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Ask QuestionPosted by Khushi.....Aadu Yaduvanshi 6 years, 3 months ago
- 10 answers
Rani Mishra ??? 6 years, 3 months ago
Student Lyf ? 6 years, 3 months ago
Student Lyf ? 6 years, 3 months ago
Khushi.....Aadu Yaduvanshi 6 years, 3 months ago
Khushi.....Aadu Yaduvanshi 6 years, 3 months ago
Student Lyf ? 6 years, 3 months ago
Posted by Rajveer Singh 6 years, 3 months ago
- 0 answers
Posted by Mukesh Kumar 6 years, 3 months ago
- 1 answers
Sia ? 6 years, 3 months ago
Let x (in years) be the present age of Jacob's son and y (in years) be the present age of Jacob. 5 years hence, it has relation:
(y + 5) = 3(x + 5)
or, y + 5 = 3x + 15
3x + 15 - y - 5 = 0
or, 3 x - y + 10 = 0 .......(i)
5 years ago, it has relation
(y - 5) = 7(x - 5)
y - 5 = 7x - 35
or, 7x - 35 - y + 5 = 0
or, 7 x - y - 3 0 = 0 ....(ii)
From eqn. (i), y = 3x + 10 ....(iii)
On substituting the value of y in eqn. (ii), we get
7x-(3x + 10) - 30 = 0
7x - 3x - 10 - 30 = 0
or, 4x - 40 = 0
or, 4x = 40
x=10
On substituting x = 10 in eqn. (iii),
{tex}y = 3 \times 10 + 10{/tex}
y = 30 + 10
{tex}\therefore {/tex} y = 40
Hence, the present age of Jacob = 40 years and son's age = 10 years
Posted by Affan Raza 6 years, 3 months ago
- 4 answers
Posted by Deepak Choudhary 6 years, 3 months ago
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Posted by Ayush Yadav 6 years, 3 months ago
- 1 answers
Posted by Anuja S 6 years, 3 months ago
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Posted by Pk . 6 years, 3 months ago
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Posted by Pavi Abhi 6 years, 3 months ago
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Posted by Rishabh Kumar 6 years, 3 months ago
- 4 answers
Prateek Singh 6 years, 3 months ago
Manjeet Mondal 6 years, 3 months ago
Rishabh Kumar 6 years, 3 months ago
Manjeet Mondal 6 years, 3 months ago
Posted by Mohit Agrawal 6 years, 3 months ago
- 1 answers
Posted by Vandana Dwivedi 6 years, 3 months ago
- 3 answers
Amit Kumar Thakur 6 years, 3 months ago
Posted by Abhishek Gupta 6 years, 3 months ago
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Posted by Sujata Tripathi 6 years, 3 months ago
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Posted by Singarm Yashwanth 6 years, 3 months ago
- 1 answers
Posted by ????? ?????? 6 years, 3 months ago
- 1 answers
Yogita Ingle 6 years, 3 months ago
The condition required for a rational number to have a terminating decimal expansion is that when the number is in its simplest form then its denominator should be in the form of 2m x 5n ( where m and n are any whole number ).
Examples :
a.) 10 / 100 = 0.1 ( In this we can find that when the fraction will be broken down into its simplest form then its denominator will be in the form of 2m x 5m )
b.) 9 / 90 = 0.1 ( Well it also have a terminating decimal expansion as when it will be broken down then its denominator will be in the form of 2m x 5m ).
Posted by Khipal Saab 6 years, 3 months ago
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Posted by Ãńkèét Pandey 6 years, 3 months ago
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Posted by Farhan Quazi 6 years, 3 months ago
- 1 answers
Gaurav Seth 6 years, 3 months ago
a(8) = a+7d, where a is the first term and d is the common difference.
a+7d=0
a=-7d
A +7d= 0
a= -7d
As is the 38th term
a₃₈ = a +37d
= -7d + 37d
= 30d
a(38) = a+37d = -7d+37d = 30d
a(18)=a+17d = -7d+17d = 10d
30 d = 3 times 10 d
38th term is triple its 18th term
Posted by Rina Kumari 6 years, 3 months ago
- 1 answers
Yogita Ingle 6 years, 3 months ago
x2 - kx + 9 = ax2 + bx + c
a = 1 . b = -K and c = 9
since the eqn has real roots
∴ b²-4ac=0
⇒ (-k)²-4×1×9=0
⇒k²=√36
⇒k=±6
∵the smallest value of k is required
∴k= -6
Posted by Sachin Bisht Bisht 6 years, 3 months ago
- 0 answers
Posted by Kripa Rajeev 6 years, 3 months ago
- 1 answers
Mohan Meena 6 years, 3 months ago
Posted by Pawan Kumar 6 years, 3 months ago
- 3 answers
Gaurav Seth 6 years, 3 months ago
3x-y=3........1
9x-3y=9..(divided by 3)
3x-y=3......2
3x=3-y
X=3-y/3
sub X in 1
3x-y=3
3(3-y/3)-y=3
3-y-y=3
-2y=3-3
y=0
sub y in 2
3x-y=3
3x-0=3
3x=3
X=1
Posted by Chandan Kumar 6 years, 3 months ago
- 0 answers
Posted by Moumita Bhowmik 6 years, 3 months ago
- 1 answers
Gaurav Seth 6 years, 3 months ago
Thge general nth term of an AP is a + (n -1)d.
From the given conditions,
m (a + (m-1)d) = n( a + (n-1)d)
=> am + m2d - md = an + n2d - nd
=> a(m-n) + (m+n)(m-n)d - (m-n)d = 0
=> (m-n) ( a + (m+n-1)d ) = 0
Rejecting the non-trivial case of m=n, we assume that m and n are different.
=> ( a + (m + n - 1)d ) = 0
The LHS of this equation denotes the (m+n)th term of the AP, which is Zero.
Posted by Swapnil Kumar 6 years, 3 months ago
- 3 answers
Jainandann J 6 years, 3 months ago
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Khushi.....Aadu Yaduvanshi 6 years, 3 months ago
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