted by Abhinav Sharma 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Rakshitha Raju? 6 years, 10 months ago

Either the answers is 2 or 4??

0Thank You

Sneha Singh 6 years, 10 months ago

Write full question abhinav ji

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ANSWER

Find the value of K for which the point A (K+1,2K) ,B(3K,2K+3)&C(5K-1,5K) are collinear

Posted by Aayushi Gurjar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Rakshitha Raju? 6 years, 10 months ago

Use area of triangle formula.. U will get the answer

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ANSWER

The dimensions of a solid iron cuboid are 4.4mX2.6mX1.0m.It is melted and recast into a hollow cylindrical pipe of 30cm inner radius and thickness 5 cm. Find the length of the pipe.

Posted by Rakshitha Raju? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Rakshitha Raju? 6 years, 10 months ago

0Thank You

Shashank Mishra 6 years, 10 months ago

Pehle volume of cuboid nikalkar use Cm me badal liyo phir volume of cylinder Aur Usme Khali h ki value nahi rakhni h ki jo value aaeyigi would h = 25.4222

1Thank You

ANSWER

Har bar exam mea ane wala question

Posted by Nikhil Sahu 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Meghana Meghana 6 years, 10 months ago

google cbse tute

1Thank You

ANSWER

Hamesha ane wala question

Posted by Nikhil Sahu 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Ankit Raj 6 years, 10 months ago

Theorem 1 or 3 of circle.

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ANSWER

The value of cos^2A=

Posted by Geetanand Yadav 6 years, 10 months ago

CBSE > Class 10 > Mathematics

4 answers

Meghana Meghana 6 years, 10 months ago

1-sin^2A

0Thank You

Sreenivas Huddar 6 years, 10 months ago

or Subtract Sin^2A from both sides to get Cos^2A!

1Thank You

Sreenivas Huddar 6 years, 10 months ago

Since Sin^2A+Cos^2A=1 , Therefore, transpose Sin^2A to the RHS and hence you get your answer...

1Thank You

Sreenivas Huddar 6 years, 10 months ago

Cos^2A=1-Sin^2A

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ANSWER

what real root

Posted by Shivam Yadav 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Farhat Shaikh Shaikh 6 years, 10 months ago

When d=0it exit real root

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Sreenivas Huddar 6 years, 10 months ago

i.e., real nos.

1Thank You

Sreenivas Huddar 6 years, 10 months ago

Real roots are roots that are real!

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ANSWER

Obtain all the zeroes of the polynomial x^4-5x^3+2x^2+10x-8 if the zeroes are √2 and -√2

Posted by Angel Jacob 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Riya Pal 6 years, 10 months ago

The other zeroes are 1 and 4.....☺️☺️

1Thank You

Honey ??? 6 years, 10 months ago

4 and1

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ANSWER

Find the third vertex of the triangle ABC.if two of its vertices are at A(-3,1)&B(0,2)& the mid points of BC is at D(3/2,-1/2).

Posted by Ashish Batham 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Honey ??? 6 years, 10 months ago

3,-3

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We have 6 subjects if we get 70+ in 5 only then did the result will include 6 or 5

Posted by Ayush Tomar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Sreenivas Huddar 6 years, 10 months ago

Otherwise only 5

0Thank You

Lol No 6 years, 10 months ago

No, the 6th one would only be displayed on in the marksheet...it won't be counted...

1Thank You

Sreenivas Huddar 6 years, 10 months ago

If all 6 are there for board exam, then the marksheet will include all 6

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ANSWER

How do we find the median clss in median

Posted by Kavita Bharti 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Niharika Singh 6 years, 10 months ago

Median class is that whose cumilative freq. Is just greater than n/2. Where n=sigma fi

0Thank You

Ayush Tomar 6 years, 10 months ago

Divide no. Of rows by 2 Ex if you have 7 rows 7/2=3.5 Median class =4th row If you have 6 row median class =3

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Geetanand Yadav 6 years, 10 months ago

Which have high c.f.from my side

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ANSWER

If secA+tanA=p show that secA-tanA=1/p hence find the values of sinA and cosA

Posted by Madhura Kaware 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Chaithanya Sreedharan 6 years, 10 months ago

Sec A + Tan A =p -equation 1 We know that Sec^2 A - Tan^2 A = 1 (Sec A -Tan A)(Sec A+ Tan A)=1[a^2 -b^2 =(a+b)(a-b)] From equation 1 (Sec A - Tan A)(p) = 1 Sec A - Tan A=1÷p -equation 2 Adding equations 1 and 2 Sec A - Tan A +Sec A+ Tan A=(1+p^2)/p 2 Sec A =(1+p^2)/p Sec A=(1+p^2)/2p Now you can easily find the value of sin and cos

1Thank You

Immortal 2K17009 6 years, 10 months ago

Answer, SecA+tanA=p --------------eq1 Now, Sec^2A-tan^2A=1. (a^2-b^2) (SecA+tanA)(secA-tanA)=1 (a+b)(a-b) p(secA-tanA)=1. (using eq1) secA-tanA=1/p PROVED

2Thank You

Honey ??? 6 years, 10 months ago

Shift tan to rhs and sq. on both sides and find value of tan in trms of p and put the values in a triangle and then find the t ratios.

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ANSWER

If the area of the triangle formed by joining the point A(x,y),b(3,2),c(-2,4) is 10 square units show that 2x+5y+4=0

Posted by Guddi Mathur 6 years, 10 months ago

CBSE > Class 10 > Mathematics