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  • 0 answers
  • 2 answers

Sumit Sharma 6 years, 1 month ago

254545

Vikash Kumar Sinha 6 years, 1 month ago

254545
  • 5 answers

Yashi .... 6 years, 1 month ago

Area of segment of a circle= area of the corresponding sector - area of corresponding triangle

Yashi .... 6 years, 1 month ago

Area of circle= πr^2

Yashi .... 6 years, 1 month ago

Lenght of an arc of sector of angle theta= theta/360×2πr

Yashi .... 6 years, 1 month ago

Area of sector of angle thetha= theta/360×πr^2

Yashi .... 6 years, 1 month ago

Circumference=2πr
  • 0 answers
  • 3 answers

Yashi .... 6 years, 1 month ago

Solution: let 'r' be the radius of spherical ball. ◆Volume raised by shperical ball=6.75cm. ◆Vol. of spherical ball = vol. of water displaced in cylindrical tub. ◆4/3pie r^3= pie r^2h ◆r^3=3/4×12×12×6.75 ◆r^3=729 cm^3◆r=9 cm.

Yashi .... 6 years, 1 month ago

9 cm.

Aadya Singh ? 6 years, 1 month ago

Radius of ball is 9 cm.
  • 2 answers

Sumit Sharma 6 years, 1 month ago

10 yeras sample paper book lele bro wo help karegi jaada usse practice karo jitna ho sake

Abhinav ? 6 years, 1 month ago

Practice kro jitni ho ske..sample papers solve kro..R.D.Sharma..R.S.Aggrawal lagao..
  • 1 answers

Abhinav ? 6 years, 1 month ago

Tension toh h pr acche marks aaye toh life set h..
  • 4 answers

Jattin Bansal 6 years, 1 month ago

It's not so difficult when you think that maths is easy

Anuj Jha 6 years, 1 month ago

No, you have to do ultimate practise

Abhinav ? 6 years, 1 month ago

Maths is my fav. subject..its easy not too much hard

? ... 6 years, 1 month ago

Jisko aati uske liye easy hai but for me maths is very hard
  • 1 answers

Aman Pal 6 years, 1 month ago

Hellooooo plz give me solution
  • 4 answers

Abhinav ? 6 years, 1 month ago

◆Total no of outcome = 6² = 36 ◆Let E be the event of getting a sum of 8 ◆Favorable outcome = { (2,6) , (3,5) , (4,4) , (5,3) , (6,2) } ◆No. of favorable outcome = 5 ◆Probability =No.of favourable outcomes/Total no. of outcomes. ◆P(E)= 5/36.

Anany Mittal 6 years, 1 month ago

Explain ?

Anany Mittal 6 years, 1 month ago

How ?

Aadya Singh ? 6 years, 1 month ago

5/36.
  • 2 answers

Aman Pal 6 years, 1 month ago

9(sec^2A - tan^2A) Sec^2A - tan^2A =1 9 (1) 9

Aadya Singh ? 6 years, 1 month ago

9sec^2 A - 9tan^2 A => 9(sec^2 - tan^2) => 9×1 => 9
  • 1 answers

Kavyansh Rautela 6 years, 1 month ago

Hipparchus
  • 0 answers
  • 2 answers

Hariom Yaduvanshi 6 years, 1 month ago

Gt

Aadya Singh ? 6 years, 1 month ago

The value of m is 2.
  • 1 answers

Nandagopan Nandagopan.G 6 years, 1 month ago

root ofx2+y2
  • 6 answers

Rohit Friend Deepika 6 years, 1 month ago

Hii deepika

? ... 6 years, 1 month ago

I think in standard math 70% questions will come from ncert remaining 30% will come from additional books like rd sharma and rs Agarwal but it will be based on ncert.

Abhinav ? 6 years, 1 month ago

Ha ..aate h .. practice ke lie lagana padega ..ye ni keh skte ki poora ncert ayega..pr base vahi h...

Aarti Rana 6 years, 1 month ago

Are u sure ??

Aarti Rana 6 years, 1 month ago

Mainly isse se aate hai

Manisha Dhibar 6 years, 1 month ago

Obviously,but its based on ncert
  • 5 answers

Sanjana Kumari 6 years, 1 month ago

Thanks to all

Sachin Gurjar 6 years, 1 month ago

NO ,but pattern is almost same as given in sample paper. so don't totally depends on that questions and don't try to fix them in mind without understanding . you should solve your problems first ok
Pattern same hota hai ji waitage of qiestion bhi same hota hai but question same nahi hota?

Prince Raj 6 years, 1 month ago

Haan.. maximum waisa hi hota hai so exam ko humesha cool mind de do..best of luck...??

Deepak Gupta 6 years, 1 month ago

No
  • 4 answers

Shashwat Shukla 6 years, 1 month ago

Ok thanku.....may be aisa hi ho...paper level as sample paper
It is quite difficult bro ...but not too that we are not going to solve.....waise aap 1-2 sample paper bana lo doubt clear ho jayega.....

Yashi .... 6 years, 1 month ago

Yes..it will same as previous year board paper..

Aadya Singh ? 6 years, 1 month ago

Yes..It will same...
  • 4 answers

Aadya Singh ? 6 years, 1 month ago

Sahil....It's solution is too long....u can use google or you tube to understand it...?

Sahil ??? 6 years, 1 month ago

How, i want solution to understand

Shresth Bhardwaj ?? 6 years, 1 month ago

Thank s Buddie

Aadya Singh ? 6 years, 1 month ago

349
  • 4 answers

Sahil ??? 6 years, 1 month ago

TanQ=7/24 and secQ=25/24

Arpita Prasad 6 years, 1 month ago

Since OQ- PQ=1 Let PQ be x,therefore OQ=1+x Apply Pythagoras n find OQ and PQ tanQ=7/24 secQ=25/24

Aadya Singh ? 6 years, 1 month ago

TanQ = 7/24 and secQ = 25/24
7/24 and 25/24
  • 3 answers

Sahil ??? 6 years, 1 month ago

√15 and -√15

Md Amir 6 years, 1 month ago

t^2-15=(t-√15)(t+√15) So zeroes t-√15=0 t=√15 t+√15=0 t=-√15
+√15 and -√15
  • 8 answers

Vijay Verma 6 years, 1 month ago

No it's answer is 70 °

Sahil ??? 6 years, 1 month ago

I think it os 9th class question

Sahil ??? 6 years, 1 month ago

angle BCD=60°

Prince Raj 6 years, 1 month ago

Angle BDC=Angle BAC=50 degree(angle at same segment) Hence,angle BCD+angle CBD+angle BDC=180degree AngleBCD+60degree+50degree=180 degree AngleBCD=(180-110)degree AngleBCD=70degree
U r most welcome bro?

Vijay Verma 6 years, 1 month ago

Thanku
Use relation of angle between same segment
70 degree
  • 1 answers

Chandrakant Mane 6 years, 1 month ago

Next Gurukul Learner's Section WikiK-12 Wiki AssessmentAssessments ForumQ&A Forum Educator's Section MOOCMOOCs Join Experts PanelJoin Experts Panel Next WorldThe Next World Academic Questions & Answers Forum Vijay Sep 7, 2014 Prove that cos A / (1 - tan A) + sin A /(1 - cot A) = sin A + cos A Prove that cos A / (1 - tan A) + sin A /(1 - cot A) = sin A + cos A question_answer Answers(1) person Chandrakant Mane Member since Apr 1, 2014 Sol: cos A / (1 - tan A) + sin A /(1 - cot A) = sin A + cos A LHS = cos A / (1 - tan A) + sin A /(1 - cot A) = cos2 A / (cos A - sin A) + sin2 A / (sin A - cos A) = cos2 A / (cos A - sin A) - sin2 A / (cos A - sin A) = (cos2 A - sin2 A) / (cos A - sin A) = (cos A + sin A) (cos A - sin A) / (cos A - sin A) . = (cos A + sin A). Hence proved.
  • 24 answers

Yashi .... 6 years, 1 month ago

Ok..aadya..?

Yashi .... 6 years, 1 month ago

Aap aye ni the isliye..ab happy h hum..☺️

Aadya Singh ? 6 years, 1 month ago

Ek ekta ka h...vahi pe baat karte h
Hey plzz hamne sorry bola na....aap ?? kyu rahi ho

Yashi .... 6 years, 1 month ago

Ok..kaha pr..

Aadya Singh ? 6 years, 1 month ago

Uper aa jao...

Yashi .... 6 years, 1 month ago

Hum bhi acche h..☺️

Yashi .... 6 years, 1 month ago

Kaha the aap..??

Aadya Singh ? 6 years, 1 month ago

Aur aap..

Aadya Singh ? 6 years, 1 month ago

Mai achhi hu..

Yashi .... 6 years, 1 month ago

Aadyaa..kaisi ho aap..?
Sorry i too miss you a lot....

Aadya Singh ? 6 years, 1 month ago

I'm fine bro..

Aadya Singh ? 6 years, 1 month ago

Hello shreya

Yashi .... 6 years, 1 month ago

Im fine pk ji..I was waiting for u..??
Bro reply bhi kar do....sirf thanks hi karoge....?
Hey how r u...shreya g

Yashi .... 6 years, 1 month ago

Hello pk ji..and aadya..?
Sorry for being late
How r u

Aadya Singh ? 6 years, 1 month ago

Good evening bro...?
Good evening sis
374 cm square

Aadya Singh ? 6 years, 1 month ago

374 cm square.
  • 4 answers

Prinshi Jangir 6 years, 1 month ago

Haaa

Aadya Singh ? 6 years, 1 month ago

Yes...and I know the sample paper is easy.. ?

Suhana.. .. ? #Alone 6 years, 1 month ago

Standard li hh.....but maths lover bilkul nahi hu ... Aur 11th m bhi maths nahi lungi??..

Yashi .... 6 years, 1 month ago

Yes..
  • 2 answers

Vighnesh Suryavanshi 6 years, 1 month ago

x = -b +_ √b^2 + 4ac /2a

Ram ? 6 years, 1 month ago

X equals minus b plus or minus root of b square minus 4ac whole divided by 2a
  • 1 answers

Arukshita Dubey 6 years, 1 month ago

Given: secA = x+1/4x secA ^2 =(x+1/4x) ^2 (Squaring both the sides) tanA^2 + 1 = x^2 + 1/16x^2 + 1/2 tanA^2 = x^2 + 1/16x^2 + 1/2 - 1 tanA^2 = x^2 + 1/16x^2 - 1/2 tanA ^2 = (x - 1/4x) ^2 tanA = x - 1/4x AS PER QUESTION : secA +tanA = x +1/4x + x - 1 /4x secA +tanA = x + x = 2x.... HENCE PROVED

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