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Ask QuestionPosted by Yash Sharma 6 years, 10 months ago
- 3 answers
Gaurav Seth 6 years, 10 months ago
R= 28cm
central angle (theta)= 45
area of sector=theta/360*pi*r*r
=45/360*22/7*28*28
308cm²
Posted by Uzzwal Upadhyay 6 years, 10 months ago
- 1 answers
Posted by Aditya Sharma Sarswat 6 years, 10 months ago
- 1 answers
Ramesh Singh 6 years, 10 months ago
Posted by Yadava Krishnan 6 years, 10 months ago
- 1 answers
Gaurav Seth 6 years, 10 months ago
If possible,let √p be a rational number.
also a and b is rational.
then,√p = a/b
on squaring both sides,we get,
(√p)²= a²/b²
→p = a²/b²
→b² = a²/p [p divides a² so,p divides a]
Let a= pr for some integer r
→b² = (pr)²/p
→b² = p²r²/p
→b² = pr²
→r² = b²/p [p divides b² so, p divides b]
Thus p is a common factor of a and b.
But this is a contradiction, since a and b have no common factor.
This contradiction arises by assuming √p a rational number.
Hence,√p is irrational.
Posted by Swarnima Dhabre 6 years, 10 months ago
- 3 answers
Esha Pal 6 years, 10 months ago
Posted by Satish Kumar 6 years, 10 months ago
- 2 answers
Posted by Akanksha Dutta 6 years, 10 months ago
- 2 answers
Posted by Khan Fardin 6 years, 10 months ago
- 5 answers
Jyoti Laddha 6 years, 10 months ago
Khan Fardin 6 years, 10 months ago
Posted by Skyadavskyadav Skyadavskyadav 6 years, 10 months ago
- 2 answers
Posted by Ruby Mathuria 6 years, 10 months ago
- 2 answers
Posted by Shivani Rawat 6 years, 10 months ago
- 0 answers
Posted by Priya Pardeshi 6 years, 10 months ago
- 2 answers
Posted by Selma Ussan 6 years, 10 months ago
- 1 answers
Kirti Dhillon 6 years, 10 months ago
Posted by Ritik Chauhan 6 years, 10 months ago
- 0 answers
Posted by Saswat Kumar 6 years, 10 months ago
- 2 answers
Posted by Shivani Rawat 6 years, 10 months ago
- 4 answers
Posted by Yogesh Sharma 6 years, 10 months ago
- 2 answers
Yogita Ingle 6 years, 10 months ago
Sum of the areas of two squares = 468 m2
Let a and b be the sides of the two squares.
⇒a2 + b2 = 468…(1)
Also given that, the difference of their perimeters = 24m
⇒4a - 4b = 24
⇒a - b = 6
⇒a = b + 6…(2)
We need to find the sides of the two squares.
Substituting the value of a from equation (2) in equation (1), we have,
(b + 6)2 + b2 = 468
⇒b2 + 62 + 2 × b × 6 + b2 = 468
⇒2b2 + 36 + 12b = 468
⇒2b2 + 36 + 12b - 468 = 0
⇒2b2 + 12b - 432 = 0
⇒b2 + 6b - 216 = 0
⇒b2 + 18b - 12b - 216 = 0
⇒b(b + 18) - 12(b + 18) = 0
⇒(b + 18)(b - 12) = 0
⇒b + 18 = 0 or b - 12 = 0
⇒b = -18 = 0 or b = 12
Side cannot be negative and hence b = 12 m.
Therefore, a = b + 6 = 12 + 6 = 18 m.
Posted by Akshum Sharma 6 years, 10 months ago
- 0 answers
Posted by Subham Sarma 6 years, 10 months ago
- 3 answers
Chetna ? 6 years, 10 months ago
Chetna ? 6 years, 10 months ago
Posted by Subham Sarma 6 years, 10 months ago
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Sannidhya Tyagi 6 years, 10 months ago
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- 1 answers
Posted by Manish Semlawat 6 years, 10 months ago
- 5 answers
Nitin Dadhich 6 years, 10 months ago
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- 4 answers
Abhay Modi 6 years, 10 months ago

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#Miss_Raagini ???? 6 years, 10 months ago
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