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Neetu Yadav 6 years, 3 months ago
We know that HCF of two numbers can be found by Euclid's Division Algorithm
1445=1190×1+255
1190=255×4+170
255=170×1+85
170=85×2+0
so HCF(1190,1445) is 85
From second last equation
85=255-170
85=255-(1190-255×4)
85=255×5-1190
85=(1445-1190)×5-1190
85=-1190×6+1445×5
85=1190 m+1445n
m=-6
n=5
Hope it helps you.
Posted by Nishu Sharma 6 years, 3 months ago
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