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  • 1 answers

Puja Sahoo? 6 years, 9 months ago

Complete yur question
  • 3 answers

Gaurav Seth 6 years, 9 months ago

Sol:

Given:   In an equilateral triangle ΔABC. The side BC is trisected at D such that BD = (1/3) BC.

To prove:  9AD2  = 7AB

Construction:  Draw AE ⊥ BC.

Proof :

In a ΔABC and ΔACE

AB = AC ( Given)

AE = AE ( common)

∠AEB = ∠AEC = 90°

∴ ΔABC ≅ ΔACE ( For RHS criterion)

BE = EC (By C.P.C.T)

BE = EC = BC / 2

In a right angled triangle ADE

AD2 = AE2 + DE2 ---------(1)

In a right angled triangle ABE

AB2 = AE2 + BE2 ---------(2)

From equ (1) and (2) we obtain

⇒ AD2  - AB2 =  DE- BE.

⇒ AD2  - AB2 = (BE – BD)- BE.

⇒ AD2  - AB2 = (BC / 2 – BC/3)– (BC/2)

⇒ AD2  - AB2 = ((3BC – 2BC)/6)– (BC/2)

⇒ AD2  - AB2 = BC/ 36 – BC/ 4 ( In a equilateral triangle ΔABC, AB = BC = CA)

⇒ AD= AB2 + AB/ 36 – AB/ 4

⇒ AD= (36AB2 + AB2– 9AB2) / 36

⇒ AD= (28AB2) / 36

⇒ AD= (7AB2) / 9

9AD= 7AB.

Nishita Jaisalmeria 6 years, 9 months ago

Ncert mai diya hai

Puja Sahoo? 6 years, 9 months ago

Ncert ka question hai, yu can get the solution in this app
  • 1 answers

Samyukta ... 6 years, 9 months ago

U tube mai ek channel hai Fastest Education name se...usmai hain videos aisi dheer saari...check them out!
  • 3 answers

Pranit Somkuwar 6 years, 9 months ago

Given, T1 = 213 = a. T2 = 205. Then, d = T2 - T1. d = 205 - 213. d = - 8. Now, Tn = a + (n - 1) × d. 37 = 213 + (n - 1) × (-8). 37 = 213 - 8n + 8. 37 = 221 - 8n. 8n = 221 - 37. 8n = 264. n = 184/8. n = 23. Hence the total no. of terms in the A.P are 23. therefore the no. middle term will be 12. Then, T12 = a + (12 - 1) × d. = a + 11d. = 213 + 11(-8). = 213 - 88. T12 = 125.

Hariom Sharma 6 years, 9 months ago

Take out first no of terms do it's half that tern

Puja Sahoo? 6 years, 9 months ago

125 which is 12th term of ap
  • 2 answers

Gaurav Seth 6 years, 9 months ago

Given, a circle inscribed in triangle ABC, such that the circle touches the sides of the triangle 

Tangents drawn to a circle from an external point are equal.

Afrin Hussain 6 years, 9 months ago

8
  • 1 answers

Mona Sharma ? 6 years, 9 months ago

Euclid div lemma is a proven statement used to prove a given statement or problem but euclid div algorithm is a defined series of steps used to compute HCF of given integers. Hope would help. ?
  • 1 answers

Puja Sahoo? 6 years, 9 months ago

x sq. + 2x - 3.....
  • 2 answers

Sahil Rajput 6 years, 9 months ago

6.5 que 15

Puja Sahoo? 6 years, 9 months ago

What's your question........?
  • 0 answers
  • 7 answers

Pragati Jadav 6 years, 9 months ago

Ap= √2,√18,√50, √98 it can also be writtenin the form Ap=√2,3√2,5√2,7√2...... A=√2. D=2√2. Now, a of 18= a+( n-1 )×d. √2+17×2√2. = √2+34√2. =35√2 answer.?

Ansh Kumar 6 years, 9 months ago

Ap is in form /2, 3/2, 5/2 ........ where / means root and difference d = a2-a1 =3/2-/2 = 2/2 a=/2 d=2/2 a18= a+17d = /2 + 17×2/2 = /2 + 34/2 =35/2 = /2450

Ram Kushwah 6 years, 9 months ago

The AP can be written as:

√2 ,3 √2 ,5 √2 ,7 √2 ...

a= √2  and d=2 √2

a18= √2 +17*2 √2

=(1+34) √2

=35 √2 ={tex}\sqrt 2450{/tex}

 

Affu 😊 6 years, 9 months ago

35√2

Aditya Mandal 6 years, 9 months ago

A=root 2 D=2 root2 N=18 Therefore applying a+(n-1)d ANSWER IS= 35root2

Puja Sahoo? 6 years, 9 months ago

35 root 2.....

Rohit Sreeram 6 years, 9 months ago

sqrt 2450
  • 1 answers

Isha Kapoor 6 years, 9 months ago

U just see the register on which u have practiced maths
  • 2 answers

Puja Sahoo? 6 years, 9 months ago

Hcf=13 and x=3, y=-2

Rohit Sreeram 6 years, 9 months ago

x=3, y= -2
  • 6 answers

Shikhar Singh 6 years, 9 months ago

128 is the correct answer.

Sahil Singh 6 years, 9 months ago

Thanks

Crazy Kills Tv 6 years, 9 months ago

an = a + (n-1)d a is 105 D is 7 and an = 994 994 = 105 + (n-1)7 889÷ 7 = n-1 127 =n-1 128 = n

?#Hr_76# ? 6 years, 9 months ago

Refer to ncert ch-5 A.P

Puja Sahoo? 6 years, 9 months ago

128

Sahil Singh 6 years, 9 months ago

Ans fast.......
  • 3 answers

Poonam Kadian 6 years, 9 months ago

solve this complete

Shikhar Singh 6 years, 9 months ago

The x=8 and y=3. Take x+y as v and x-y as u solve and you will get the answer.

Rohit Sreeram 6 years, 9 months ago

x=8, y=3
  • 2 answers

Rohit Sreeram 6 years, 9 months ago

-5.5

Meet Agarwal 6 years, 9 months ago

-5.5
  • 2 answers

Heart ? Hacker 6 years, 9 months ago

Bakwas

#Miss_Raagini ???? 6 years, 9 months ago

a+b
  • 3 answers

Garima Choudhary 6 years, 9 months ago

Rohit plzz tell its ans briefly

Rohit Sreeram 6 years, 9 months ago

it has 2 or more than 2 prime factors

Heart ? Hacker 6 years, 9 months ago

Out of knowledge
  • 2 answers

Shikhar Singh 6 years, 9 months ago

This pair of equation don't have any solution.

Meet Agarwal 6 years, 9 months ago

x=3448
  • 0 answers
  • 2 answers

#Miss_Raagini ???? 6 years, 9 months ago

Ya

#Miss_Raagini ???? 6 years, 9 months ago

X^2 - 3x - m(m+3) = 0 => x^2 + mx - (m+3)x- m(m+3) = 0 => x(x+m) - (m+3)(x+m) = 0 => (x+m) (x-m-3) = 0 x = - m and m+3 Roots are - m and m+3 ??
  • 1 answers

#Miss_Raagini ???? 6 years, 9 months ago

x2+x-p(p+1)=0 x2+(p+1)x-px-p(p+1)=0 x(x+p+1) -p(x+p+1)=0 (x+p+1)(x-p)=0 x=-p-1, p hope it will help u ??
  • 2 answers

Praveen Basera 6 years, 9 months ago

The answer of this question is too long.How I can send u

Meet Agarwal 6 years, 9 months ago

Bhai its to long how i send u
  • 1 answers

#Miss_Raagini ???? 6 years, 9 months ago

LHS = (sinθ - cosθ + 1)/(sinθ + cosθ - 1) dividing by cosθ both Numerator and denominator = (sinθ/cosθ - cosθ/cosθ + 1/cosθ)/(sinθ/cosθ + cosθ/cosθ - 1/cosθ) = (tanθ + secθ - 1)/(tanθ - secθ + 1) Multiply (tanθ - secθ) with both Numerator and denominator = (tanθ + secθ - 1)(tanθ - secθ)/(tanθ - secθ + 1)(tanθ - secθ) = {(tan²θ - sec²θ) - (tanθ - secθ)}/(tanθ - secθ + 1)(tanθ - secθ) = (-1 - tanθ + secθ)/(tanθ - secθ + 1)(tanθ - secθ) [ ∵ sec²x - tan²x = 1 ] = -1/(tanθ - secθ) = 1/(secθ - tanθ) = RHS Hope it helps archana ?
  • 0 answers
  • 3 answers

Prachi Maithil 6 years, 9 months ago

Probability: how likely something is to happen Formula to find probability = favourable outcomes /total outcomes... Probability is can't be negative.....
Favorable outcomes/total putcomes

#Miss_Raagini ???? 6 years, 9 months ago

Fav. outcomes/total outcomes
  • 1 answers

#Miss_Raagini ???? 6 years, 9 months ago

(P -12)x² +2( P -12) x + 2 =0 have two real and equal roots so, D = b² -4ac =0 here, b = 2( P -12) a = (P -12) c = 2 now, D = {2(P -12)}² -4.2(P -12) =0 4{ (P -12)² -2( P -12) } =0 (P -12)² -2(P -12)=0 (P -12){ P -12 -2} = 0 (P -12)( P -14) =0 P = 12, 14 hence value of P = 12,14

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