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Aadya Singh ? 6 years ago

16/81.

ANSWER

If the polynomial p x is divisible by x minus 4 and 2 is a zero of PX then find PX

Posted by Lakshay Raj Garg 6 years ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

√x+4/√x+4 + √x-10/√x-10=5/2 Solve for x

Posted by Kunal Jadhav 6 years ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Area of hexagon

Posted by Prateek Vishwakarma 6 years ago

CBSE > Class 10 > Mathematics

2 answers

Kunal Jadhav 6 years ago

Area of hexagon = 3√3/2 ( side)^2

Lucifer ? Morningstar? 6 years ago

3√3/2(side)²

ANSWER

Find all the zeroes of polynomial 2x^4 - 11x^3 +7x^2 + 13x - 7 , it being given that two of its zeroes are (3+√2) (3-√2).

Posted by Shrija Singh?? 6 years ago

CBSE > Class 10 > Mathematics

2 answers

Shrija Singh?? 6 years ago

How to solve this

Aadya Singh ? 6 years ago

1/2 and -1

4Thank You

ANSWER

Solve for x (2 x/x-5)^2+(2x/x-5) - 24=0

Posted by Ridhima Singh 6 years ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Give me a all formulas of class 10

Posted by Garv Sharma 6 years ago

CBSE > Class 10 > Mathematics

5 answers

Kamalakannan Kandasamy 6 years ago

Sarvagya Porwal 6 years ago

Kitabe khol lo sab milega

Garv Sharma 6 years ago

Give me answers pls

Moulik Goel 6 years ago

Or science

Moulik Goel 6 years ago

Of maths

ANSWER

Is the following statement true or false? Justify your ans . If the zeroes of a quadratic polynomial ax×bx+by+c are both negative then a b and c all have the same sign

Posted by Mahesh Pinjarkar 6 years ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Proove that 2lmda sec lemda upon tan beeta - tan alpha

Posted by Parul Bansal 6 years ago

CBSE > Class 10 > Mathematics

1 answers

Sarvagya Porwal 6 years ago

Q. Sahi se bhejo tabhi to solve kare

ANSWER

Prove that 1 prove that prove that sin theta minus cos theta + 1 upon sin theta + cos theta minus 1 is equals to 1 + sin theta upon cos theta

Posted by Sachin Yadav 6 years ago

CBSE > Class 10 > Mathematics

1 answers

Parul Bansal 6 years ago

It is complete by taking LHS then devide it whole with sin theeta so change the values then it can be done

ANSWER

If the points A(k+1, 2k), B(3k, 2k+3) and C(5k -1, 5k) are collinear, then find the value of k.

Posted by Vinakshi Rana 6 years ago

CBSE > Class 10 > Mathematics

2 answers

Aryan Kothari 6 years ago

Sorry K=2 and K=1/2

Aryan Kothari 6 years ago

Its simple , it is given that all three points are collinear i.e. area of points A,B&C is zero. So by putting formula: Area of points A,B&C =1/2 [X1 (Y2-Y3) + X2 (Y3-Y1) + X3 (Y1-Y2)] Where , Area=0, X1=(k+1), X2=3k, X3=(5k-1), Y1=2k, Y2=(2k+3), and Y3=5k. We get X=2 and X=1/2..

ANSWER

what is a value of 1 PERCENT

Posted by Samsung G 6 years ago

CBSE > Class 10 > Mathematics

1 answers

Alok Raj 6 years ago

1/100

ANSWER

The LCM of smallest two digit number composite number and smallest composite number is

Posted by Vishal Singh 6 years ago

CBSE > Class 10 > Mathematics

2 answers

Gaurav Seth 6 years ago

First, we have to know what is a composite number. A composite number is a number that has a minimum of two factors. Or we can say a whole number that can make by multiplying other whole numbers.

So, the smallest composite number is 4, and the smallest 2 digits composite number is 10.

4 is a composite number cause it has 2 factors. One is (1 *4) and, another one is (2*2)

10 is also a composite number because it also has 2 factors. One is (1 *10) and, another one is (5*2)

LCM of these two composite numbers ( 4 and 10 ) is 20.

Aadya Singh ? 6 years ago