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    • Posted by Apurva Prasad 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
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    • Posted by Maria Nawab 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Utkarsh Mishra 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Mahaswetha Prathvirajan 2 years, 5 months ago

    1/2

    0Thank You

    Bhuvana.A Bhuvana 2 years, 5 months ago

    0.5

    0Thank You

    Bhuvana.A Bhuvana 2 years, 5 months ago

    What's the question sir

    1Thank You

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    • Posted by Jeet Rathi 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
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    • Posted by Khushi Chandekar 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Utkarsh Mishra 2 years, 5 months ago

    Book hai to app pr kya ker raha

    0Thank You

    Madhur Sardiwal 2 years, 5 months ago

    Book mein h dekhle

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    • Posted by Ananya Admane 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Jasnoor Maan 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 4 answers

    Jigyasa Sen 2 years, 5 months ago

    (2+√3)(2-√3) here we can apply the identity of (a+b)(a-b) = a²-b² So, (2+√3)(2-√3) = (2)²-(√3)² Which means , 4-3 =1 [ here (√3)² = √3×√3 = 3 ] Also,1 is a rational no. as it is in the form of p/q. [ 1/1 ] Hence, (2+√3)(2-√3) is a rational number.

    0Thank You

    Niraj Kumar 2 years, 5 months ago

    Rational number

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    Srijoy Roy 2 years, 5 months ago

    Rational number

    1Thank You

    Rudrakshi Thakur 2 years, 5 months ago

    Ans is 1

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    • Posted by Jasnoor Maan 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Muskaan Syed 2 years, 5 months ago

    O. 375

    0Thank You

    Bhuvana.A Bhuvana 2 years, 5 months ago

    2.666

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    • Posted by Fareha Manzar 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Amishi Agarwal 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Muskaan Syed 2 years, 5 months ago

    Let's assume that √2 + √5 is a rational number. √2+√5=a/b Sq. On both sides =2+5+2√10= a^2/b^2 2√10=a^2/b^2 -7 2√10=a^2-7/b^2. √10=a^2-7/2b^2 . It's a fact that √10 is irrational. Hence our assumption that √2+√5 is rational is incorrect..... Hence, √2+√5 is irrational

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    • Posted by Amishi Agarwal 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    B 01 Rojalin Behera 2 years, 5 months ago

    Let assume that √2 is rational So, √2=a/b (a and b are positive co-prime number and b is not equal to 0) i.e. HCF (a,b)=1 b√2=a Squaring both the sides, we get (b√2)^2=a^2 =2b^2=a^2....(i) =b^2=a^2/2 =a^2/2 (if P is a prime number, if P divides a^2 then P divides a) =a/2 So, a=3c for some integer c Putting a=2c in equation (i) 2b^2=(2c)^2 =2b^2=4c^2 =b^2=2c^2 =b^2/2=c^2 =b^2/2 (If P is a prime number, if P divides a^2 then P divides a) =b/2 So, a and b have another prime factor 2 But this contradicts the fact that a and b are co-prime number. This contradiction has arisen due to our incorrect assumption. So, √2 is an irrational number. Hence, proved.

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    • Posted by Cccc Bbb 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sourav Singh 2 years, 5 months ago

    -0.133974596

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    • Posted by Paridhi Saxena 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Sourav Singh 2 years, 5 months ago

    α2+β2=a2b2−2ac

    1Thank You

    Ashish Ashish 2 years, 5 months ago

    Paper to easy hota hai ya hard

    2Thank You

    Ashish Ashish 2 years, 5 months ago

    Sir mai 10th compartment kar rha hu

    2Thank You

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    • Posted by Kaushik Krishna 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Aditya D 2 years, 5 months ago

    LCM of 48 and 60 = 240 bookd

    1Thank You

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    • Posted by Mohammed Ali Rahib 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Prashasti Jk 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    B 01 Rojalin Behera 2 years, 5 months ago

    6=2×3 72=2×2×2×3×3 120=2×2×2×3×5 HCF(6,72,120)=2×3 =6 LCM(6,72,120)=2^3×3^2×5 =8×9×5 =360

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    • Posted by Ananya Tiwari 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Cute Boy 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Sourav Singh 2 years, 5 months ago

    Let x^2 =t then the given equation reduces to t^2+4t+6=0 D=b^2 −4ac D=(4)^2−4(6)(1) D=16−24=−8 D<0 Discriminant is less than zero,so the given equation has imaginary roots.  As all the 3 terms in this polynomial are all positive, this polynomial can never become zero for real values of x. Hence, the given polynomial has no real

    0Thank You

    Parv Jain 2 years, 5 months ago

    Let x^2 =t then the given equation reduces to t^2+4t+6=0 D=b^2 −4ac D=(4)^2−4(6)(1) D=16−24=−8 D<0 Discriminant is less than zero,so the given equation has imaginary roots.  As all the 3 terms in this polynomial are all positive, this polynomial can never become zero for real values of x. Hence, the given polynomial has no real zeros.

    2Thank You

    ANSWER

    • Posted by Kavya Singla 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Prateek Singh 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Shreya Agnihotri 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Yukti - 2 years, 5 months ago

    Prime factors=3²*5²*17

    0Thank You

    Shreya Agnihotri 2 years, 5 months ago

    3×3×5×5×17

    3Thank You

    ANSWER

    • Posted by Pawan Verma 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Pallavi Maravi 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Parv Jain 2 years, 5 months ago

    16ⁿ = (2×2×2×2)ⁿ Prime factorisation of 16ⁿ does not contain the prime factor 5. Therefore, 16ⁿ cannot end with digit 0 for any natural number n

    1Thank You

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    • Posted by Mayank 1234 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Mayank 1234 2 years, 5 months ago

    Hi

    0Thank You

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    • Posted by Piyush Rajpurohit 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Shivam Kumar 2 years, 5 months ago

    Let, assume that ✓17 is rational number. We will prove it by contradiction ✓=p/q, ( where p and q are coprime integer & q does not = 0) Squaring on both sides (✓17)2 = (p/q)2 17= p2/q2 P2 = 17 q2 < first equation Here 17 divide p and 17 divide p2 also P2/17= c , ( where c is any positive integer) P2 = 17c Squaring on both sides P2 = 289c2 < second equ From 1 and 2 17c = 289 c2 c = 17 c2 17 divide c and 17 divide c2 also We can observe that 17 is common factor of p and q This contradict the fact that p and q are coprime So, our assumption that✓17 is rational is wrong Hence, proved that ✓17 is irrational

    2Thank You

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    • Posted by Abuzar Turkei 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Devershika Nayak 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
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    • Posted by Thari S 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
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    • Posted by Bhuvaneshwari Shivapur 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Mahi Singh ❤️‍🔥❤️‍🔥 2 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
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