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  • 1 answers

Aadya Singh ? 6 years, 3 months ago

(43 - 24√3)/11
  • 5 answers

Royal ?? Chundawat 6 years, 3 months ago

It's 73 Very simple...

Arpit Maurya 6 years, 3 months ago

73

......D I Y A..... 6 years, 4 months ago

73

Himanshu Verma 6 years, 4 months ago

73

Aadya Singh ? 6 years, 4 months ago

73
  • 0 answers
  • 3 answers

Shreya G 6 years, 4 months ago

I know but sometimes the question will be to find TSA but they use CSA.....

Shashwat Shukla 6 years, 4 months ago

When there is need

Shreya G 6 years, 4 months ago

I mean when to use HCF and LCM
  • 1 answers

Manvi Sirohi 6 years, 4 months ago

Practice more and more of different questions including NCERT and other books
  • 2 answers

Aadya Singh ? 6 years, 4 months ago

Hence , option (b) is correct.

Aadya Singh ? 6 years, 4 months ago

HCF of 65 and 117 is 13. So, ATQ => 65m - 117 = 13 => m = 130/65 => m = 2.
  • 3 answers

Utsav Goyal 6 years, 4 months ago

Sin

Aadit S Nair S Nair 6 years, 4 months ago

Sin=os/h Cos=as/h Tan=os/as Cosec=1/sin Sec=1/cos Cot=1/tan

Aadit S Nair S Nair 6 years, 4 months ago

Sin
  • 1 answers

?? Thakur 06 ???? 6 years, 4 months ago

Firstly don't take tension belive yourself and on your books study daily science ,sst and maths . revise every thing which you have studied in a week you must focus on ncert questions. Clear your concept. You can do anything and everything
  • 3 answers

Aadya Singh ? 6 years, 4 months ago

XY = 6cm.

Aayush Ghdoliya 6 years, 4 months ago

This Ans is write or not

Aayush Ghdoliya 6 years, 4 months ago

Ans is 6 cm In triangle XYZ , DE parallel to YZ therefore BY BPT XD/DY=YE/EZ 2.4/DY=3.2/4.8 BY CROSS MULTIPLICATION 2.4×4.8=3.2×DY 11.52/3.2=DY DY=3.6 cm Now we have to find XY So XY = XD+DY XY=2.4 cm+3.6 cm XY=6.0 Cm
  • 2 answers

Aadya Singh ? 6 years, 4 months ago

16:81

Aadya Singh ? 6 years, 4 months ago

16/81.
  • 2 answers

Kunal Jadhav 6 years, 4 months ago

Area of hexagon = 3√3/2 ( side)^2

Lucifer ? Morningstar? 6 years, 4 months ago

3√3/2(side)²
  • 0 answers
  • 5 answers

Kamalakannan Kandasamy 6 years, 4 months ago

Av

Sarvagya Porwal 6 years, 4 months ago

Kitabe khol lo sab milega

Garv Sharma 6 years, 4 months ago

Give me answers pls

Moulik Goel 6 years, 4 months ago

Or science

Moulik Goel 6 years, 4 months ago

Of maths
  • 1 answers

Sarvagya Porwal 6 years, 4 months ago

Q. Sahi se bhejo tabhi to solve kare
  • 1 answers

Parul Bansal 6 years, 4 months ago

It is complete by taking LHS then devide it whole with sin theeta so change the values then it can be done
  • 2 answers

Aryan Kothari 6 years, 4 months ago

Sorry K=2 and K=1/2

Aryan Kothari 6 years, 4 months ago

Its simple , it is given that all three points are collinear i.e. area of points A,B&C is zero. So by putting formula: Area of points A,B&C =1/2 [X1 (Y2-Y3) + X2 (Y3-Y1) + X3 (Y1-Y2)] Where , Area=0, X1=(k+1), X2=3k, X3=(5k-1), Y1=2k, Y2=(2k+3), and Y3=5k. We get X=2 and X=1/2..
  • 1 answers

Alok Raj 6 years, 4 months ago

1/100
  • 2 answers

Gaurav Seth 6 years, 4 months ago

First, we have to know what is a composite number. A composite number is a number that has a minimum of two factors. Or we can say a whole number that can make by multiplying other whole numbers.

So, the smallest composite number is 4, and the smallest 2 digits composite number is 10.

4 is a composite number cause it has 2 factors. One is (1 *4) and, another one is (2*2)

10 is also a composite number because it also has 2 factors. One is (1 *10) and, another one is (5*2)

LCM of these two composite numbers ( 4 and 10 ) is 20.

Aadya Singh ? 6 years, 4 months ago

20
  • 0 answers

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