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Ask QuestionPosted by Adiii Agrawal 6 years, 10 months ago
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Posted by Vishal Vishwakarma 6 years, 4 months ago
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Sia ? 6 years, 4 months ago
We have,
AC = CE, BD = DE
And, AP = BP = 14 cm
{tex}\therefore{/tex} Perimeter of {tex}\Delta{/tex}PCD = PC + CD+ PD
{tex}\Rightarrow{/tex} Perimeter of {tex}\Delta{/tex}PCD = PC + (CE + ED) + PD
= (PC + CE) + (ED + PD)
= (PC + AC) + (BD + PD)
= PA + PB
= 14 + 14
= 28
{tex}\therefore{/tex} Perimeter of {tex}\triangle{/tex}PCD = 28 cm.
Posted by Raj Senjaliya 6 years, 4 months ago
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Sia ? 6 years, 4 months ago
According to the question,we are given that,
Volume of brass = 2.2 dm3 = 2200 cm3
Diameter of cylindrical wire = 0.25 cm
Therefore, radius of wire = {tex}\frac { 0.25 } { 2 }{/tex} cm
By the given condition ,we have,
Volume of cylindrical wire = Volume of Brass
{tex}\Rightarrow \quad \pi r ^ { 2 } h = 2200{/tex}
{tex}\Rightarrow \quad \frac { 22 } { 7 } \times \left( \frac { 0.25 } { 2 } \right) ^ { 2 } \times h = 2200{/tex}
{tex}\Rightarrow \quad h = \frac { 2200 \times 7 \times 2 \times 2 } { 22 \times 0.25 \times 0.25 }{/tex}
{tex}\Rightarrow{/tex} h = 44800 cm = 448 metres
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Sia ? 6 years, 4 months ago
{tex}\frac { x } { y } = \tan 45 ^ { \circ } = 1{/tex}
{tex}\Rightarrow {/tex} x = y
Now in big triangle
tan 60o = {tex}\frac {x+7}x{/tex}
√3 = {tex}\frac {x+7}x {/tex}
{tex}x(√3-1) = 7{/tex}
So height of the tower
{tex}x=\frac{\gamma}{1.73-1}=9.58{/tex}
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Sia ? 6 years, 4 months ago
Let us assume, to the contrary, that √p is rational.
So, we can find co-prime integers a and b(b ≠ 0)
{tex}\begin{array}{l}\sqrt p=\frac ab\\\end{array}{/tex}
{tex}a = b _ { \sqrt { P } }{/tex}
on squaring both sides we get
a2 = pb2 ...... (1)
so a2 is divisible by p
hence a is divisible by p ....... (2)
So, we can write a = pc for some integer c.
Squaring both the sides we get
a2 = p2 c2 ....
⇒ pb2 = p2 c2 ....[From (1)]
⇒ b2 = pc2
⇒ b2 is divisible by p
⇒ b is divisible by p ....... (3)
From (2) and (3) we conclude that p divides both a and b.
∴ a and b have at least p as a common factor.
But this contradicts the fact that a and b are co-prime. (As per our assumption)
This contradiction arises because we have assumed that √p is rational.
∴ √p is irrational.
Posted by Mahi ✌?? 6 years, 10 months ago
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Ram Kushwah 6 years, 10 months ago
Let the angles are a-d,a and a+d
then a-d +a a+d=180
3a=180
a=60
Also
a-d=1/2(a+d)
2a-2d=a+d
a=3d ,d=a/3=60/3=20
So the angles are 40,60 and 80
Posted by Sonal Kumawat 6 years, 10 months ago
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Chirag Mantri 6 years, 9 months ago
1Thank You