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13.1 prashnawali ka chodta Kishan

Posted by Lokesh Meena ❤️ 9 months, 3 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Sankalp Dinesh 9 months, 3 weeks ago

What is the question bro??

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If alpha and beta are zeroes of x²-x-1 , find 1/alpha + 1/beta

Posted by Kajal Sengar 9 months, 3 weeks ago

CBSE > Class 10 > Mathematics

2 answers

Sankalp Dinesh 9 months, 3 weeks ago

We know that, alpha + beta = -b/a alpha x beta = c/a Therefore, 1/alpha + 1/beta = beta + alpha/alpha x beta = -(-1)/1/-1/1 = 1/-1 = -1/1 So, -1 is the answer.

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B Praveen 9 months, 3 weeks ago

Geiub

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(x+2)^3=2x(x^2-1)

Posted by Abhi Bishnoi 9 months, 3 weeks ago

CBSE > Class 10 > Mathematics

1 answers

I Am Helper 9 months, 3 weeks ago

Expand the left-hand side: [(x+2)^3 = x^3 + 3 \cdot x^2 \cdot 2 + 3 \cdot x \cdot 2^2 + 2^3] [= x^3 + 6x^2 + 12x + 8]Expand the right-hand side: [2x(x^2 - 1) = 2x \cdot x^2 - 2x \cdot 1] [= 2x^3 - 2x]Set the expanded forms equal: [x^3 + 6x^2 + 12x + 8 = 2x^3 - 2x]Move all terms to one side to form a polynomial equation: [x^3 + 6x^2 + 12x + 8 - 2x^3 + 2x = 0] [ - x^3 + 6x^2 + 14x + 8 = 0]Simplify the equation: [x^3 - 6x^2 - 14x - 8 = 0]Solve the cubic equation (x^3 - 6x^2 - 14x - 8 = 0):

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If 3825 = 3 x × 5 y × 17z then the value of x+y-2z is?

Posted by Harman Kaur 9 months, 3 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Rakesh Kumar 9 months, 3 weeks ago

3x is x and y is 5y and z is 17z

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If 2 tan A = 3 , then the value of

Posted by Bikram Kumar Sarkar 9 months, 3 weeks ago

CBSE > Class 10 > Mathematics

2 answers

Yuvraj Shinde 9 months, 2 weeks ago

2x+y=7 4x-3y+1=0

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I Am Helper 9 months, 3 weeks ago

Given that

$2 \tan A = 3$ , we want to find the value of

$\sin A$ and

$\cos A$ . 1. **Express

$\tan A$ in terms of a simpler fraction**:

$\tan A = \frac{3}{2}$ 2. **Use the Pythagorean identity to find

$\sin A$ and

$\cos A$ **: We know that:

$\sin^2 A + \cos^2 A = 1$ and

$\tan A = \frac{\sin A}{\cos A}$ Since

$\tan A = \frac{3}{2}$ , we can set:

$\sin A = 3k \quad \text{and} \quad \cos A = 2k$ where

$k$ is a common factor. 3. **Use the Pythagorean identity** to find

$k$ :

$\sin^2 A + \cos^2 A = 1$ Substitute

$\sin A$ and

$\cos A$ :

$(3k)^2 + (2k)^2 = 1$ Simplify the equation:

$9k^2 + 4k^2 = 1$

$13k^2 = 1$ Solve for

$k$ :

$k^2 = \frac{1}{13}$

$k = \frac{1}{\sqrt{13}}$ 4. **Find

$\sin A$ and

$\cos A$ ** using

$k$ :

$\sin A = 3k = 3 \times \frac{1}{\sqrt{13}} = \frac{3}{\sqrt{13}} = \frac{3 \sqrt{13}}{13}$

$\cos A = 2k = 2 \times \frac{1}{\sqrt{13}} = \frac{2}{\sqrt{13}} = \frac{2 \sqrt{13}}{13}$ Thus, the values of

$\sin A$ and

$\cos A$ are:

$\sin A = \frac{3 \sqrt{13}}{13}$

$\cos A = \frac{2 \sqrt{13}}{13}$

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For what value of k,x^ -4x + k touches x- axis

Posted by Trupti R 9 months, 3 weeks ago

CBSE > Class 10 > Mathematics

0 answers

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A and B are the friend and their age differ by 2 years as father D is twins as old as a and b is twins as old as his sister the age of D and C differ by 40 years find the age of a and d

Posted by Khushi Yadav 9 months, 3 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Khushi Yadav 9 months, 3 weeks ago

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for what values of nth are the end terms of two AP'S : 63,65, 67...And 3,10,17... equal?

Posted by Srushti Biradar 9 months, 3 weeks ago

CBSE > Class 10 > Mathematics

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Prove that roots 7-8 is an irrational number

Posted by Ku.Krishna Yadav 9 months, 3 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Ku.Krishna Yadav 9 months, 3 weeks ago

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Posted by Malvika Singh 9 months, 3 weeks ago

CBSE > Class 10 > Mathematics

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If ab×ba = 57a

Posted by Beeraiah Bee 9 months, 3 weeks ago

CBSE > Class 10 > Mathematics

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Posted by Mannat Dadwal 9 months, 3 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Aryan Garg 9 months, 3 weeks ago

The given expression can be factored as: 13×17×19×23 + 13×23 = 13×(17×19×23 + 23) Since 17, 19, and 23 are all prime numbers, the factor (17×19×23 + 23) is a composite number. Therefore, the entire expression is also a composite number.

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If 6x=secA and 6/x=tanA, find the value of 9(x²-1/x²)

Posted by Rakshith Hs 9 months, 4 weeks ago

CBSE > Class 10 > Mathematics

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Find HCF X LCM for the numbers 100 and 150.

Posted by Sweety R 9 months, 4 weeks ago

CBSE > Class 10 > Mathematics

1 answers

H H 9 months, 4 weeks ago

HCF 50 LCM 300

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ax²+by+c=?

Posted by Aachal 🤍 9 months, 4 weeks ago

CBSE > Class 10 > Mathematics

2 answers

Rakshith Hs 9 months, 3 weeks ago

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Punit Patodi 9 months, 3 weeks ago

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x² - x - 23

Posted by Vidhi Gupta 9 months, 4 weeks ago

CBSE > Class 10 > Mathematics

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Bcb

Posted by Shreeya Nayak 9 months, 4 weeks ago

CBSE > Class 10 > Mathematics

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5 pencil and 7 pens together cost 50 whereas 7 pencil and 5 pen together cost 46.find the cost of one pencil and that of one pen.

Posted by Ashish Ashish 9 months, 4 weeks ago

CBSE > Class 10 > Mathematics

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H H 9 months, 3 weeks ago

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Lavanya throws a ball upwards, from a rooftop, which is 20 m above from ground. It will reach a maximum height and then fall back to the ground. The height of the ball from the ground at time t is h , which is given by h=-4t2+16t+20 . (i)What is the height reached by the ball after 1 second? (II)What is the maximum height reached by the ball (iii) How long will the ball take to hit the ground? (iv) What are the two possible times to reach the ball at the same height of 32 m? (v) Where is the ball after 5 seconds ?

Posted by Nivritee Pal 9 months, 4 weeks ago

CBSE > Class 10 > Mathematics

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X2 + 45x-99

Posted by Golu Kumar 9 months, 4 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Kritika Gupta 9 months, 3 weeks ago

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Find the lcm and hcf of 448,1008,168 by fundamental theorem

Posted by Gouri Nandana 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Naman Kumar Lakra 9 months, 3 weeks ago

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If 10 a equal to 3 by 4 then sin a cos a equal to 12 by 25

Posted by Abhinav Kumar 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Rakshith Hs 9 months, 3 weeks ago

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A motor boat speed in still water is 16 km per hour , takes 2 hours more to go 60 km upstream than to return to the same spot. Find the speed of the stream

Posted by Yashika Sain 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhinav Kumar 9 months, 3 weeks ago

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If ∆ABC~∆QRP, area of ∆ABC/area of∆QRP=9/4. AB=18cm and BC=15cm, then find the length of PR

Posted by Kirti Rana 10 months ago

CBSE > Class 10 > Mathematics

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If z=0.064, find the value of {1/z}^1/3

Posted by Zuha Yasmin 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Zuha Yasmin 10 months ago

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If α and βare the zeros of the quadratic polynomial f(t)= t2-4t+3, find the value of α4β3 +α3β4 .

Posted by Diya Debbarma 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Aryan Garg 9 months, 3 weeks ago

To find the value of α^4β^3 + α^3β^4, we first need to find the sum and product of the roots of the quadratic polynomial f(t) = t^2 - 4t + 3. The sum of the roots (α + β) = -(-4) = 4 The product of the roots (αβ) = 3 Now, we can use these values to find the desired expression: α^4β^3 + α^3β^4 = α^3β^3(α + β) = α^3β^3 * 4 (since α + β = 4) = 4 * (αβ)^3 = 4 * 3^3 = 4 * 27 = 108 Therefore, the value of α^4β^3 + α^3β^4 is 108.

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Find the degree of the following polynomials of t⁸-3t⁷+2t⁵-6t²/t²

Posted by Faiza Asad 10 months ago

CBSE > Class 10 > Mathematics

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Students of a class are made to stand in rows. If 4 students are extra in a row. there would be two rows less. If 4 students are less in a row there would be 4 more rows. Find the number of students in class.

Posted by Durgesh Kavate 10 months ago

CBSE > Class 10 > Mathematics

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Posted by Priyal Khandelwal 9 months, 4 weeks ago

CBSE > Class 10 > Mathematics

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A train travels at a certain average speed for a distance of 63 km and then travels at a distance of 72 km at an average speed of 6km/hr than its original speed.if it takes 3 hours to complete total journey ,what is the original average speed?

Posted by Pritika Limboo 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Bhavya Sharma 10 months ago

Let x be the original average speed of the train in km/hr. We know the total distance traveled is 63 km + 72 km = 135 km. We can express the time taken for each part of the journey using the formula time = distance / speed. Time for the first 63 km: 63 km / x hours Time for the second 72 km: 72 km / (x + 6) hours (since the speed is 6 km/hr faster than the original speed) The total time taken is 3 hours, so we can set up an equation: 63 km / x hours + 72 km / (x + 6) hours = 3 hours

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