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  • 4 answers

Anup Raj 6 years, 10 months ago

Yes

Anup Raj 6 years, 10 months ago

Yez

Anushka S 6 years, 10 months ago

Yes

Nitin Kumar? 6 years, 10 months ago

Yess
  • 2 answers

Simran Kaur 6 years, 10 months ago

A7=a+6d ==== a + 6(4)=4 ===== a+ 24=4 ======== a= -20

Chetna ? 6 years, 10 months ago

-20
  • 2 answers

Atharva Dixit 6 years, 10 months ago

H²=B²+P²

Nitin Kumar? 6 years, 10 months ago

H^2=P^2 +B^2
2-5
  • 2 answers

Mehakdeep Kaur 6 years, 10 months ago

-3

Niyati Gupta 6 years, 10 months ago

-3
  • 1 answers

Ujjwal Gautam 6 years, 10 months ago

n is an odd no. n=4q+1 and n=4q+3 n^2-1=(4q+1)^2-1. And. n^2-1=(4q+3)^2-1 =16q^2+8q+1-1. =16q^2+24q+9-1 =8(2q^2+q) =16q^2+24q+8 =8m. =8(2q^2+3q+1) =8m
  • 1 answers

Sia ? 6 years, 6 months ago

Let Salim's present age be x years and his daughter's age be y years.
Two years ago,
Salim's age = (x - 2) years
Daughter's age = (y - 2) years
As per given condition
Two years ago, Salim was thrice as old as his daughter .
 x - 2 = 3(y - 2)
x - 2 = 3y - 6
{tex}\Rightarrow{/tex} x - 3y = -4 .........(i)
Six years hence,
Salim's age = (x + 6) years
Daughter's age = (y + 6) years
As per second condition
Six years later, he will be four years older than twice her age.
x + 6 = 2(y + 6) + 4
x + 6 = 2y + 12 + 4
{tex}\Rightarrow{/tex} x - 2y = 10 ...........(ii)
Subtracting (i) from (ii), we have
x - 2y - x  + 3y =10 - ( -4)
y = 14
Put y = 14 in (i)
{tex}\Rightarrow{/tex} x - 3(14) = -4
{tex}\Rightarrow{/tex}  x - 42 = - 4
{tex}\Rightarrow{/tex} x = 38
Therefore, the present age of Salim is 38 years and that of his daughter is 14 years.

  • 1 answers

Gautãm . 6 years, 10 months ago

It is flow of electrons
  • 3 answers

Puja Sahoo? 6 years, 10 months ago

1/3pie h(R^2+r^2+Rr)
HAan paii kdi padh lya kro

Sw Kkk 6 years, 10 months ago

Textbook khola kro alsi logo ?????????????
  • 2 answers

Puja Sahoo? 6 years, 10 months ago

He's ryt... ncert is the base......

Sumedh Dabir 6 years, 10 months ago

Do only ncert textbook for this exam...dont even look towards oswaal s chand all in one rd sharma...80%-90% comes from ncert...and rest u can solve by own bcoz base concepts become clear in ncert...???
  • 0 answers
  • 1 answers

Sia ? 6 years, 6 months ago

Check exam pattern here : <a href="https://mycbseguide.com/cbse-syllabus.html">https://mycbseguide.com/cbse-syllabus.html</a>

  • 2 answers

Niyati Gupta 6 years, 10 months ago

Su mit ye kesa Q hai

Gautam Prajapati 6 years, 10 months ago

2x+4
  • 1 answers

Nikhil Thomas 6 years, 10 months ago

cos^2A + cos^2A x cot^2A = cos^2A (1 + cot^2A) = cos^2A x cosec^2A ( since cosec^2A -cot^2A=1) =cos^2A/sin^2A =cot^2A
  • 3 answers

Tanya Zanzad 6 years, 10 months ago

First four cjapters are impprtant as they comparises of 20 marks

@ __R Rajput? 6 years, 10 months ago

Mensuration

Adarsh Kumbhar 6 years, 10 months ago

Everything is important
  • 2 answers

Swetanshu Kumar 6 years, 10 months ago

3x^2+5x-2 3x^2+6x-x-2 3x(x+2)-1(x+2) (x+2) (3x-1)=0 x= -2 or 1/3 sum = -b/a sum = -5/3

Charu Sharma 6 years, 10 months ago

-5/3
  • 3 answers

Sarthak Paliwal 6 years, 10 months ago

an=a+(n-1)d 109=4+5d-5 105+5=5n n=110÷5 =22

Sahil Kumar 6 years, 10 months ago

22th term

Bhavana Ramanathan 6 years, 10 months ago

22nd term
  • 2 answers

Tina6 Gupta 6 years, 10 months ago

But there are some chapters of geometry that chapters may I do only ncert or not

Honey ? 6 years, 10 months ago

For getting 70+ there is no point of view of study , just study all
  • 1 answers

Vaishali Chandnani 6 years, 10 months ago

Oswaal sample papers Super 20

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