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Roohi travels 300 km to her home partly by train and partly by bus. She takes 4 hours if she travels 60 km by rain and the remaining by bus. If she travels 100 km by train and the remaining by bus , she takes 10 minutes longer . Find the speed of the train and the bus separately.

Posted by Shruti Kumari 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 3 months ago

Let the speed of train =x km/h and let the speed of bus =y km/h
According to given conditions,
{tex}\frac{{60}}{x} + \frac{{240}}{y} = 4\,{\text{and}}\,\frac{{100}}{x} + \frac{{200}}{y} = 4 + \frac{{10}}{{60}}{/tex}
Let {tex}\frac{1}{x} = p\,{\text{and}}\,\frac{1}{y} = q{/tex}
Putting this in the above equations, we get
60p +240q =4 ........................... (1)
And100p +200q = {tex}\frac{{25}}{6}{/tex} ............................. (2)
Multiplying (1) by 5 and (2) by 3, we get
300p +1200q = 20 ......................... (3)
300p +600q = {tex}\frac{{25}}{2}{/tex}......................... (4)
Subtracting (4) from (3), we get
600q =20− {tex}\frac{{25}}{2}{/tex} =7.5 ⇒ q = {tex}\frac{{7.5}}{{600}}{/tex}
Putting value of q in (2), we get
100p +200{tex}\left( {\frac{{7.5}}{{600}}} \right) = \frac{{25}}{6}{/tex}
⇒ 100p + 2.5 = {tex}\frac{{25}}{6}{/tex}
⇒ 100p = {tex}\frac{{25}}{6}{/tex} - 2.5
⇒ p = {tex}\frac{{10}}{{600}}{/tex}
But {tex}\frac{1}{x} = p\;{\text{and}}\;\frac{1}{y} = q{/tex}
Therefore, x = {tex}\frac{{600}}{{10}} = 60{/tex} km/h and y = {tex}\frac{{600}}{{7.5}}{/tex} = 80km/h
Therefore, speed of train =60 km/h
And, speed of bus =80 km/h

ANSWER

If the mean of 5 observations x,x+2,x+4,x+6 and x+8 is 11 , find the value of x.

Posted by Prince Raj 6 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Mayank Sharma 6 years, 4 months ago

X=7

Suniksha Bhatia 6 years, 4 months ago

x=9

ANSWER

Important formula

Posted by Sonu Sahu 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Yash Tyagi 6 years, 4 months ago

Of what

ANSWER

A chord of circle radius 10cm make a right angleat centre of the circle find the area of major and minner segment

Posted by Arpit Dubey 6 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Obtain all zeroes of 3x⁴-15x³+13x²+25x-30 if two of it's zero's are √5/3 and -√5/3

Posted by Rani Patil 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 3 months ago

We have the polynomial f(x) = (3x⁴ - 15x³ + 13x² + 25x - 30).
Since {tex}\sqrt { \frac { 5 } { 3 } } \text { and } - \sqrt { \frac { 5 } { 3 } }{/tex} are the zeros of f(x),
i.e., {tex}x=-\sqrt{\frac53}{/tex} and {tex}x=\sqrt{\frac53}{/tex}
i.e., {tex}x+\sqrt{\frac53}=0\;and\;x-\sqrt{\frac53}=0{/tex} so it follows that each
one of {tex}\left( x - \sqrt { \frac { 5 } { 3 } } \right) \operatorname { and } \left( x + \sqrt { \frac { 5 } { 3 } } \right){/tex} is a factor of f(x).so using {tex}\left(a+b\right)\left(a-b\right)=a^2-b^2{/tex}, we get
{tex}\therefore \quad \left( x - \frac { \sqrt { 5 } } { \sqrt { 3 } } \right) \left( x + \frac { \sqrt { 5 } } { \sqrt { 3 } } \right) = 0 \Rightarrow \left( x ^ { 2 } - \frac { 5 } { 3 } \right)= 0 \Rightarrow \frac { \left( 3 x ^ { 2 } - 5 \right) } { 3 }= 0{/tex} is also a factor of f(x).
Consequently, (3x²- 5) is a factor of f{x).
On dividing the polynomial by (3x² - 5), we get

{tex}\therefore{/tex} f(x) = 3x⁴ - 15x³ + 13x² + 25x - 30
= (3x²- 5 )(x²- 5x + 6).
By middle term factorisation. We get,
={tex}\left(3x^2-5\right)\left(x^2-2x-3x+6\right){/tex}
=({tex}\lbrack(\sqrt{3x})^2-\left(\sqrt5\right)^2\rbrack{/tex}{tex}\left[x\left(x-2\right)-3\left(x-2\right)\right]{/tex}
By using {tex}a^2-b^2=\left(a+b\right)\left(a-b\right){/tex}we get,
{tex}= ( \sqrt { 3 } x + \sqrt { 5 } ) ( \sqrt { 3 } x - \sqrt { 5 } ) ( x - 2 ) ( x - 3 ){/tex}
{tex}\therefore{/tex} f(x) = 0 , so either factors can equated to zero to get the roots {tex}\Rightarrow ( \sqrt { 3 } x + \sqrt { 5 } ) = 0 \text { or } ( \sqrt { 3 } x - \sqrt { 5 } ) = 0{/tex}
{tex}\Rightarrow{/tex}(x - 2) = 0 or (x - 3) = 0
{tex}\Rightarrow x = - \sqrt { \frac { 5 } { 3 } } \text { or } x = \sqrt { \frac { 5 } { 3 } }{/tex} or x = 2 or x = 3
Hence, we get all zeros of f(x) are {tex}\sqrt { \frac { 5 } { 3 } } , - \sqrt { \frac { 5 } { 3 } }{/tex}, 2 and 3.

ANSWER

Why the values of trigonometry can't changed???

Posted by Nagappa Talawar 6 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

RAT=42 and CAT=57 then LATE=

Posted by Akash Lal 6 years, 4 months ago

CBSE > Class 10 > Mathematics

3 answers

Akash Lal 6 years, 4 months ago

Can u please upload the solution please

Janu Likki 6 years, 4 months ago

72

Suniksha Bhatia 6 years, 4 months ago

70

ANSWER

Prove that if x and y are odd positive integers, then xsqaure +y square is even but not divisible by 4

Posted by Rithin Smart 6 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Prince Raj 6 years, 4 months ago

Understood

Prince Raj 6 years, 4 months ago

Let the two positive odd integers be x=2m+1 and y=2n+1 where m and n is any positive integet because if a no. is multiplied by 2 it is even no. and then added by 1 then it changes to odd. ATQ x²+y²=(2m+1)²+(2n+1)² =4m²+1+4m+4n²+1+4n =4m²+4n²+4m+4n+2 =4(m²+n²+m+n)+2 Since the sum of square of any positive odd integar is always even And the unit digit of no. is 2 which is not fulfilled the divisibility rule of 4(the sum of the digits of the no.is divisible by 4 then the original no. is also perfectly divisible by 4Hence the square of x+y is even but not divisible by 4

ANSWER

How to multiply equation??

Posted by Vaishali Wani 6 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Vaishali Wani 6 years, 4 months ago

Which?

Janu Likki 6 years, 4 months ago

By using formula

ANSWER

I have doubt in HCF expansion please explain it in some simplest way

Posted by Mansi Sengar 6 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Mansi Sengar 6 years, 4 months ago

I want to know HCF linear combination in a simplest way

Akash Lal 6 years, 4 months ago

For exanple we have to find HCF of 20 and 12 so we first we convert them into its prime factors 20= 2×2×5 12=2×2×6 The highest common factor is 2×2. So its HCF is 4

ANSWER

i want blueprint of cbse exam

Posted by Smriti Mishra 6 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Is there is any option in maths for 10th standard....like_ basic maths or standard maths... Plzz give me some information about this

Posted by Tanya Suryavanshi 6 years, 4 months ago

CBSE > Class 10 > Mathematics

16 answers

Tanya Suryavanshi 6 years, 4 months ago

Thank u from the deep of the heart...and sorry for late answering

Pk . 6 years, 4 months ago

Anyway if you have doubt regardinga ny topic from any chapters . your are heartly welcome?️?️?️?️?️?️

Pk . 6 years, 4 months ago

You have to play with math, think about math, compare the event happening around with math.

Pk . 6 years, 4 months ago

Tanya if you really want to improve your math.then firstly you have to focus on calculation, as fast as your calculation math became as easy as bio( your favourite) ?????

Pk . 6 years, 4 months ago

Strongly welcome tanya

Tanya Suryavanshi 6 years, 4 months ago

If maths is ur veins...so plzz help me to understand it because i need someone who will teach me this..

Tanya Suryavanshi 6 years, 4 months ago

I like bio most...so i wants to chose basic

Pk . 6 years, 4 months ago

Mathematic is in my vain

Pk . 6 years, 4 months ago

Of standard label

Pk . 6 years, 4 months ago

I am going to choose mathematic

Tanya Suryavanshi 6 years, 4 months ago

Ok...so which option do u choose

Pk . 6 years, 4 months ago

Maine kaha na mere sis ne mera doubt clear kar diya

Pk . 6 years, 4 months ago

Tanya i have no doubt at all

Tanya Suryavanshi 6 years, 4 months ago

I'm also confused...so how could i clear ur doubt

Pk . 6 years, 4 months ago

I was also confused about it. But my sweet sis clear my doubt

Pk . 6 years, 4 months ago

Yes tanya the option basic or standard is for us class 10

ANSWER

Which chapter come in final

Posted by Amit Singh 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

?Niharika Sharma ? 6 years, 4 months ago

Whole chapters of all subjects except Social Science

ANSWER

Number of terms

Posted by Motivation Training 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Motivation Training 6 years, 4 months ago

an=a(n-1)d

ANSWER

The first three tremendous an AP 3y-1,3y±5& 5y±1 then find the value of yuan.

Posted by Harsh Choudhary Harsh Choudhary 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 3 months ago

Since {tex}(3y-1), (3y+5)\ and\ (5y+1){/tex} are in AP, we have
{tex}(3y+5)-(3y-1)=(5y+1)-(3y+5){/tex}
{tex} \Rightarrow {/tex} {tex}3y+5-3y+1=5y+1-3y-5{/tex}
{tex} \Rightarrow {/tex} {tex}6=2y-4{/tex}
{tex} \Rightarrow {/tex} 2y=10
{tex} \Rightarrow {/tex} y=5

ANSWER

a1x +b1y +c1=0 a2x +b2y +c1=0

Posted by Saurabh Pathak 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Janu Likki 6 years, 4 months ago

The question itself is wrong a1x +b1y +c1=0 & a2x +b2y +c2 /_____/

ANSWER

What is the formula for acute angle triangle of one side square is equal to?

Posted by Viraj Thekdi 6 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

I want a set of questions of class 11 relations and functions

Posted by Jhuma Moitra 6 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Trigonometry: In a right-angled triangle, the Pythagoras theorem states (perpendicular )2 + ( base )2 = ( hypotenuse )2 Important trigonometric properties: (with P = perpendicular, B = base and H = hypotenuse) SinA = P / H CosA = B / H TanA = P / B CotA = B / P CosecA = H / P SecA = H/B Trigonometric Identities: sin2A + cos2A=1 tan2A +1 = sec2A cot2A + 1= cosec2A Relations between trigonometric identities are given below: Trigonometric Ratios of Complementary Angles are given as follows: sin (90° – A) = cos A cos (90° – A) = sin A tan (90° – A) = cot A cot (90° – A) = tan A sec (90° – A) = cosec A cosec (90° – A) = sec A NCERT Exemplar Problems and Solutions Class 10 Maths: All Chapters Values of Trigonometric Ratios of 0° and 90° are tabulated below:

Posted by Abh!Shek Mourya 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

__Richa Tiwari 6 years, 4 months ago

SinA 0°=0 30°=1/2 45°=1/√2 60°=√3/2 90°=1 we have learn only sin A value and all value learn eaisly cosA value opposite to sin A all value like cosA 0°=1 30°=√3/2 45° = 1/√2 60°= 1/2 90°=0 tanA all ratio find use sinA/cosAformula like tanA0°=sin0°/cos0° 0/1 = 0 so tanA0° is 0 similarly all tanA trignometric ratio find sinA/cosA tanA 30° = sin30°/cos30° 1/2/√3/2 = 1√3 tanA 45°= sin 45°/cos45°=1/√2/1/√2 = 1 tanA 60° = sin60°/cos60°=√3/2/1/2=√3 tanA 90°= sin90°/cos90° =1/0 = not define means soch ke bhar find cosecA trigonometric ratio use 1/sinA like cosecA 0° = 1/sin0°= 1/0= not define cosecA 30°= 1/sin30°=1/1/2=2 cosecA 45°=1/sin45°=1/1√2= √2 cosec60°=1/sin60°= 1/√3/2= 2/√3 cosec90°=1/sin90°= 1/1 = 1 secA opposite to cosecA like secA 0°= cosecA 90° secA 0°=1 secA 30°= cosecA 60° sec 30°= 2/√3 sec45°=cosec45° sec45°= √2 secA 60°= cosecA 30° secA 60°= 2 secA 90°= cosecA 0° sec90°= not define agr app iss mai confuse ho rhe ho to app ko yaad hoga sinA ka opposite cosecA hota h cosA ka opposite secA hota h hum cosA ko 1/secA likh skte h aise hi secA ko 1/cosA likh skte h 1/cosA ki value agr lagyege to hume secA ke all trignometric ratio pta chl jayege ab bacha cotA bhut easy h isme hum cosA/ sin A lga kar kr skte h ya fir 1/tanA lga kr . Isse hum easily yaad kr skte h sare ratio frnds bs hume sinA ke all trigonometric ratio yad hone chaiye baki hum formula lga kr skre kr skte h.????

ANSWER

Sum and products of zeroes of quadratic polynomial are -1/4 & 1/2 respectively. Find the polynomial.

Posted by Joel Emil 6 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

__Richa Tiwari 6 years, 4 months ago

Sum= -1/4 product= 1/2 use formula make quadratic polynomial formula is x² - (sum of zeroes)x +(product of zeroes) putting the value x²- (-1/4)x + (1/2) ans ayega x² + 1/4+1/2. Fir hum multiply krege 4 se jisse divide ki value chali jaye like 4x²+ 4× 1/4 + 4×1/2 to humare pss equation ayegi 4x²+ x +2 ye humara quadratic polynomial banega

Nikhil Raj 6 years, 4 months ago

(a+b)=-1/4 (ab)=1/2 Putting the value of (a+b),(ab). P(x)=x2+( a +b)x-(ab) x2-1/4x-1/2 4x2-1x-2 hence the polynomial is 4x2-1x-2

ANSWER

All the formulas of trignometry

Posted by Saloni Singh 6 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

What is polynomial

Posted by Kailash Yadav 6 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Gaurav Seth 6 years, 4 months ago

A polynomial looks like this:

example of a polynomial
this one has 3 terms

Polynomial comes from <i>poly-</i> (meaning "many") and <i>-nomial</i> (in this case meaning "term") ... so it says "many terms"

A polynomial can have:

constants (like 3, −20, or ½)

variables (like <i>x</i> and <i>y</i>)

exponents (like the 2 in y²), but only 0, 1, 2, 3, ... etc are allowed

Pk . 6 years, 4 months ago

Combination of constant and variable with +,-,×,÷ sign are polynomials

ANSWER

Find the quadratic equation whose zeros are 2 and -6

Posted by Rama S Rama S 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sumit Sharma 6 years, 4 months ago

K(x2-(x+y)x +xy) K[x2-(2+(-6))x +(2*-6)] K[x2-(2-6)x +(-12)] K[x2-(-4)x -12] k[x2+4x-12] put k=1 Hence the polynomial is x2+4x-12

ANSWER

5x-8y+1=0 3x-24/5y+3/5=0. Graphically find whether the following pair of equations has no solution,unique solution or infinely many solution.

Posted by Ragini Vats. 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Ankit ?? Kumar 6 years, 4 months ago

Unique solution...

ANSWER

Ek but a + b + X barabar 1 but a + b + 1 by X

Posted by Anurag Upadhyay 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Janu Likki 6 years, 4 months ago

??????

ANSWER

tan(A-B)=tanA-tanB /1+tanA*tanB

Posted by Amrita Singh 6 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

__Richa Tiwari 6 years, 4 months ago

Isko prof krna h ya value nikalni hai

Ankit ?? Kumar 6 years, 4 months ago

1

ANSWER

Maths chapter 6

Posted by Sandhya Kumari 6 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

from where questions come in board in maths

Posted by Sandeep Kachhap 6 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Ankit ?? Kumar 6 years, 4 months ago

Together with only....

L K 6 years, 4 months ago

R.D sharma , Ncert ,Prabodh

ANSWER

Which term of AP 5,9,13,17----------------is81

Posted by Sheetal Kumari 6 years, 4 months ago

CBSE > Class 10 > Mathematics

5 answers

Ankit ?? Kumar 6 years, 4 months ago

The 20th term of given ap is 81

Sarita Rajput 6 years, 4 months ago

a=5 :d=9-5=4 :an=81 : n=..? an=a+(n-1)d 81=5+(n-1)4 81-5=(n-1)4 76=(n-1)4 76/4= n-1 19 =n-1 19+1 =n n=20

Mayank Sharma 6 years, 4 months ago

a=5, d=9-5=4. an=81. an=a+(n-1)d. 81=5+(n-1)4. 81-5=(n-1)4. 76÷4=n-1. 19=n-1. 19+1=n. 20=n

Aadya Singh 6 years, 4 months ago

a = 5 , d = 9-5=4 , Tn=81 , n= ? AP of n th term is given by, Tn= a+ (n-1)d . Then, Tn = 5+(n-1)4 81= 5+4n-4 81+1=4n n= 82/4 n= 2.5 th term

Bhaskar .T 6 years, 4 months ago

An=a+(n-1)d 81=5+(n-1)4 81=5+4n-4 81=1+4n 81-1=4n 80=4n 80/4=n N=20

ANSWER

Find the zeroes of P(x)=15x×x+31x-24

Posted by Nithesh Nithesh 6 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

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