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  • 2 answers

Tanu Meena 6 years, 3 months ago

No prove root 3 as irrational then write similarly to prove root 5 as irrational no need to prove it separately

Sourav Sharma 6 years, 3 months ago

Let √3 is a rational number so we can write in the form of p/q where q is not equal to 0 and p and q are composite number so , √3=p/q S B S (√3)²=(p/q)² 3=p²/q² 3q²=p² P²is divisible by 3 •.•p is disible by 3 P=3m S B S p²=(3m)² P²=9m² (p² =3q²) 3q²=9m² q²=3m² Q²is divisible by 3 •.•q is divisible by 3 Hence our contradiction is wrong therefore √3 is a irrational number Similarly we will prove √5 is irrational number We will add both equation And when we add two irrational number it give irrational no not rational number Hence √3+√5 is irrational number
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Raman Tripathi 6 years, 3 months ago

-25.6
First divide then multiply then add and then subtract
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Silent Girl Happy 6 years, 3 months ago

Let us two positive integer be x and x+1 A.T.Q x^2+(x+1)^2=365 x^2+x^2+2x +1=365 2x^2+2x-364=0 x^2+x-182=0 Let us split middle term X^2+14x-13x-182=0 X(x+14)-13 (x+14)=0 (X+14)(X-13)=0 X =-14 or X=13 Negative root being rejected Hence required number are 13 and 14

Silent Girl Happy 6 years, 3 months ago

13 and 14
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B.M Mishra 6 years, 3 months ago

*gf

B.M Mishra 6 years, 3 months ago

Can u be my gd
  • 1 answers

?​?​?​?​?​?​ ?? 6 years, 3 months ago

If u see this message plz come our timimg
  • 1 answers

Yogita Ingle 6 years, 3 months ago

One diagonal is 16 and another 12 then half of both is 8and6.diagonal of rhombus bisect at 90'

By pythogaurus theorem

8²+6²=h²

64+36=100

Side = 10

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Vishnu Malik 6 years, 3 months ago

Yes you can also prove one of them and write same as sabove

Manoj Das 6 years, 3 months ago

Yes, We can prove

Amritpal Kaur 6 years, 3 months ago

Yes
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Gaurav Seth 6 years, 3 months ago

→ a cos∅ + b sin∅ = c .......(1) .

 

 

Now,

 

→ ( a cos∅ - b sin∅ )² + ( a sin∅ + b cos∅ )² .

 

= a²cos²∅ + b²sin²∅ - 2a sin∅ b cos∅ + a²cos²∅ + b²sin²∅ + 2a sin∅ b cos∅ .

 

= a²sin²∅ + a²cos²∅ + b²cos²∅ + b²sin²∅ .

 

= a²( sin²∅ + cos²∅ ) + b²( cos²∅ + sin²∅ ) .

 

= a² + b² . [ ∵ sin²∅ + cos²∅ = 1 ] .

 

 

Thus, ( a cos∅ - b sin∅ )² + ( a sin∅ + b cos∅ )² = ( a² + b² ) .

 

⇒ c² + ( a sin∅ + b cos∅ )² = ( a² + b² ) .

 

⇒ ( a sin∅ - b cos∅ )² = ( a² + b² - c² ) .

 

⇒ ( a sin∅ - b cos∅ ) = ±√( a² + b² - c² ) .

 

Hence,

 

OR

a cosx - b sinx = c

a2 cos2x + b2 sin2x - 2ab sinx cosx = c2

a2 ( 1 - sin2x) + b( 1 - cos2x) - 2ab sinx cosx = c2

a2 - a2 sin2x + b2 - b2 cos2x - 2ab sinx cosx = c2

-(a2 sin2x + b2 cos2x + 2ab sinx cosx) = -a2 - b2 + c2

(a sinx + b cosx)2 = a2 + b2 - c2

asinx + bcosx = +- root(a2+b2-c2)

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Gaurav Seth 6 years, 3 months ago

Let Rehman"s present age =  years

Rehman's age 3 years ago  =- 3 years

Five years from now  = + 5 years

According to question

                                    

Rejecting negative value 

Hence Rehmans age =7 Yrs

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B.M Mishra 6 years, 3 months ago

2(l+b)
  • 1 answers

Raj Singh 6 years, 3 months ago

If in two triangles, corresponding angles are equal,then their corresponding sides are in the same ratio and hence two triangles are similar
  • 2 answers

Raj Singh 6 years, 3 months ago

But not in the syllabus

Anish Kumar 6 years, 3 months ago

P(E)=n(E)/n(S)
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Anshul Chauhan 6 years, 3 months ago

In vu tk hd dish di crush again after a staffs sucks bcuz Antioch and arch x dunks stfu arch at
√(x^2+y^2)

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