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Miss. 1234 6 years, 1 month ago
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Posted by Harjas Singh 6 years, 1 month ago
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Yogita Ingle 6 years, 1 month ago
The dimension of cuboid = 8×4×2;
The total surface area of cuboid = 2(lw+wh+hl);
Here l - length, w- width, h-height;
Total surface are = 2 (8×4+4×2+2×8)
= 2 (32+8+16) = 56×2 = 112 cm2;
This cuboid is cut into cube of equal sides 1cm, Volume of cube = 1cm^3;
Volume of cuboid = 8×4×2 = 64cm3;
Total no. of cubes = 64/1 = 64;
Total surface area of cube = 6;
The ratio of surface are of original cuboid to unit cube = 112/6 = 56/3
Posted by Anubhaw Agarwal 6 years, 1 month ago
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Yogita Ingle 6 years, 1 month ago
2x² + x + 4 = 0
(Divide by 2 through)
x² + 1/2x + 2 = 0
(Subtract 2 from both sides)
x² + 1/2x = -2
(add (b/2)² to both sides)
x² + 1/2x + (1/4)² = -2 + (1/4)²
(Complete the square)
(x + 1/4)² = -31/16
(Square root both sides)
x + 1/4 = ±√(-31/16)
x + 1/4 = ±i√(31/16)
Subtract 1/4 from both sides:
x = i√(31/16) - 1/4 or - i√(31/16) - 1/4
=> Both roots are imaginary numbers
=> There is no real roots
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Posted by Anubhaw Agarwal 6 years, 1 month ago
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Yogita Ingle 6 years, 1 month ago
Let A(a, -11), B(5, b), C(2, 15) and D(1,1) be the given points.
We know that diagonals of parallelogram bisect each other.
Therefore, Coordinates of mid-point of AC = Coordinates of mid-point of BD


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Daman Maan 6 years, 1 month ago
0Thank You