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Gaurav Seth 6 years, 4 months ago

Each altitude of the equilateral triangle is equal to
Thus,
To find:
Each of its altitudes = ?
Solution:
Given : ABC is an equilateral triangle of side 2a.
In equilateral triangle, △ADB = △ADC
& ∠ADB = ∠ADC (Both 90 degree as AD ⊥ BC)
Thus, △ ADB ≅ △ ADC (By R. H. S. Congruency)
As per CPCT i.e. they are corresponding parts of congruent triangle,
BD = DC
Using Pythagoras theorem,
Hence,
Thus, the altitudes of the given equilateral triangle is equal to
Posted by Abhishek Gupta 6 years, 4 months ago
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Gaurav Seth 6 years, 4 months ago
Answer:
k = 4
Step-by-step explanation:
Our given equation is :
9 x² - 3 k x + k = 0
Comparing with a x² + b x + c = 0 we get :
a = 9
b = - 3 k
c = k .
Whenever we are told that the equation has equal roots then :
b² = 4 a c
This method can be used effectively to calculate the value of k .
( - 3 k )² = 4 ( 9 ) ( k )
⇒ 9 k² = 36 k
⇒ k² = 36 k / 9
⇒ k² = 4 k
⇒ k = 4
The value of k is 4 .

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Honey ???? 6 years, 4 months ago
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