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The study of the measurement, relationships, and properties of quantities and sets, using numbers and symbols. Arithmetic, algebra, geometry, and calculus are branches of mathematics.

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Arithmetic. Progressions. Exercise. 5.1. 1. Question

Posted by Pratibha Gite 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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The angry arjun carried some arrows for fighting with bhism with half the arrows, he cut down the arrows thrown by bhism on him and with 6 other he killed the rath driver of bhism. With one arrow each he knocked down respectively the rath, flag and the bow of the bhism. Finally, with one more than 4 times a square root of arrows laid bhism unconcious on an aerogate. Find the no of arrow on which bhism was laid down

Posted by Adit Chaudhary 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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Sia ? 6 years, 3 months ago

Suppose Arjun had x arrows.
Number of arrows used to cut arrows of Bheeshm = x/2
Number of arrows used to kill the rath driver = 6
Number of other arrows used = 3 (required to knock down rath, flag & bow of bheem)
According to the question; Remaining arrows = {tex}4 \sqrt { x } + 1{/tex}
Total no. of arrows Arjuna had = {tex}\quad \frac { x } { 2 } + 6 + 3 + 4 \sqrt { x } + 1{/tex}
{tex}\therefore \quad \frac { x } { 2 } + 6 + 3 + 4 \sqrt { x } + 1 = x{/tex}{tex}\Rightarrow\frac{\displaystyle x}{\displaystyle2}+10+4\sqrt x=x{/tex}
{tex}\Rightarrow \quad x + 20 + 8 \sqrt { x } = 2 x{/tex}
{tex}\Rightarrow \quad x = 20 + 8 \sqrt { x }{/tex}
Putting {tex}\sqrt x=y\Rightarrow y=x^2{/tex} , the above equation becomes
y² = 20 + 8y
{tex}\Rightarrow{/tex} y² - 8y - 20 = 0
{tex}\Rightarrow{/tex} y² -10y +2y -20 = 0
{tex}\Rightarrow{/tex} (y - 10) (y + 2) = 0
{tex}\Rightarrow{/tex} y = 10 or. y = -2
{tex}\Rightarrow{/tex} y = 10 [{tex}\because{/tex} y cannot be negative , as it is square root of x ]
{tex}\Rightarrow{/tex} x = y² {tex}\Rightarrow{/tex} x = 100
Hence, the number of arrows which Arjun had is x = 100.

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Adit Chaudhary 6 years, 3 months ago

Thanku sia

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A gulab jamun, contains sugar syrup up to about 30% of its volume. Find appropriately how much syrup would be found in 45 gulab jamun each shaped like a cylinder with two hemispherical ends with length 5cm and diameter 2.8cm

Posted by Aryaman Ranjan 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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Sia ? 6 years, 3 months ago

Volume of a gulab jamun

{tex} = \frac{2}{3}\pi {(1.4)^3} + \pi {(1.4)^2}(2.2) + \frac{2}{3}\pi {(1.4)^3}{/tex}
{tex} = \frac{4}{3}\pi {(1.4)^3} + \pi {(1.4)^2}(2.2){/tex}
{tex} = \pi {(1.4)^2}\left[ {\frac{{4 \times 1.4}}{3} + 2.2} \right]{/tex}
{tex} = \pi (1.96)\left[ {\frac{{5.6 + 6.6}}{3}} \right]{/tex}
{tex} = \frac{{\pi (1.96)(12.2)}}{3}c{m^3}{/tex}
{tex}\therefore {/tex} Volume of 45 gulab jamuns
{tex} = 45 \times \frac{{\pi (1.96)(12.2)}}{3}{/tex}
{tex} = 15\pi (1.96 \times 12.2){/tex}
{tex} = 15 \times \frac{{22}}{7} \times 1.96 \times 12.2{/tex}
{tex} = 15 \times 22 \times 2.8 \times 12.2{/tex}
= 1127.28 cm³
{tex}\therefore {/tex} Volume of syrup
{tex} = 1127.28 \times \frac{{30}}{{100}}{/tex}
= 338.184 cm³
= 338 cm³ (approx.)

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If 45 is subtracted from twice the greater of two numbers , it results in the other number .if 21 is subtracted from the smaller number,it results in the greater number. Find the number.

Posted by Rishabh Singh 6 years, 3 months ago

CBSE > Class 10 > Mathematics

4 answers

Priyanka Agrawal 6 years, 3 months ago

X=66

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Priyanka Agrawal 6 years, 3 months ago

X=8

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Saraswati Sabat 6 years, 3 months ago

Let the greater number be x and the smallest number be y. ATQ, 2x-45= y.........1 and y -21= x........2 Add up the equations 1 and 2 now. Then it comes x-66= 0 It implies that x=66 and then substitute the value of x in equation 1 such that it will become 132 - 45 = 87

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??????Singh? Pk 6 years, 3 months ago

66 and 87

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If root 2 sin (60 - a) =1 then find the value of a

Posted by Astha Kumari 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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Sin theta divided by (sec theta + tan theta - 1) + cos theta divided by (cosec theta + cot theta minus one) is equal to one

Posted by Jagbir Singh 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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All Formula's of ch -8 Trignometry

Posted by Raj Faujdar 6 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Raj Faujdar 6 years, 3 months ago

Oye btao abhi haveli pe

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Google Account 6 years, 3 months ago

Aao kabhi haveli pe phir batate hai

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Shiw that (a-b)2,(a2+b2)and (a+b)2 are in AP

Posted by Amit Kumar Thakur 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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Sia ? 6 years, 3 months ago

{tex}(a^2+b^2)-(a-b)^2=a^2+b^2-(a^2+b^2-2ab)=a^2+b^2-a^2-b^2+2ab=2ab{/tex}
{tex}(a+b)^2-(a^2+b^2)=(a^2+b^2+2ab)-a^2-b^2=a^2+b^2+2ab-a^2-b^2=2ab{/tex}
Since (a²+b²)-(a-b)²=(a+b)²-(a²+b²),
(a-b)², (a²+b²) and (a+b)² are in AP.

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Sir please send MCQ questions

Posted by Kunal Kumawat 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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Defination of perfect square

Posted by Keshav Kumat 6 years, 3 months ago

CBSE > Class 10 > Mathematics

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Sia ? 6 years, 3 months ago

A perfect square is a number, from a given number system, that can be expressed as the square of a number from the same number system. 25 is a natural number, and since there is another natural number 5, such that 5²= 25, 25 is a perfect square.

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At present Asha 's age is 2 more than the square of her daughter Nisha's age.When Nisha grows to her mother's present age of Asha would be one year less than 10 times the present age of Asha and Nisha

Posted by Priyanshi Singh 6 years, 3 months ago

CBSE > Class 10 > Mathematics