Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Lokesh Choudhary 6 years, 2 months ago
- 1 answers
Posted by नीतेश गोयन 6 years, 2 months ago
- 1 answers
Posted by Jayesh Lokhande 6 years, 2 months ago
- 0 answers
Posted by Baljeet Singh 6 years, 2 months ago
- 7 answers
Anuradha Baskaran 6 years, 2 months ago
Srimoyee Chakraborty 6 years, 2 months ago
Posted by Manish Yadav 6 years, 2 months ago
- 2 answers
Puneet Jaiswal 6 years, 2 months ago
Posted by Konakalla Harideep 6 years, 2 months ago
- 0 answers
Posted by Shubham Upadhyay 6 years, 2 months ago
- 4 answers
Priyanshu Rounwat ?????? 6 years, 2 months ago
Posted by Prajith Purayil 6 years, 2 months ago
- 1 answers
Puneet Jaiswal 6 years, 2 months ago
Posted by Alok Kumar 6 years, 2 months ago
- 0 answers
Posted by Prajith Purayil 6 years, 2 months ago
- 0 answers
Posted by Roma Sikarwar 6 years, 2 months ago
- 0 answers
Posted by Vikas Verma 6 years, 2 months ago
- 2 answers
Posted by Bhavesh Gupta 5 years, 3 months ago
- 1 answers
Posted by Khushi Desai 6 years, 2 months ago
- 4 answers
Posted by Cool ? Baniya ? 6 years, 2 months ago
- 5 answers
Kaustubh Verma 6 years, 2 months ago
Posted by Srimoyee Chakraborty 6 years, 2 months ago
- 1 answers
Yogita Ingle 6 years, 2 months ago
For collinear points, area of triangle formed by them is zero.
Therefore, for points (8, 1), (k, - 4), and (2, - 5), area = 0
1/2 [8 { -4- (-5)} + k{(-5)-(1)} + 2{1 -(-4)}] = 0
8 - 6k + 10 = 0
6k = 18
k = 3
Posted by Rajiv Kum 6 years, 2 months ago
- 1 answers
Sia ? 6 years, 2 months ago
Three digit numbers which leave the remainder 2 when divided by 5 are 102, 107, 112, 117......, 997.
102, 107, 112.... 997 is an A.P
In this A.P
a (first term)= 102
d (Common difference)= 5
I(last term ) = 997
l= an = a + (n – 1) d
997= 102 + (n – 1) {tex}\times{/tex} 5
5 (n – 1) = 997 – 102 = 895
n-1={tex}\frac {885}{5}{/tex}
(n – 1) = 179
n = 179 +1
n = 180
Sum of all three digit numbers which leaves remainder 2 when divided by 5
Sn ={tex}\frac{n}{2}{/tex} [a+l]
Sn= {tex}\frac{180}{2}{/tex} [ 102+ 997]
Sn= 90 {tex}\times{/tex} 1099
Sn= 98910
Sum of all three digit numbers which leaves remainder 2 when divided by 5 is 98910
Posted by Rajiv Kum 6 years, 2 months ago
- 0 answers
Posted by Sudhanshu Choudhary 6 years, 2 months ago
- 1 answers
Rajendra Sahoo 6 years, 2 months ago
Posted by Anil Kumar Choudhary Anil Kumar Choudhary 6 years, 2 months ago
- 0 answers
Posted by Yogendra Gupta 6 years, 2 months ago
- 1 answers
Posted by Seema Sebastian 6 years, 2 months ago
- 1 answers
Kaustubh Verma 6 years, 2 months ago
Posted by ?Suhana ....? 6 years, 2 months ago
- 6 answers
Bharat Saini 6 years, 2 months ago
Mukesh Rawat 6 years, 2 months ago
Posted by ?Suhana ....? 6 years, 2 months ago
- 4 answers
Posted by Kumar Dheeraj 6 years, 2 months ago
- 1 answers
Mukesh Rawat 6 years, 2 months ago
Posted by Dheeraj Malhotra 6 years, 2 months ago
- 1 answers
Posted by Riya Rathore 6 years, 2 months ago
- 1 answers
Virat Chaudhary 6 years, 2 months ago
Posted by Madhu Kumari 6 years, 2 months ago
- 7 answers
Anegha Grace Nelson 6 years, 2 months ago
Snow .. White..? 6 years, 2 months ago

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Cool ? Baniya ? 6 years, 2 months ago
3Thank You