CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Given,LHS=√tanAtanB+tanAcotB/sinAsecB-sin²B/cos²B

=√tanAtan(90-A)+tanAcot(90-A)/sinAsec(90-A)-sin²(90-A)/cos²A

=√tanAcotA+tanAtanA/sinAcosecA-cos²A/cos²A

=√1+tan²A/1-1

=√tan²A

=tanA

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Shivam Tripathi 6 years, 9 months ago

U r new tenthian maths he.........u

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Heart ? Hacker 6 years, 9 months ago

Paper ho gya ab dimag kharab mat kar

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When will be the marking scheme of class 10 2019 will come.?

Posted by Ayush Johari 6 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

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if a^2 + b^2 + c^2 = 2 (a+2b +2c ) -9 find a+b+c

Posted by Bhavya Singh 6 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

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If alpha and beta are the zeroes of 2*x^2+5*x_10, then the value of alpha and beta is

Posted by Madhav Jadhav 6 years, 9 months ago

CBSE > Class 10 > Mathematics

3 answers

Bhavya Singh 6 years, 9 months ago

roots will be -5+ 105^2 / 4 and -5 - 105^2 / 4

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Ansh Sharma 6 years, 9 months ago

Oh... Thanks sanjana good answer...

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Chetan Chetan 6 years, 9 months ago

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If sin A--3/4 calculate sec A

Posted by Durgesh Sen 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

👉👉Tripti Pal👈👈 6 years, 9 months ago

Maths exam is over bro

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find the zeros of the polynomial x2+1/6x-2

Posted by Harmandeep Warring 6 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

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Find the zeros of the quadratic polynomial 3x2-2 and verify the relationship between the zeros and the coefficients

Posted by Harisree Jojith 6 years, 9 months ago

CBSE > Class 10 > Mathematics

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What is mean by pythagorean

Posted by Digvijay Dane 6 years, 9 months ago

CBSE > Class 10 > Mathematics

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find the largest no which divides 615 and 963 leaving the remainder 6 in each case

Posted by Taj Ameena 6 years, 9 months ago

CBSE > Class 10 > Mathematics

3 answers

Yogita Ingle 6 years, 9 months ago

To find the largest number which divides 615 and 963 leaving remainder 6 in each case i.e. HCF.
Consider HCF be x.
In order to make 615 and 963 completely divisible by x, we need to deduct the remainder 6 from both the cases.
609 = 3 x 3 x 29
957= 3 x 11 x 29
⇒ x = 3 x 29 = 87
∴ largest number which divides 615 and 963 leaving remainder 6 in each case is 87.

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👉👉Tripti Pal👈👈 6 years, 9 months ago

Maths exam is over bro now next is hindi see the date sheet

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Anushka Jugran ✌️ 6 years, 9 months ago

87...

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If a,b are zeroes of x²-4x+1,then 1/a+1/b -ab is

Posted by Sakshi ..... 6 years, 9 months ago

CBSE > Class 10 > Mathematics

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Surface area volumes.... exercise 15.4 last sum ... can anybody solve it and send

Posted by K Sai Uttej 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Bhavya Singh 6 years, 9 months ago

yr it is given in this app only

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Use Euclids division algorithm to find HCF 135and225

Posted by Ashish S 6 years, 9 months ago

CBSE > Class 10 > Mathematics

3 answers

Yogita Ingle 6 years, 9 months ago

135 and 225 Since 225 > 135,
we apply the division lemma to 225 and 135 to obtain
225 = 135 × 1 + 90
Since remainder 90 ≠ 0, we apply the division lemma to 135 and 90 to obtain
135 = 90 × 1 + 45
We consider the new divisor 90 and new remainder 45, and apply the division lemma to obtain
90 = 2 × 45 + 0
Since the remainder is zero, the process stops.
Since the divisor at this stage is 45,
Therefore, the HCF of 135 and 225 is 45.

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Anushka Jugran ✌️ 6 years, 9 months ago

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Honey ??? 6 years, 9 months ago

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A boy standing on a horizontal plane finds a bird flying at a distance of 100m from him at an elevation of 30°. A girl standing on the roof of a 20m high building, finds the elevation of the same bird to be 45°. The boy and the girl are on the opposite sides of the bird . Find the distance of the bird from the girl

Posted by Pulkit Sharma 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 6 years, 9 months ago

Let O be the position of the bird, B be the position of the boy, G be the position of the girl and FG be the building at which the girl is standing.

BO= 100m , FG= 20m

In ∆OLB,

= sin30°OL =50m

OM = OL-ML = OL-FG = 50-20 = 30m

In ∆OMG,

Thus, the distance of the bird from the girl is 42.3 m.

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In quadrilateral ABCD P,Q,R and S are mid points prove the diagonal is trisected

Posted by Yoganshu Tripathi 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Shireen Gupta 6 years, 9 months ago

Given ABCD is a parallelogram Hence AB || CD ⇒ AE || FC Also AB = CD (Opposite sides of parallelogram ABCD) ⇒ AE = FC (Since E and F are midpoints of AB and CD) In quadrilateral AECF, one pair of opposite sides are equal and parallel. ∴ AECF is a parallelogram. ⇒ AF || EC (Since opposite sides of a parallelogram are parallel) In ΔDPC, F is the midpoint of DC and FQ || CP Hence Q is the midpoint of DQ by converse of midpoint theorem. ⇒ DQ = PQ → (1) Similarly, in ΔAQB, E is the midpoint of AB and EP || AQ Hence P is the midpoint of DQ by converse of midpoint theorem. ⇒ BP = PQ → (2) From equations (1) and (2), we get BP = PQ = DQ Hence, the line segments AF and EC trisect the diagonal BD of parallelogram ABCD.

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5x+6y=11

Posted by Dr. Dineshramane 5 years, 9 months ago

CBSE > Class 10 > Mathematics