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  • 1 answers

Mridupawan Patiri 1 year, 5 months ago

sin(90°-65°) cos 65°+cos(90°-65°) sin65° cos65°cos65°+sin65°sin65° (sin(90°-a) =cosa) (cos(90-a) =sina)
  • 1 answers

Khwahis Parveen 1 year, 5 months ago

Let 16+17√3 be rational and let it's simplest form be p/q where p and q are integers and q≠0. Then, 16+17√3=p/q 17√3=p/q – 16 √3=p/q–16/17 …(i) Now, p/q is rational →(p/q–16/17) is rational [… difference of rational is rational] √3 is rational … from (i) The contradiction arises by assuming that √3 is rational. Hence, 16+17√3 is irrational.
  • 3 answers

Ajay Kumar Sahu 1 year, 5 months ago

Let Y=0,0+X=14 x=14

Janeesh Kumar 1 year, 5 months ago

X+y=14 Let x=0 0+y=14 Y=0-14 Y=-14

Revati Shegaonkar 1 year, 5 months ago

RRR
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Anmol Kaur 1 year, 5 months ago

Let the 1√6+5 is rational number . 1√6+5=p/q 1√6=p/q-3 1√6=p/q-3q √1=p-3q/2q L.H.S = irrational number R.H.S = rational number L.H.S =|= R.H.s Our supposition is wrong . 1√6+5 is not rational number . 1√6+5 is an irrational number .
  • 3 answers

Khwahis Parveen 1 year, 5 months ago

24÷2×100 →12×100 →1200(answer)

Ladli Kasaudhan 1 year, 5 months ago

1200

Anjali Kumari 1 year, 5 months ago

1200
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Jaat Jaat 1 year, 5 months ago

The first equation: x-1/y =1/3 Do the cross multiplication It become: 3x-3= y 3x-y=3 (first equation) The second equation: x/y+8=1/4 Do the cross multiplication It become: 4x=y+8 4x-y=8 (second equation) Then solve it with elimination or substitution method.
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  • 5 answers

Khwahis Parveen 1 year, 5 months ago

HCF of 12 and 14 12=2×2×3 14=2×7 (In both 2 is common so HCF is 2)

Ladli Kasaudhan 1 year, 5 months ago

2

L.V.A Naidu 1 year, 5 months ago

2

Sakshi Kolekar 1 year, 5 months ago

2

Sachin Rajpoot 1 year, 5 months ago

2
  • 2 answers

Sakshi Kolekar 1 year, 5 months ago

75

Tanishk Chauhan 1 year, 5 months ago

75
  • 1 answers

Sakshi Kolekar 1 year, 5 months ago

Let , √2 is rational number √2=a,b(a,b,are coprime) √2b=a Squaring on both sides (√2b²)=a² 2b²=a²—1 b²=a²/2 'a²'is divisible by '2' 'a' is divisible by '2' a/2=m a=2m Putting in eq 1 2b²=a² 2b²=(2m)² 2b²=4m² b²=4m²/2 b²=2m² b²/2=m² m²= b²/2 'b²'is divisible by '2' 'b'is divisible by '2' But,a and b are coprime Our assumption was wrong Therefore, √2 is irrational number
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